我得到了一个AsyncTask,应该检查对主机名的网络访问。但是doInBackground()永远不会超时。有人知道吗?

public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {

    private Main main;

    public HostAvailabilityTask(Main main) {
        this.main = main;
    }

    protected Boolean doInBackground(String... params) {
        Main.Log("doInBackground() isHostAvailable():"+params[0]);

        try {
            return InetAddress.getByName(params[0]).isReachable(30); 
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return false;       
    }

    protected void onPostExecute(Boolean... result) {
        Main.Log("onPostExecute()");

        if(result[0] == false) {
            main.setContentView(R.layout.splash);
            return;
        }

        main.continueAfterHostCheck();
    }   
}

当前回答

我已经应用了@Levit提供的解决方案,并创建了不会调用额外Http请求的函数。

它将解决无法解析主机的错误

public static boolean isInternetAvailable(Context context) {
    ConnectivityManager cm = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    if (activeNetwork == null) return false;

    switch (activeNetwork.getType()) {
        case ConnectivityManager.TYPE_WIFI:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        case ConnectivityManager.TYPE_MOBILE:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        default:
            return false;
    }
    return false;
}

private static boolean isInternet() {

    Runtime runtime = Runtime.getRuntime();
    try {
        Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
        int exitValue = ipProcess.waitFor();
        Debug.i(exitValue + "");
        return (exitValue == 0);
    } catch (IOException | InterruptedException e) {
        e.printStackTrace();
    }

    return false;
}

现在叫它,

if (!isInternetAvailable(getActivity())) {
     //Show message
} else {
     //Perfoem the api request
}

其他回答

这个线程中的大多数答案只检查是否有可用的连接,但不检查该连接是否工作,其他答案不是设备范围,我的解决方案应该在每个设备上工作。

你可以在启动应用程序之前在你的主要活动中删除我的代码,它会快速确定是否有实际的互联网连接,如果有对话框将立即删除,应用程序将被启动,如果没有警报会弹出说应用程序需要互联网连接才能工作。

final AlertDialog alertDialog = new AlertDialog.Builder(this).create();
        alertDialog.setTitle("Checking Connection");
        alertDialog.setMessage("Checking...");
        alertDialog.show();
        new CountDownTimer(5000, 1000) {
            @Override
            public void onTick(long millisUntilFinished) {

                new Thread(new Runnable() {
                    public void run() {
                        try {
                            URL url = new URL("http://web.mit.edu/");
                            HttpURLConnection connection = (HttpURLConnection) url.openConnection();
                            connection.setRequestMethod("GET");
                            connection.setConnectTimeout(5000);
                            isConnected = connection.getResponseCode() == HttpURLConnection.HTTP_OK;
                        } catch (Exception e) {
                            e.printStackTrace();
                        }
                    }
                }).start();

                if (isConnected == false){
                    alertDialog.setMessage("Try " +  (5 - millisUntilFinished/1000) + " of 5.");
                } else {
                    alertDialog.dismiss();
                }
            }
            @Override
            public void onFinish() {
                if (isConnected == false) {
                    alertDialog.dismiss();
                    new AlertDialog.Builder(activity)
                            .setTitle("No Internet")
                            .setMessage("Please connect to Internet first.")
                            .setPositiveButton(android.R.string.yes, new DialogInterface.OnClickListener() {
                                public void onClick(DialogInterface dialog, int which) {
                                    // kill the app?
                                }
                            })
                            .setIcon(android.R.drawable.ic_dialog_alert)
                            .show();
                } else {
                    // Launch the app
                }
            }
        }.start();

我在这里看到了很多过时的答案,所以我决定加入我的答案。

由于Android 10 (API级别29)getActiveNetworkInfo()已弃用,谷歌建议我们使用NetworkCallbacks而不是针对Android 10及更高版本的应用程序。

关于阅读网络状态的文档提供了一些关于如何使用NetworkCallback的信息,但我没有设法找到一个很好的代码示例,整个事情的工作,所以这里是我提出的代码,我们在我们的应用程序中使用:

import android.content.Context
import android.net.ConnectivityManager
import android.net.LinkProperties
import android.net.Network
import android.net.NetworkCapabilities
import com.fieldontrack.kmm.common.network.ConnectivityMonitor
import com.fieldontrack.kmm.entities.connectivity.NetworkType
import kotlinx.coroutines.flow.MutableStateFlow
import kotlinx.coroutines.flow.StateFlow

class ConnectivityMonitorImpl(appContext: Context) : ConnectivityMonitor {
    private val connectivityManager = appContext.getSystemService(ConnectivityManager::class.java)
    private val networkCallback = object : ConnectivityManager.NetworkCallback() {
        override fun onAvailable(network: Network) =
            connectivityManager.getNetworkCapabilities(network)?.let { networkCapabilities ->
                updateConnectionStatus(networkCapabilities = networkCapabilities)
                updateNetworkType(networkCapabilities = networkCapabilities)
            } ?: run {
                _isConnectedState.value = true
            }

        override fun onLost(network: Network) {
            // Do not check for NetworkCapabilities here, as they might be wrong.
            // If we get this callback, we're certain that we've lost connection.
            _isConnectedState.value = false
            _networkTypeState.value = NetworkType.Unknown
        }

        override fun onCapabilitiesChanged(
            network: Network,
            networkCapabilities: NetworkCapabilities
        ) {
            updateConnectionStatus(networkCapabilities = networkCapabilities)
            updateNetworkType(networkCapabilities = networkCapabilities)
        }

        override fun onLinkPropertiesChanged(
            network: Network,
            linkProperties: LinkProperties
        ) = Unit
    }
    private val _isConnectedState = MutableStateFlow(false)
    private val _networkTypeState = MutableStateFlow(NetworkType.Unknown)

    override val isConnectedState: StateFlow<Boolean> = _isConnectedState
    override val networkTypeState: StateFlow<NetworkType> = _networkTypeState

    override val isConnected: Boolean
        get() = _isConnectedState.value

    override val networkType: NetworkType
        get() = _networkTypeState.value

    init {
        startMonitoring()
    }

    override fun startMonitoring() =
        connectivityManager.registerDefaultNetworkCallback(networkCallback)

    override fun stopMonitoring() =
        connectivityManager.unregisterNetworkCallback(networkCallback)

    private fun updateConnectionStatus(networkCapabilities: NetworkCapabilities) {
        val isConnected =
            networkCapabilities.hasCapability(NetworkCapabilities.NET_CAPABILITY_INTERNET)

        _isConnectedState.value = isConnected
    }

    private fun updateNetworkType(networkCapabilities: NetworkCapabilities) {
        val networkType = when {
            networkCapabilities.hasTransport(NetworkCapabilities.TRANSPORT_WIFI) -> NetworkType.WiFi
            networkCapabilities.hasTransport(NetworkCapabilities.TRANSPORT_CELLULAR) -> NetworkType.Cellular
            else -> NetworkType.Unknown
        }

        _networkTypeState.value = networkType
    }
}

ConnectivityMonitor界面非常简单:

interface ConnectivityMonitor {
    val isConnected: Boolean
    val networkType: NetworkType

    val isConnectedState: StateFlow<Boolean>
    val networkTypeState: StateFlow<NetworkType>
    
    fun startMonitoring()
    fun stopMonitoring()
}

NetworkType只是一个简单的枚举:

enum class NetworkType { Unknown, Cellular, WiFi }

据我测试,无论应用程序是在后台还是前台,这都是可行的。

不需要太复杂。最简单的框架方式是使用ACCESS_NETWORK_STATE权限并创建一个连接的方法

public boolean isOnline() {
    ConnectivityManager cm =
        (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);

    return cm.getActiveNetworkInfo() != null && 
       cm.getActiveNetworkInfo().isConnectedOrConnecting();
}

如果您有特定的主机和连接类型(wifi/移动),也可以使用requestRouteToHost。

你还需要:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />

在你的android清单中。

在我目前所见过的所有方法中,最短、最干净的方法应该是:

public final static boolean isConnected( Context context )
{   
   final ConnectivityManager connectivityManager = 
         (ConnectivityManager) context.getSystemService( Context.CONNECTIVITY_SERVICE );  
   final NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();    
   return networkInfo != null && networkInfo.isConnected();
}

PS:这不会ping任何主机,它只是检查连接状态,所以如果你的路由器没有互联网连接,而你的设备连接到它,这个方法将返回true,尽管你没有互联网。 对于实际的测试,我建议执行一个HttpHead请求(例如到www.google.com)并检查状态,如果它是200 OK,一切正常,并且您的设备有互联网连接。

下面是一些现代代码,使用AsynTask来解决android崩溃的问题,当你尝试在主线程上连接并为用户引入一个带有冲洗和重复选项的警报。

class TestInternet extends AsyncTask<Void, Void, Boolean> {
    @Override
    protected Boolean doInBackground(Void... params) {
        try {
            URL url = new URL("http://www.google.com");
            HttpURLConnection urlc = (HttpURLConnection) url.openConnection();
            urlc.setConnectTimeout(3000);
            urlc.connect();
            if (urlc.getResponseCode() == 200) {
                return true;
            }
        } catch (MalformedURLException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
            return false;
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
            return false;
        }
        return false;
    }

    @Override
    protected void onPostExecute(Boolean result) {
        if (!result) { // code if not connected
            AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
            builder.setMessage("An internet connection is required.");
            builder.setCancelable(false);

            builder.setPositiveButton(
                    "TRY AGAIN",
                    new DialogInterface.OnClickListener() {
                        public void onClick(DialogInterface dialog, int id) {
                            dialog.cancel();
                            new TestInternet().execute();
                        }
                    });


            AlertDialog alert11 = builder.create();
            alert11.show();
        } else { // code if connected
            doMyStuff();
        }
    }
}

...

new TestInternet().execute();