通过名称获取cookie

我有一个getter从cookie中获取值。

现在我有了两个cookie，名字分别是shares=和obligation =。

我想让这个getter只从义务cookie中获取值。

我怎么做呢?因此for语句将数据拆分为单独的值，并将其放入数组中。

 function getCookie1() {
    // What do I have to add here to look only in the "obligations=" cookie? 
    // Because now it searches all the cookies.

    var elements = document.cookie.split('=');
    var obligations= elements[1].split('%');
    for (var i = 0; i < obligations.length - 1; i++) {
        var tmp = obligations[i].split('$');
        addProduct1(tmp[0], tmp[1], tmp[2], tmp[3]);
    }
 }

当前回答

这是一个很简短的版本

 function getCookie(n) {
    let a = `; ${document.cookie}`.match(`;\\s*${n}=([^;]+)`);
    return a ? a[1] : '';
}

注意，我使用了ES6的模板字符串来组成正则表达式。

2016-11-24 12:24:20

其他回答

我喜欢使用闭包按名称获取cookie值。下面的闭包将允许您通过名称获取cookie值，但只有在更新了cookie字符串时才会解析cookie字符串。

您可以通过以下方法检索cookie的值:

var foo = cookies.get( "bar" );

代码:

var cookies = ( function() {
    var cookieString = null;
    var cookieArray = [];

    function getValOf( name ) {
        if ( newCookies() ) {
            parseCookieString()
        }
        return cookieArray[ name ];
    }

    // Check if new cookies have been added
    function newCookies() {
        return cookieString === document.cookie;
    }

    function parseCookieString() {
        cookieString = document.cookie;

        // Separate cookies
        var cookies = cookieString.split( ";" );

        // Empty previous cookies
        cookieArray = [];

        // Update cookieArray with new name-value pairs
        for ( var i in cookies ) {

            // Separate name and value
            var nameVal = cookies[ i ].split( "=" );
            var name = nameVal[ 0 ].trim();
            var value = nameVal[ 1 ].trim();

            // Add cookie name value pair to dictionary
            cookieArray[ name ] = value;
        }
    }

    return {

        /**
         * Returns value or undefined
         */
        get: function( name ) {
            return getValOf( name );
        }  
    };
})();

2016-04-07 17:15:47

通过名称获取cookie只需将cookie的名称传递给下面的函数

function getCookie(cname) {
  var name = cname + "=";
  var decodedCookie = decodeURIComponent(document.cookie);
  var ca = decodedCookie.split(';');
  for(var i = 0; i <ca.length; i++) {
    var c = ca[i];
    while (c.charAt(0) == ' ') {
      c = c.substring(1);
    }
    if (c.indexOf(name) == 0) {
      return c.substring(name.length, c.length);
    }
  }
  return "";
}

2020-05-30 09:29:49

总是很有效:

function getCookie(cname) {
    var name = cname + "=",
        ca = document.cookie.split(';'),
        i,
        c,
        ca_length = ca.length;
    for (i = 0; i < ca_length; i += 1) {
        c = ca[i];
        while (c.charAt(0) === ' ') {
            c = c.substring(1);
        }
        if (c.indexOf(name) !== -1) {
            return c.substring(name.length, c.length);
        }
    }
    return "";
}

function setCookie(variable, value, expires_seconds) {
    var d = new Date();
    d = new Date(d.getTime() + 1000 * expires_seconds);
    document.cookie = variable + '=' + value + '; expires=' + d.toGMTString() + ';';
}

对jQuery或任何东西都没有要求。纯粹的老JavaScript。

2015-03-13 16:52:59

在我的项目中，我使用以下函数按名称访问cookie

function getCookie(cookie) {
    return document.cookie.split(';').reduce(function(prev, c) {
        var arr = c.split('=');
        return (arr[0].trim() === cookie) ? arr[1] : prev;
    }, undefined);
}

2013-11-14 07:02:42

const cookies = 'key1=chocolate; key2=iceCream; key3=cookies;';

// convert string into array with split
const arrCookies = cookies.split('; '); // [ 'key1=chocolate', 'key2=iceCream', 'key3=cookies' ]

// split key value by equal sign
const arrArrCookiesKeyValue = arrCookies.map(cookie => [cookie.split('=')]);  // [[['key1', 'chocolate']], ...']

// make an object with key value
const objectKeyValueCookies = {}; // { key1: 'chocolate', key2: 'iceCream', key3: 'cookies;' }
for (let arr of arrArrCookiesKeyValue) {
    objectKeyValueCookies[arr[0][0]] = arr[0][1];
}

// find the key in object
const findValueByKey = (key = null, objectCookies) => objectCookies[key];
console.log(findValueByKey('key2', objectKeyValueCookies)); // chocolate

2021-03-23 02:16:39

通过名称获取cookie

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