我想获得一个日期对象,它比另一个日期对象晚30分钟。我如何用JavaScript做到这一点?


当前回答

事情就是这么简单;

let initial_date = new Date;
let added30Min = new Date(initial_date.getTime() + (30*60*1000));

其他回答

事情就是这么简单;

let initial_date = new Date;
let added30Min = new Date(initial_date.getTime() + (30*60*1000));

“添加”30分钟的一种方法是创建第二个日期对象(主要用于演示),并将分钟设置为分钟+ 30。如果第一次距离下一个小时不到30分钟,这也可以考虑调整时间。(即4:45至5:15)

const first = new Date(); console.log("第一次约会:",first. tostring ()); const second =新的日期(第一个); const newMinutes = second.getMinutes() + 30; console.log("new minutes:", newMinutes); second.setMinutes (newMinutes); console.log("second date:", second. tostring ());

对于像我这样的懒人:

Kip的答案(从上面)在coffeescript中,使用“enum”,并对同一对象进行操作:

Date.UNIT =
  YEAR: 0
  QUARTER: 1
  MONTH: 2
  WEEK: 3
  DAY: 4
  HOUR: 5
  MINUTE: 6
  SECOND: 7
Date::add = (unit, quantity) ->
  switch unit
    when Date.UNIT.YEAR then @setFullYear(@getFullYear() + quantity)
    when Date.UNIT.QUARTER then @setMonth(@getMonth() + (3 * quantity))
    when Date.UNIT.MONTH then @setMonth(@getMonth() + quantity)
    when Date.UNIT.WEEK then @setDate(@getDate() + (7 * quantity))
    when Date.UNIT.DAY then @setDate(@getDate() + quantity)
    when Date.UNIT.HOUR then @setTime(@getTime() + (3600000 * quantity))
    when Date.UNIT.MINUTE then @setTime(@getTime() + (60000 * quantity))
    when Date.UNIT.SECOND then @setTime(@getTime() + (1000 * quantity))
    else throw new Error "Unrecognized unit provided"
  @ # for chaining

一行代码

  var afterSomeMinutes = new Date(new Date().getTime() + minutes * 60000);

在哪里分钟是一个数字

var d1 = new Date (),
    d2 = new Date ( d1 );
d2.setMinutes ( d1.getMinutes() + 30 );
alert ( d2 );