如何从控制器内确定给定请求的IP地址?例如(在快递中):
app.post('/get/ip/address', function (req, res) {
// need access to IP address here
})
如何从控制器内确定给定请求的IP地址?例如(在快递中):
app.post('/get/ip/address', function (req, res) {
// need access to IP address here
})
当前回答
请求。headers['x-forwarded-for'] || request.connection.remoteAddress . headers['x-forwarded-for'
如果有x-forward -for报头,则使用它,否则使用. remoteaddress属性。
The x-forwarded-for header is added to requests that pass through load balancers (or other types of proxy) set up for HTTP or HTTPS (it's also possible to add this header to requests when balancing at a TCP level using proxy protocol). This is because the request.connection.remoteAddress the property will contain the private IP address of the load balancer rather than the public IP address of the client. By using an OR statement, in the order above, you check for the existence of an x-forwarded-for header and use it if it exists otherwise use the request.connection.remoteAddress.
其他回答
在Typescript中使用ValidatorJS。下面是NodeJS中间件:
// Extract Client IP Address
app.use((req, res, next) => {
let ipAddress = (req.headers['x-forwarded-for'] as string || '').split(',')[0]
if (!validator.isIP(ipAddress))
ipAddress = req.socket.remoteAddress?.toString().split(':').pop() || ''
if (!validator.isIP(ipAddress))
return res.status(400).json({errorMessage: 'Bad Request'})
req.headers['x-forwarded-for'] = ipAddress
next()
})
在这里,我假设所有请求都应该有一个有效的IP地址,因此如果没有找到有效的IP地址,则返回一个代码为400的响应。
函数getCallerIP(请求){ Var IP = request。标题(“x-forwarded-for”)| | request.connection.remoteAddress | | request.socket.remoteAddress | | request.connection.socket.remoteAddress; IP = IP .split(',')[0]; IP = IP .split(':').slice(-1);//如果IP以“::ffff:146.xxx.xxx.xxx”格式返回 返回的ip; }
首先,在项目中安装request-ip
import requestIp from 'request-ip';
const clientIp = requestIp.getClientIp(req);
console.log(clientIp)
如果使用localhost,结果可能是::1,因为::1是真实的IP地址,是localhost的IPV6表示法。
在节点10.14中,在nginx后面,你可以通过nginx头请求它来检索ip,就像这样:
proxy_set_header X-Real-IP $remote_addr;
然后在你的app.js中:
app.set('trust proxy', true);
在那之后,你想让它出现的地方:
var userIp = req.header('X-Real-IP') || req.connection.remoteAddress;
我使用这个ipv4格式
req.connection.remoteAddress.split(':').slice(-1)[0]