是否有一种方法可以动态地获取函数的函数参数名?
假设我的函数是这样的
function doSomething(param1, param2, .... paramN){
// fill an array with the parameter name and value
// some other code
}
现在,我如何从函数内部获得参数名称及其值的列表到数组中?
是否有一种方法可以动态地获取函数的函数参数名?
假设我的函数是这样的
function doSomething(param1, param2, .... paramN){
// fill an array with the parameter name and value
// some other code
}
现在,我如何从函数内部获得参数名称及其值的列表到数组中?
当前回答
(function(a,b,c){}).toString().replace(/.*\(|\).*/ig,"").split(',')
=> ["a", "b", "c"]
其他回答
这很简单。
At the first there is a deprecated arguments.callee — a reference to called function. At the second if you have a reference to your function you can easily get their textual representation. At the third if you calling your function as constructor you can also have a link via yourObject.constructor. NB: The first solution deprecated so if you can't to not use it you must also think about your app architecture. If you don't need exact variable names just use inside a function internal variable arguments without any magic.
https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Functions_and_function_scope/arguments/callee
它们都将调用toString并将其替换为re,这样我们就可以创建一个helper:
// getting names of declared parameters
var getFunctionParams = function (func) {
return String(func).replace(/[^\(]+\(([^\)]*)\).*/m, '$1');
}
一些例子:
// Solution 1. deprecated! don't use it!
var myPrivateFunction = function SomeFuncName (foo, bar, buz) {
console.log(getFunctionParams(arguments.callee));
};
myPrivateFunction (1, 2);
// Solution 2.
var myFunction = function someFunc (foo, bar, buz) {
// some code
};
var params = getFunctionParams(myFunction);
console.log(params);
// Solution 3.
var cls = function SuperKewlClass (foo, bar, buz) {
// some code
};
var inst = new cls();
var params = getFunctionParams(inst.constructor);
console.log(params);
享受与JS!
UPD:实际上杰克·艾伦提供了一个更好的解决方案。GJ杰克!
这个包使用重铸来创建AST,然后从它们收集参数名,这允许它支持模式匹配,默认参数,箭头函数和其他ES6特性。
https://www.npmjs.com/package/es-arguments
哇,已经有这么多答案了。我很确定这件事会被埋葬。即便如此,我觉得这对一些人来说可能有用。
我对所选的答案并不完全满意,因为在ES6中,默认值不能很好地工作。它也不提供默认值信息。我还想要一个不依赖于外部库的轻量级函数。
这个函数对于调试非常有用,例如:记录被调用函数的参数、默认参数值和参数。
我昨天花了一些时间在这个问题上,破解正确的RegExp来解决这个问题,这就是我想到的。它运行得非常好,我对结果非常满意:
const REGEX_COMMENTS = /((\/\/.*$)|(\/\*[\s\S]*?\*\/))/mg; const REGEX_FUNCTION_PARAMS = /(?:\s*(?:function\s*[^(]*)?\s*)((?:[^'"]|(?:(?:(['"])(?:(?:.*?[^\\]\2)|\2))))*?)\s*(?=(?:=>)|{)/m const REGEX_PARAMETERS_VALUES = /\s*(\w+)\s*(?:=\s*((?:(?:(['"])(?:\3|(?:.*?[^\\]\3)))((\s*\+\s*)(?:(?:(['"])(?:\6|(?:.*?[^\\]\6)))|(?:[\w$]*)))*)|.*?))?\s*(?:,|$)/gm /** * Retrieve a function's parameter names and default values * Notes: * - parameters with default values will not show up in transpiler code (Babel) because the parameter is removed from the function. * - does NOT support inline arrow functions as default values * to clarify: ( name = "string", add = defaultAddFunction ) - is ok * ( name = "string", add = ( a )=> a + 1 ) - is NOT ok * - does NOT support default string value that are appended with a non-standard ( word characters or $ ) variable name * to clarify: ( name = "string" + b ) - is ok * ( name = "string" + $b ) - is ok * ( name = "string" + b + "!" ) - is ok * ( name = "string" + λ ) - is NOT ok * @param {function} func * @returns {Array} - An array of the given function's parameter [key, default value] pairs. */ function getParams(func) { let functionAsString = func.toString() let params = [] let match functionAsString = functionAsString.replace(REGEX_COMMENTS, '') functionAsString = functionAsString.match(REGEX_FUNCTION_PARAMS)[1] if (functionAsString.charAt(0) === '(') functionAsString = functionAsString.slice(1, -1) while (match = REGEX_PARAMETERS_VALUES.exec(functionAsString)) params.push([match[1], match[2]]) return params } // Lets run some tests! var defaultName = 'some name' function test1(param1, param2, param3) { return (param1) => param1 + param2 + param3 } function test2(param1, param2 = 4 * (5 / 3), param3) {} function test3(param1, param2 = "/root/" + defaultName + ".jpeg", param3) {} function test4(param1, param2 = (a) => a + 1) {} console.log(getParams(test1)) console.log(getParams(test2)) console.log(getParams(test3)) console.log(getParams(test4)) // [ [ 'param1', undefined ], [ 'param2', undefined ], [ 'param3', undefined ] ] // [ [ 'param1', undefined ], [ 'param2', '4 * (5 / 3)' ], [ 'param3', undefined ] ] // [ [ 'param1', undefined ], [ 'param2', '"/root/" + defaultName + ".jpeg"' ], [ 'param3', undefined ] ] // [ [ 'param1', undefined ], [ 'param2', '( a' ] ] // --> This last one fails because of the inlined arrow function! var arrowTest1 = (a = 1) => a + 4 var arrowTest2 = a => b => a + b var arrowTest3 = (param1 = "/" + defaultName) => { return param1 + '...' } var arrowTest4 = (param1 = "/" + defaultName, param2 = 4, param3 = null) => { () => param3 ? param3 : param2 } console.log(getParams(arrowTest1)) console.log(getParams(arrowTest2)) console.log(getParams(arrowTest3)) console.log(getParams(arrowTest4)) // [ [ 'a', '1' ] ] // [ [ 'a', undefined ] ] // [ [ 'param1', '"/" + defaultName' ] ] // [ [ 'param1', '"/" + defaultName' ], [ 'param2', '4' ], [ 'param3', 'null' ] ] console.log(getParams((param1) => param1 + 1)) console.log(getParams((param1 = 'default') => { return param1 + '.jpeg' })) // [ [ 'param1', undefined ] ] // [ [ 'param1', '\'default\'' ] ]
正如你所知道的,一些参数名消失了,因为Babel转译器将它们从函数中删除了。如果你在最新的NodeJS中运行它,它会像预期的那样工作(注释的结果来自NodeJS)。
另一个注意事项,正如注释中所述,它不能作为默认值与内联箭头函数一起工作。这使得使用RegExp提取值变得非常复杂。
如果这对你有用,请让我知道!很乐意听到一些反馈!
这是我的解决方案——它适用于命名函数和未命名函数,异步和非异步函数,异步和非异步lambdas,以及带和不带paren的lambdas。
const STRIP_COMMENTS = /((\/\/.*$)|(\/\*.*\*\/))/mg;
const STRIP_KEYWORDS = /(\s*async\s*|\s*function\s*)+/;
const ARGUMENT_NAMES = /\(([^)]+)\)\s*=>|([a-zA-Z_$]+)\s*=>|[a-zA-Z_$]+\(([^)]+)\)|\(([^)]+)\)/;
const ARGUMENT_SPLIT = /[ ,\n\r\t]+/;
function getParamNames(func) {
const fnStr = func.toString()
.replace(STRIP_COMMENTS, "")
.replace(STRIP_KEYWORDS, "")
.trim();
const matches = ARGUMENT_NAMES.exec(fnStr);
var match;
if (matches) {
for (var i = 1; i < matches.length; i++) {
if (matches[i]) {
match = matches[i];
break;
}
}
}
if (match === undefined) {
return [];
}
return match.split(ARGUMENT_SPLIT).filter(part => part !== "");
}
尝试手动:
function something(arg1, arg2) {
console.log ( arg1 + arg2 );
}