如何从控制器内确定给定请求的IP地址?例如(在快递中):
app.post('/get/ip/address', function (req, res) {
// need access to IP address here
})
如何从控制器内确定给定请求的IP地址?例如(在快递中):
app.post('/get/ip/address', function (req, res) {
// need access to IP address here
})
当前回答
获取ip地址有两种方式:
让IP = req.ip 让ip = req.connection.remoteAddress;
但上述方法存在一个问题。
如果你在Nginx或任何代理程序后面运行你的应用程序,每个IP地址将是127.0.0.1。
因此,获取user的ip地址的最佳方案是:-
let ip = req.header('x-forwarded-for') || req.connection.remoteAddress;
其他回答
这里有很多很棒的观点,但没有一个是全面的,所以这里是我最终使用的:
function getIP(req) {
// req.connection is deprecated
const conRemoteAddress = req.connection?.remoteAddress
// req.socket is said to replace req.connection
const sockRemoteAddress = req.socket?.remoteAddress
// some platforms use x-real-ip
const xRealIP = req.headers['x-real-ip']
// most proxies use x-forwarded-for
const xForwardedForIP = (() => {
const xForwardedFor = req.headers['x-forwarded-for']
if (xForwardedFor) {
// The x-forwarded-for header can contain a comma-separated list of
// IP's. Further, some are comma separated with spaces, so whitespace is trimmed.
const ips = xForwardedFor.split(',').map(ip => ip.trim())
return ips[0]
}
})()
// prefer x-forwarded-for and fallback to the others
return xForwardedForIP || xRealIP || sockRemoteAddress || conRemoteAddress
}
警告:
不要盲目地将其用于重要的速率限制:
let ip = request.headers['x-forwarded-for'].split(',')[0];
这很容易被欺骗:
curl --header "X-Forwarded-For: 1.2.3.4" "https://example.com"
在这种情况下,用户的真实IP地址将是:
let ip = request.headers['x-forwarded-for'].split(',')[1];
我很惊讶,没有其他答案提到这一点。
也有同样的问题…im也是新的javascript,但我解决了这个与req.connection.remoteAddress;这给了我IP地址(但在ipv6格式::ffff.192.168.0.101),然后.slice删除前7位数字。
var ip = req.connection.remoteAddress;
if (ip.length < 15)
{
ip = ip;
}
else
{
var nyIP = ip.slice(7);
ip = nyIP;
}
如果你正在使用Graphql-Yoga,你可以使用以下函数:
const getRequestIpAddress = (request) => { const requestIpAddress = request.request。headers['X-Forwarded-For'] || request.request.connection.remoteAddress . headers['X-Forwarded-For' if (!requestIpAddress)返回null const ipv4 = new RegExp(“(?:(?:25(0 - 5)| 2[0 - 9][0 - 4]|[01]?[0 - 9][0 - 9]?)\){3}(?:25(0 - 5)| 2[0 - 9][0 - 4]|[01]?[0 - 9][0 - 9]?)”) const [ipAddress] = requesttipaddress .match(ipv4) 返回ipAddress }
Var ipaddress = (req。标题(“x-forwarded-for”)| | req.connection.remoteAddress | | req.socket.remoteAddress | | req.connection.socket.remoteAddress) .split (", ") [0];