如何从控制器内确定给定请求的IP地址?例如(在快递中):

app.post('/get/ip/address', function (req, res) {
    // need access to IP address here
})

当前回答

    const express = require('express')
    const app = express()
    const port = 3000

    app.get('/', (req, res) => {
    var ip = req.ip
    console.log(ip);
    res.send('Hello World!')
    })

   // Run as nodejs ip.js
    app.listen(port, () => {
    console.log(`Example app listening at http://localhost:${port}`)
    })

其他回答

我试过了,但都没用,

console.log(clientIp);
console.log(req.ip);

console.log(req.headers['x-forwarded-for']);
console.log(req.connection.remoteAddress);
console.log(req.socket.remoteAddress);
console.log(req.connection.socket.remoteAddress.split(",")[0]);

当在Nginx代理后运行Express应用程序时,你必须将应用程序变量信任代理设置为true。Express提供了其他一些信任代理值,您可以在它们的文档中查看这些值,但以下步骤对我来说是有效的。

app.set('trust proxy', true)

App.set('信任代理',true);

在Nginx中添加proxy_set_header X-Forwarded-For $remote_addr 服务器块的配置。

位置/ { proxy_pass http://localhost: 3001; proxy_http_version 1.1; 升级$http_upgrade; 连接“升级”; 主机$ Host; proxy_set_header X-Forwarded-For $remote_addr;#这一行 proxy_cache_bypass http_upgrade美元; }

对象中读取客户端的IP地址 req.header('x-forwarded-for')或req.connection.remoteAddress;ipfilter的完整代码

module.exports = function(req, res, next) { let enable = true; // true/false let blacklist = ['x.x.x.x']; let whitelist = ['x.x.x.x']; let clientIp = req.header('x-forwarded-for') || req.connection.remoteAddress; if (!clientIp) { return res.json('Error'); } if (enable && paths.some((path) => (path === req.originalUrl))) { let blacklist = blacklist || []; if (blacklist.some((ip) => clientIp.match(ip) !== null)) { return res.json({ status: 401, error: 'Your IP is black-listed !'}); } let whitelist = whitelist || []; if (whitelist.length === 0 || whitelist.some((ip) => clientIp.match(ip) !== null)) { next(); return; } else { return res.json({ status: 401, error: 'Your IP is not listed !'}); } } next(); };

你可以保持DRY,只使用支持IPv4和IPv6的node-ipware。

安装:

npm install ipware

在你的app.js或中间件中:

var getIP = require('ipware')().get_ip;
app.use(function(req, res, next) {
    var ipInfo = getIP(req);
    console.log(ipInfo);
    // { clientIp: '127.0.0.1', clientIpRoutable: false }
    next();
});

它将尽最大努力获取用户的IP地址或返回127.0.0.1,以表明它无法确定用户的IP地址。查看README文件中的高级选项。

函数getCallerIP(请求){ Var IP = request。标题(“x-forwarded-for”)| | request.connection.remoteAddress | | request.socket.remoteAddress | | request.connection.socket.remoteAddress; IP = IP .split(',')[0]; IP = IP .split(':').slice(-1);//如果IP以“::ffff:146.xxx.xxx.xxx”格式返回 返回的ip; }

如果您使用的是快速版3。X或更大,您可以使用信任代理设置(http://expressjs.com/api.html#trust.proxy.options.table),它将遍历X -forward -for报头中的地址链,并将链中尚未配置为受信任代理的最新IP放入req对象的IP属性中。

以下函数涵盖了所有的情况,将会有所帮助

var ip;
if (req.headers['x-forwarded-for']) {
    ip = req.headers['x-forwarded-for'].split(",")[0];
} else if (req.connection && req.connection.remoteAddress) {
    ip = req.connection.remoteAddress;
} else {
    ip = req.ip;
}console.log("client IP is *********************" + ip);