如何从控制器内确定给定请求的IP地址?例如(在快递中):

app.post('/get/ip/address', function (req, res) {
    // need access to IP address here
})

当前回答

首先,在项目中安装request-ip

import requestIp from 'request-ip';
const clientIp = requestIp.getClientIp(req); 
console.log(clientIp)

如果使用localhost,结果可能是::1,因为::1是真实的IP地址,是localhost的IPV6表示法。

其他回答

请求。headers['x-forwarded-for'] || request.connection.remoteAddress . headers['x-forwarded-for'

如果有x-forward -for报头,则使用它,否则使用. remoteaddress属性。

The x-forwarded-for header is added to requests that pass through load balancers (or other types of proxy) set up for HTTP or HTTPS (it's also possible to add this header to requests when balancing at a TCP level using proxy protocol). This is because the request.connection.remoteAddress the property will contain the private IP address of the load balancer rather than the public IP address of the client. By using an OR statement, in the order above, you check for the existence of an x-forwarded-for header and use it if it exists otherwise use the request.connection.remoteAddress.

如果您使用的是快速版3。X或更大,您可以使用信任代理设置(http://expressjs.com/api.html#trust.proxy.options.table),它将遍历X -forward -for报头中的地址链,并将链中尚未配置为受信任代理的最新IP放入req对象的IP属性中。

如果你正在使用Graphql-Yoga,你可以使用以下函数:

const getRequestIpAddress = (request) => { const requestIpAddress = request.request。headers['X-Forwarded-For'] || request.request.connection.remoteAddress . headers['X-Forwarded-For' if (!requestIpAddress)返回null const ipv4 = new RegExp(“(?:(?:25(0 - 5)| 2[0 - 9][0 - 4]|[01]?[0 - 9][0 - 9]?)\){3}(?:25(0 - 5)| 2[0 - 9][0 - 4]|[01]?[0 - 9][0 - 9]?)”) const [ipAddress] = requesttipaddress .match(ipv4) 返回ipAddress }

    const express = require('express')
    const app = express()
    const port = 3000

    app.get('/', (req, res) => {
    var ip = req.ip
    console.log(ip);
    res.send('Hello World!')
    })

   // Run as nodejs ip.js
    app.listen(port, () => {
    console.log(`Example app listening at http://localhost:${port}`)
    })

在Typescript中使用ValidatorJS。下面是NodeJS中间件:

// Extract Client IP Address
app.use((req, res, next) => {
    let ipAddress = (req.headers['x-forwarded-for'] as string || '').split(',')[0]
    if (!validator.isIP(ipAddress))
        ipAddress = req.socket.remoteAddress?.toString().split(':').pop() || ''
    if (!validator.isIP(ipAddress))
        return res.status(400).json({errorMessage: 'Bad Request'})

    req.headers['x-forwarded-for'] = ipAddress
    next()
})

在这里,我假设所有请求都应该有一个有效的IP地址,因此如果没有找到有效的IP地址,则返回一个代码为400的响应。