我得到了一个AsyncTask,应该检查对主机名的网络访问。但是doInBackground()永远不会超时。有人知道吗?

public class HostAvailabilityTask extends AsyncTask<String, Void, Boolean> {

    private Main main;

    public HostAvailabilityTask(Main main) {
        this.main = main;
    }

    protected Boolean doInBackground(String... params) {
        Main.Log("doInBackground() isHostAvailable():"+params[0]);

        try {
            return InetAddress.getByName(params[0]).isReachable(30); 
        } catch (UnknownHostException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return false;       
    }

    protected void onPostExecute(Boolean... result) {
        Main.Log("onPostExecute()");

        if(result[0] == false) {
            main.setContentView(R.layout.splash);
            return;
        }

        main.continueAfterHostCheck();
    }   
}

当前回答

我已经应用了@Levit提供的解决方案,并创建了不会调用额外Http请求的函数。

它将解决无法解析主机的错误

public static boolean isInternetAvailable(Context context) {
    ConnectivityManager cm = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    if (activeNetwork == null) return false;

    switch (activeNetwork.getType()) {
        case ConnectivityManager.TYPE_WIFI:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        case ConnectivityManager.TYPE_MOBILE:
            if ((activeNetwork.getState() == NetworkInfo.State.CONNECTED ||
                    activeNetwork.getState() == NetworkInfo.State.CONNECTING) &&
                    isInternet())
                return true;
            break;
        default:
            return false;
    }
    return false;
}

private static boolean isInternet() {

    Runtime runtime = Runtime.getRuntime();
    try {
        Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
        int exitValue = ipProcess.waitFor();
        Debug.i(exitValue + "");
        return (exitValue == 0);
    } catch (IOException | InterruptedException e) {
        e.printStackTrace();
    }

    return false;
}

现在叫它,

if (!isInternetAvailable(getActivity())) {
     //Show message
} else {
     //Perfoem the api request
}

其他回答

网络连接/互联网接入

isConnectedOrConnecting()(在大多数回答中使用)检查任何网络连接 要了解这些网络是否有internet接入,请使用以下方法之一

A) Ping服务器(简单)

// ICMP 
public boolean isOnline() {
    Runtime runtime = Runtime.getRuntime();
    try {
        Process ipProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
        int     exitValue = ipProcess.waitFor();
        return (exitValue == 0);
    }
    catch (IOException e)          { e.printStackTrace(); }
    catch (InterruptedException e) { e.printStackTrace(); }

    return false;
}

+可以在主线程上运行

在一些旧设备上不能工作(Galays S3等),如果没有网络,它会阻塞一段时间。

B)连接到Internet上的Socket(高级)

// TCP/HTTP/DNS (depending on the port, 53=DNS, 80=HTTP, etc.)
public boolean isOnline() {
    try {
        int timeoutMs = 1500;
        Socket sock = new Socket();
        SocketAddress sockaddr = new InetSocketAddress("8.8.8.8", 53);

        sock.connect(sockaddr, timeoutMs);
        sock.close();

        return true;
    } catch (IOException e) { return false; }
}

+非常快(任何一种方式),适用于所有设备,非常可靠

-不能在UI线程上运行

这工作非常可靠,在每个设备上,非常快。它需要在一个单独的任务中运行(例如ScheduledExecutorService或AsyncTask)。

可能的问题

Is it really fast enough? Yes, very fast ;-) Is there no reliable way to check internet, other than testing something on the internet? Not as far as I know, but let me know, and I will edit my answer. What if the DNS is down? Google DNS (e.g. 8.8.8.8) is the largest public DNS in the world. As of 2018 it handled over a trillion queries a day [1]. Let 's just say, your app would probably not be the talk of the day. Which permissions are required? <uses-permission android:name="android.permission.INTERNET" /> Just internet access - surprise ^^ (Btw have you ever thought about, how some of the methods suggested here could even have a remote glue about internet access, without this permission?)

 

额外:一次性RxJava/RxAndroid示例(Kotlin)

fun hasInternetConnection(): Single<Boolean> {
  return Single.fromCallable {
    try {
      // Connect to Google DNS to check for connection
      val timeoutMs = 1500
      val socket = Socket()
      val socketAddress = InetSocketAddress("8.8.8.8", 53)
    
      socket.connect(socketAddress, timeoutMs)
      socket.close()
  
      true
    } catch (e: IOException) {
      false
    }
  }
  .subscribeOn(Schedulers.io())
  .observeOn(AndroidSchedulers.mainThread())
}

///////////////////////////////////////////////////////////////////////////////////
// Usage

    hasInternetConnection().subscribe { hasInternet -> /* do something */}

额外:一次性RxJava/RxAndroid示例(Java)

public static Single<Boolean> hasInternetConnection() {
    return Single.fromCallable(() -> {
        try {
            // Connect to Google DNS to check for connection
            int timeoutMs = 1500;
            Socket socket = new Socket();
            InetSocketAddress socketAddress = new InetSocketAddress("8.8.8.8", 53);

            socket.connect(socketAddress, timeoutMs);
            socket.close();

            return true;
        } catch (IOException e) {
            return false;
        }
    }).subscribeOn(Schedulers.io()).observeOn(AndroidSchedulers.mainThread());
}

///////////////////////////////////////////////////////////////////////////////////
// Usage

    hasInternetConnection().subscribe((hasInternet) -> {
        if(hasInternet) {

        }else {

        }
    });

额外:一次性AsyncTask示例

注意:这是如何执行请求的另一个示例。然而,由于AsyncTask已弃用,它应该被你的应用程序的线程调度,Kotlin协程,Rx,…

class InternetCheck extends AsyncTask<Void,Void,Boolean> {

    private Consumer mConsumer;
    public  interface Consumer { void accept(Boolean internet); }

    public  InternetCheck(Consumer consumer) { mConsumer = consumer; execute(); }

    @Override protected Boolean doInBackground(Void... voids) { try {
        Socket sock = new Socket();
        sock.connect(new InetSocketAddress("8.8.8.8", 53), 1500);
        sock.close();
        return true;
    } catch (IOException e) { return false; } }

    @Override protected void onPostExecute(Boolean internet) { mConsumer.accept(internet); }
}

///////////////////////////////////////////////////////////////////////////////////
// Usage

    new InternetCheck(internet -> { /* do something with boolean response */ });

只需创建下面的类来检查internet连接:

public class ConnectionStatus {

    private Context _context;

    public ConnectionStatus(Context context) {
        this._context = context;
    }

    public boolean isConnectionAvailable() {
        ConnectivityManager connectivity = (ConnectivityManager) _context
                .getSystemService(Context.CONNECTIVITY_SERVICE);
        if (connectivity != null) {
            NetworkInfo[] info = connectivity.getAllNetworkInfo();
            if (info != null)
                for (int i = 0; i < info.length; i++)
                    if (info[i].getState() == NetworkInfo.State.CONNECTED) {
                        return true;
                    }
        }
        return false;
    }
}

该类仅包含一个返回连接状态布尔值的方法。因此,简单来说,如果该方法找到一个到Internet的有效连接,则返回值为true,否则为false,如果没有找到有效连接。

MainActivity中的下面的方法调用前面描述的方法的结果,并提示用户进行相应的操作:

public void addListenerOnWifiButton() {
        Button btnWifi = (Button)findViewById(R.id.btnWifi);

        iia = new ConnectionStatus(getApplicationContext());

        isConnected = iia.isConnectionAvailable();
        if (!isConnected) {
            btnWifi.setOnClickListener(new View.OnClickListener() {

                @Override
                public void onClick(View v) {
                    startActivity(new Intent(Settings.ACTION_WIFI_SETTINGS));
                    Toast.makeText(getBaseContext(), "Please connect to a hotspot",
                            Toast.LENGTH_SHORT).show();
                }
            });
        }
        else {
            btnWifi.setVisibility(4);
            warning.setText("This app may use your mobile data to update events and get their details.");
        }
    }

在上面的代码中,如果结果为假,(因此没有互联网连接,用户将被带到Android wi-fi面板,在那里他将被提示连接到wi-fi热点。

移动设备上的一个重要用例是确保存在实际连接。当移动用户使用“专属门户”进入Wifi网络时,这是一个常见的问题,他们需要在其中登录。我在后台使用这个阻塞功能来确保连接存在。

/*
 * Not Thread safe. Blocking thread. Returns true if it
 * can connect to URL, false and exception is logged.
 */
public boolean checkConnectionHttps(String url){
    boolean responded = false;
    HttpGet requestTest = new HttpGet(url);
    HttpParams params = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(params, 3000);
    HttpConnectionParams.setSoTimeout(params, 5000);
    DefaultHttpClient client = new DefaultHttpClient(params);
    try {
        client.execute(requestTest);
        responded = true;
    } catch (ClientProtocolException e) {
        Log.w(MainActivity.TAG,"Unable to connect to " + url + " " + e.toString());
    } catch (IOException e) {
        Log.w(MainActivity.TAG,"Unable to connect to " + url + " " + e.toString());
        e.printStackTrace();
    }
    return responded;
}

我在这里看到了很多过时的答案,所以我决定加入我的答案。

由于Android 10 (API级别29)getActiveNetworkInfo()已弃用,谷歌建议我们使用NetworkCallbacks而不是针对Android 10及更高版本的应用程序。

关于阅读网络状态的文档提供了一些关于如何使用NetworkCallback的信息,但我没有设法找到一个很好的代码示例,整个事情的工作,所以这里是我提出的代码,我们在我们的应用程序中使用:

import android.content.Context
import android.net.ConnectivityManager
import android.net.LinkProperties
import android.net.Network
import android.net.NetworkCapabilities
import com.fieldontrack.kmm.common.network.ConnectivityMonitor
import com.fieldontrack.kmm.entities.connectivity.NetworkType
import kotlinx.coroutines.flow.MutableStateFlow
import kotlinx.coroutines.flow.StateFlow

class ConnectivityMonitorImpl(appContext: Context) : ConnectivityMonitor {
    private val connectivityManager = appContext.getSystemService(ConnectivityManager::class.java)
    private val networkCallback = object : ConnectivityManager.NetworkCallback() {
        override fun onAvailable(network: Network) =
            connectivityManager.getNetworkCapabilities(network)?.let { networkCapabilities ->
                updateConnectionStatus(networkCapabilities = networkCapabilities)
                updateNetworkType(networkCapabilities = networkCapabilities)
            } ?: run {
                _isConnectedState.value = true
            }

        override fun onLost(network: Network) {
            // Do not check for NetworkCapabilities here, as they might be wrong.
            // If we get this callback, we're certain that we've lost connection.
            _isConnectedState.value = false
            _networkTypeState.value = NetworkType.Unknown
        }

        override fun onCapabilitiesChanged(
            network: Network,
            networkCapabilities: NetworkCapabilities
        ) {
            updateConnectionStatus(networkCapabilities = networkCapabilities)
            updateNetworkType(networkCapabilities = networkCapabilities)
        }

        override fun onLinkPropertiesChanged(
            network: Network,
            linkProperties: LinkProperties
        ) = Unit
    }
    private val _isConnectedState = MutableStateFlow(false)
    private val _networkTypeState = MutableStateFlow(NetworkType.Unknown)

    override val isConnectedState: StateFlow<Boolean> = _isConnectedState
    override val networkTypeState: StateFlow<NetworkType> = _networkTypeState

    override val isConnected: Boolean
        get() = _isConnectedState.value

    override val networkType: NetworkType
        get() = _networkTypeState.value

    init {
        startMonitoring()
    }

    override fun startMonitoring() =
        connectivityManager.registerDefaultNetworkCallback(networkCallback)

    override fun stopMonitoring() =
        connectivityManager.unregisterNetworkCallback(networkCallback)

    private fun updateConnectionStatus(networkCapabilities: NetworkCapabilities) {
        val isConnected =
            networkCapabilities.hasCapability(NetworkCapabilities.NET_CAPABILITY_INTERNET)

        _isConnectedState.value = isConnected
    }

    private fun updateNetworkType(networkCapabilities: NetworkCapabilities) {
        val networkType = when {
            networkCapabilities.hasTransport(NetworkCapabilities.TRANSPORT_WIFI) -> NetworkType.WiFi
            networkCapabilities.hasTransport(NetworkCapabilities.TRANSPORT_CELLULAR) -> NetworkType.Cellular
            else -> NetworkType.Unknown
        }

        _networkTypeState.value = networkType
    }
}

ConnectivityMonitor界面非常简单:

interface ConnectivityMonitor {
    val isConnected: Boolean
    val networkType: NetworkType

    val isConnectedState: StateFlow<Boolean>
    val networkTypeState: StateFlow<NetworkType>
    
    fun startMonitoring()
    fun stopMonitoring()
}

NetworkType只是一个简单的枚举:

enum class NetworkType { Unknown, Cellular, WiFi }

据我测试,无论应用程序是在后台还是前台,这都是可行的。

The other answers that use ConnectivityManager are wrong because having a network connection doesn't mean you have internet access. For example, the user might be connected to a coffee shop's WiFi portal but can't get to the internet. To check that the internet is accessible you have to try to connect to an actual server. Normally when you want to do this you have a specific server in mind that you want to connect to, so go ahead and check if you can connect to that server. Here's a simple method for checking connectivity to a server.

private boolean isOnTheInternet() {
    try {
        URLConnection urlConnection = new URL("http://yourserver").openConnection();
        urlConnection.setConnectTimeout(400);
        urlConnection.connect();
        return true;
    } catch (Exception e) {
        return false;
    }
}

设置ConnectTimeout的原因是,否则它默认为TCP超时,可以有很多秒长。

还要注意的是,Android不允许你在主线程上运行这个程序。