事情就是这么简单;

let initial_date = new Date;
let added30Min = new Date(initial_date.getTime() + (30*60*1000));

新日期() var newDateObj =新日期(); (+ 30 * 60 * 1000); 游戏机。log (newDateObj);

也许像这样?

var d = new Date(); var v = new Date(); v.setMinutes (d.getMinutes () + 30); console.log (v)

你可以这样做:

let 30tyminutes = 30 * 60 * 1000;//将30分钟转换为毫秒 let date1 = new Date(); let date2 = new Date(date1.getTime() + 30tyminutes); console.log (date1); console.log (date2);

这就是我所做的，似乎很有效:

Date.prototype.addMinutes = function(minutes) {
    var copiedDate = new Date(this.getTime());
    return new Date(copiedDate.getTime() + minutes * 60000);
}

然后你可以这样调用它:

var now = new Date();
console.log(now.addMinutes(50));

其他解决方案:

var dateAv = new Date();
var endTime = new Date(dateAv.getFullYear(), dateAv.getMonth(), dateAv.getDate(), dateAv.getHours(), dateAv.getMinutes() + 30);