在安卓系统中防止双击按钮的最佳方法是什么?
当前回答
防止点击乘法btns
使用:
private val disposables = CompositeDisposable()
private val clickInteractor = ClickInteractor(disposables)
...
button1.setOnClickListener{
clickInteractor.click {
Toast.makeText(context, "Btn1", Toast.LENGTH_LONG).show()
}
}
button2.setOnClickListener{
clickInteractor.click {
Toast.makeText(context, "Btn2", Toast.LENGTH_LONG).show()
}
}
ClickInteractor.kt:
class ClickInteractor constructor(disposables: CompositeDisposable) {
private val performPublish = PublishSubject.create<ClickInteractorCallback>()
init {
performPublish
.subscribeOn(Schedulers.io())
.observeOn(Schedulers.io())
.throttleFirst(1, TimeUnit.SECONDS, Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.doOnNext { callback ->
callback.invoke()
}
.retry()
.execute(disposables)
}
fun click(callback: ClickInteractorCallback) {
performPublish.onNext(callback)
}
}
typealias ClickInteractorCallback = () -> Unit
其他回答
我的解决方案是
package com.shuai.view;
import android.os.SystemClock;
import android.view.View;
/**
* 处理快速在某个控件上双击2次(或多次)会导致onClick被触发2次(或多次)的问题
* 通过判断2次click事件的时间间隔进行过滤
*
* 子类通过实现{@link #onSingleClick}响应click事件
*/
public abstract class OnSingleClickListener implements View.OnClickListener {
/**
* 最短click事件的时间间隔
*/
private static final long MIN_CLICK_INTERVAL=600;
/**
* 上次click的时间
*/
private long mLastClickTime;
/**
* click响应函数
* @param v The view that was clicked.
*/
public abstract void onSingleClick(View v);
@Override
public final void onClick(View v) {
long currentClickTime=SystemClock.uptimeMillis();
long elapsedTime=currentClickTime-mLastClickTime;
//有可能2次连击,也有可能3连击,保证mLastClickTime记录的总是上次click的时间
mLastClickTime=currentClickTime;
if(elapsedTime<=MIN_CLICK_INTERVAL)
return;
onSingleClick(v);
}
}
用法类似于OnClickListener,但重写onSingleClick()代替:
mTextView.setOnClickListener(new OnSingleClickListener() {
@Override
public void onSingleClick(View v) {
if (DEBUG)
Log.i("TAG", "onclick!");
}
};
The Best and simple solution i found is
1. to create a boolean and set as false (default) like
private boolean itemClicked = false;
/* for a safer side you can also declare boolean false in onCreate() also. */
and at onclick() method check
2. if(!itemClicked)
{
itemClicked = true;
// rest of your coding functionality goes here of onClick method.
}
3. last step is to set boolean false in onResume()
@override
onResume()
{
super.onResume(0);
itemClicked = false;
}
setEnabled(false)非常适合我。
我写{setEnabled(true);},并在第一次点击按钮时将其设为false。
Kotlin创建类SafeClickListener
class SafeClickListener(
private var defaultInterval: Int = 1000,
private val onSafeCLick: (View) -> Unit
) : View.OnClickListener {
private var lastTimeClicked: Long = 0 override fun onClick(v: View) {
if (SystemClock.elapsedRealtime() - lastTimeClicked < defaultInterval) {
return
}
lastTimeClicked = SystemClock.elapsedRealtime()
onSafeCLick(v)
}
}
在baseClass或else中创建一个函数
fun View.setSafeOnClickListener(onSafeClick: (View) -> Unit) {val safeClickListener = SafeClickListener {
onSafeClick(it)
}
setOnClickListener(safeClickListener)
}
并使用按钮点击
btnSubmit.setSafeOnClickListener {
showSettingsScreen()
}
我的解决方案(Kotlin):
class OnDebouncedClickListener(private val delayInMilliSeconds: Long, val action: () -> Unit) : View.OnClickListener {
var enable = true
override fun onClick(view: View?) {
if (enable) {
enable = false
view?.postDelayed(delayInMilliSeconds) { enable = true }
action()
}
}
}
fun View.setOnDebouncedClickListener(delayInMilliSeconds: Long = 500, action: () -> Unit) {
val onDebouncedClickListener = OnDebouncedClickListener(delayInMilliSeconds, action)
setOnClickListener(onDebouncedClickListener)
}
使用:
button.apply {
setOnDebouncedClickListener {
//your action on click
}
}
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