如何从控制器内确定给定请求的IP地址?例如(在快递中):
app.post('/get/ip/address', function (req, res) {
// need access to IP address here
})
如何从控制器内确定给定请求的IP地址?例如(在快递中):
app.post('/get/ip/address', function (req, res) {
// need access to IP address here
})
当前回答
以下函数涵盖了所有的情况,将会有所帮助
var ip;
if (req.headers['x-forwarded-for']) {
ip = req.headers['x-forwarded-for'].split(",")[0];
} else if (req.connection && req.connection.remoteAddress) {
ip = req.connection.remoteAddress;
} else {
ip = req.ip;
}console.log("client IP is *********************" + ip);
其他回答
这里有很多很棒的观点,但没有一个是全面的,所以这里是我最终使用的:
function getIP(req) {
// req.connection is deprecated
const conRemoteAddress = req.connection?.remoteAddress
// req.socket is said to replace req.connection
const sockRemoteAddress = req.socket?.remoteAddress
// some platforms use x-real-ip
const xRealIP = req.headers['x-real-ip']
// most proxies use x-forwarded-for
const xForwardedForIP = (() => {
const xForwardedFor = req.headers['x-forwarded-for']
if (xForwardedFor) {
// The x-forwarded-for header can contain a comma-separated list of
// IP's. Further, some are comma separated with spaces, so whitespace is trimmed.
const ips = xForwardedFor.split(',').map(ip => ip.trim())
return ips[0]
}
})()
// prefer x-forwarded-for and fallback to the others
return xForwardedForIP || xRealIP || sockRemoteAddress || conRemoteAddress
}
对于我使用kubernetes ingress (NGINX):
req.headers['x-original-forwarded-for']
在Node.js中非常有效
如果你有多个ip,这对我来说是可行的:
Var ipaddress = (req。标题(“x-forwarded-for”)| | req.connection.remoteAddress | | req.socket.remoteAddress | | req.connection.socket.remoteAddress) .split (", ") [0];
在你的请求对象中有一个属性叫socket,它是一个网络。套接字对象。净。套接字对象有一个属性remoteAddress,因此你应该能够通过这个调用得到IP:
request.socket.remoteAddress
(如果您的节点版本低于13,请使用已弃用的request.connection.remoteAddress)
EDIT
正如@juand在评论中指出的那样,如果服务器位于代理之后,获得远程IP的正确方法是request.headers['x-forwarded-for']
编辑2
在Node.js中使用express时:
如果你设置了app.set('信任代理',true),请请求。ip将返回真实ip地址,即使在代理。查看文档了解更多信息
警告:
不要盲目地将其用于重要的速率限制:
let ip = request.headers['x-forwarded-for'].split(',')[0];
这很容易被欺骗:
curl --header "X-Forwarded-For: 1.2.3.4" "https://example.com"
在这种情况下,用户的真实IP地址将是:
let ip = request.headers['x-forwarded-for'].split(',')[1];
我很惊讶,没有其他答案提到这一点。