如何从控制器内确定给定请求的IP地址?例如(在快递中):

app.post('/get/ip/address', function (req, res) {
    // need access to IP address here
})

当前回答

你可以像这样快速获取用户Ip

req.ip

在这个例子中,我们获取了用户的Ip,然后用req.ip把它发回给用户

app.get('/', (req, res)=> { 
    res.send({ ip : req.ip})
    
})

其他回答

要求的事情。连接已弃用node@12.12.0。使用req.connection.remoteAddress获取客户端IP可能仍然有效,但不建议使用。

幸运的是,req.socket.remoteAddress自node@0.5.10以来一直存在,是一个完美的替代品:

远程IP地址的字符串表示形式。例如,'74.125.127.100'或'2001:4860:a005::68'。如果套接字被销毁(例如,如果客户端断开连接),值可能是未定义的。

以下函数涵盖了所有的情况,将会有所帮助

var ip;
if (req.headers['x-forwarded-for']) {
    ip = req.headers['x-forwarded-for'].split(",")[0];
} else if (req.connection && req.connection.remoteAddress) {
    ip = req.connection.remoteAddress;
} else {
    ip = req.ip;
}console.log("client IP is *********************" + ip);

也有同样的问题…im也是新的javascript,但我解决了这个与req.connection.remoteAddress;这给了我IP地址(但在ipv6格式::ffff.192.168.0.101),然后.slice删除前7位数字。

var ip = req.connection.remoteAddress;

if (ip.length < 15) 
{   
   ip = ip;
}
else
{
   var nyIP = ip.slice(7);
   ip = nyIP;
}

首先,在项目中安装request-ip

import requestIp from 'request-ip';
const clientIp = requestIp.getClientIp(req); 
console.log(clientIp)

如果使用localhost,结果可能是::1,因为::1是真实的IP地址,是localhost的IPV6表示法。

请求。headers['x-forwarded-for'] || request.connection.remoteAddress . headers['x-forwarded-for'

如果有x-forward -for报头,则使用它,否则使用. remoteaddress属性。

The x-forwarded-for header is added to requests that pass through load balancers (or other types of proxy) set up for HTTP or HTTPS (it's also possible to add this header to requests when balancing at a TCP level using proxy protocol). This is because the request.connection.remoteAddress the property will contain the private IP address of the load balancer rather than the public IP address of the client. By using an OR statement, in the order above, you check for the existence of an x-forwarded-for header and use it if it exists otherwise use the request.connection.remoteAddress.