如何从控制器内确定给定请求的IP地址?例如(在快递中):

app.post('/get/ip/address', function (req, res) {
    // need access to IP address here
})

当前回答

获取ip地址有两种方式:

让IP = req.ip 让ip = req.connection.remoteAddress;

但上述方法存在一个问题。

如果你在Nginx或任何代理程序后面运行你的应用程序,每个IP地址将是127.0.0.1。

因此,获取user的ip地址的最佳方案是:-

let ip = req.header('x-forwarded-for') || req.connection.remoteAddress;

其他回答

这里有很多很棒的观点,但没有一个是全面的,所以这里是我最终使用的:

function getIP(req) {
  // req.connection is deprecated
  const conRemoteAddress = req.connection?.remoteAddress
  // req.socket is said to replace req.connection
  const sockRemoteAddress = req.socket?.remoteAddress
  // some platforms use x-real-ip
  const xRealIP = req.headers['x-real-ip']
  // most proxies use x-forwarded-for
  const xForwardedForIP = (() => {
    const xForwardedFor = req.headers['x-forwarded-for']
    if (xForwardedFor) {
      // The x-forwarded-for header can contain a comma-separated list of
      // IP's. Further, some are comma separated with spaces, so whitespace is trimmed.
      const ips = xForwardedFor.split(',').map(ip => ip.trim())
      return ips[0]
    }
  })()
  // prefer x-forwarded-for and fallback to the others
  return xForwardedForIP || xRealIP || sockRemoteAddress || conRemoteAddress
}

警告:

不要盲目地将其用于重要的速率限制:

let ip = request.headers['x-forwarded-for'].split(',')[0];

这很容易被欺骗:

curl --header "X-Forwarded-For: 1.2.3.4" "https://example.com"

在这种情况下,用户的真实IP地址将是:

let ip = request.headers['x-forwarded-for'].split(',')[1];

我很惊讶,没有其他答案提到这一点。

也有同样的问题…im也是新的javascript,但我解决了这个与req.connection.remoteAddress;这给了我IP地址(但在ipv6格式::ffff.192.168.0.101),然后.slice删除前7位数字。

var ip = req.connection.remoteAddress;

if (ip.length < 15) 
{   
   ip = ip;
}
else
{
   var nyIP = ip.slice(7);
   ip = nyIP;
}

如果你正在使用Graphql-Yoga,你可以使用以下函数:

const getRequestIpAddress = (request) => { const requestIpAddress = request.request。headers['X-Forwarded-For'] || request.request.connection.remoteAddress . headers['X-Forwarded-For' if (!requestIpAddress)返回null const ipv4 = new RegExp(“(?:(?:25(0 - 5)| 2[0 - 9][0 - 4]|[01]?[0 - 9][0 - 9]?)\){3}(?:25(0 - 5)| 2[0 - 9][0 - 4]|[01]?[0 - 9][0 - 9]?)”) const [ipAddress] = requesttipaddress .match(ipv4) 返回ipAddress }

Var ipaddress = (req。标题(“x-forwarded-for”)| | req.connection.remoteAddress | | req.socket.remoteAddress | | req.connection.socket.remoteAddress) .split (", ") [0];