在安卓系统中防止双击按钮的最佳方法是什么?


当前回答

结合Gustavo的答案,我已经在Kotlin中实现了看起来非常干净的扩展:

fun View.setOnSingleClickListener(l: () -> Unit) {
  setOnClickListener { view ->
    l.invoke(view)
      isEnabled = false
      postDelayed({
        isEnabled = true
      }, 600)
  }
}

这是你如何设置这个点击监听器:

yourView.setOnSingleClickListener {
  // Insert your code here
}

其他回答

在我的情况下,我使用按钮视图,它的点击速度太快了。只需禁用点击,并在几秒钟后再次启用它…

基本上我做了一个包装类,包装你的Views onClickListener。如果您愿意,还可以设置自定义延迟。

public class OnClickRateLimitedDecoratedListener implements View.OnClickListener {

    private final static int CLICK_DELAY_DEFAULT = 300;
    private View.OnClickListener onClickListener;
    private int mClickDelay;


        public OnClickRateLimitedDecoratedListener(View.OnClickListener onClickListener) {
            this(onClickListener, CLICK_DELAY_DEFAULT);
        }

        //customize your own delay
        public OnClickRateLimitedDecoratedListener(View.OnClickListener onClickListener, int delay) {
            this.onClickListener = onClickListener;
            mClickDelay = delay;
        }

        @Override
        public void onClick(final View v) {
            v.setClickable(false);
            onClickListener.onClick(v);

            v.postDelayed(new Runnable() {
                @Override
                public void run() {
                    v.setClickable(true);
                }
            }, mClickDelay);
        }
    }

简单地调用它:

mMyButton.setOnClickListener(new OnClickRateLimitedDecoratedListener(new View.OnClickListener() {
             @Override
             public void onClick(View v) {
                 doSomething();
             }
         }));

或者提供你自己的延迟:

 mMyButton.setOnClickListener(new OnClickRateLimitedDecoratedListener(new View.OnClickListener() {
                     @Override
                     public void onClick(View v) {
                         doSomething();
                     }
                 },1000));

更新:以上方式有点过时,现在RxJava是如此流行。正如其他人所提到的,在android中我们可以使用油门来减慢点击。这里有一个例子:

 RxView.clicks(myButton)
                    .throttleFirst(2000, TimeUnit.MILLISECONDS, AndroidSchedulers.mainThread())
                    .subscribe {
                        Log.d("i got delayed clicked")
                    }
        }

实现'com. jake沃顿。rxbinding:2.0.0'

结合Gustavo的答案,我已经在Kotlin中实现了看起来非常干净的扩展:

fun View.setOnSingleClickListener(l: () -> Unit) {
  setOnClickListener { view ->
    l.invoke(view)
      isEnabled = false
      postDelayed({
        isEnabled = true
      }, 600)
  }
}

这是你如何设置这个点击监听器:

yourView.setOnSingleClickListener {
  // Insert your code here
}

I found none of these suggestions works if the onClick method doesn't return immediately. The touch event is queued by Android and the next onClick is called only after the first one is finished. (Since this is done on the one UI thread this is really normal.) I needed to use the time when the the onClick function is finished + one boolean variable to mark whether the given onClick is running. Both these marker attributes are static to avoid any onClickListener to run at the same time. (If user clicks on another button) You can simple replace your OnClickListener to this class and instead of implementing the onClick method you need to implement the abstract oneClick() method.

    abstract public class OneClickListener implements OnClickListener {

    private static boolean started = false;
    private static long lastClickEndTime = 0;

    /* (non-Javadoc)
     * @see android.view.View.OnClickListener#onClick(android.view.View)
     */
    @Override
    final public void onClick(final View v) {
        if(started || SystemClock.elapsedRealtime()-lastClickEndTime <1000 ){
            Log.d(OneClickListener.class.toString(), "Rejected double click, " + new Date().toString() );
            return; 
        }
        Log.d(OneClickListener.class.toString(), "One click, start: " + new Date().toString() );
        try{
            started = true;
            oneClick(v);
        }finally{
            started = false;
            lastClickEndTime = SystemClock.elapsedRealtime();
            Log.d(OneClickListener.class.toString(), "One click, end: " + new Date().toString() );
        }
    }

    abstract protected void oneClick(View v);
}

这是我的解决方案:

if (waitDouble) {
    waitDouble = false;
    Thread thread = new Thread() {
        @Override
        public void run() {
            try {
                sleep(300);
                if (waitDouble == false) {
                    waitDouble = true;
                    singleClick();  //singleClick
                }
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
    };
    thread.start();
} else {//DoubleClick
    DoubleClick();
    waitDouble = true;
}

或者另一种解决方案:

public class NoDoubleClickUtils {
    private static long lastClickTime;
    private final static int SPACE_TIME = 500;

    public static void initLastClickTime() {
        lastClickTime = 0;
    }

    public synchronized static boolean isDoubleClick() {
        long currentTime = System.currentTimeMillis();
        boolean isClick2;
        if (currentTime - lastClickTime > SPACE_TIME) {
            isClick2 = false;
        } else {
            isClick2 = true;
        }
        lastClickTime = currentTime;
        return isClick2;
    }
}

试试这个,它是有效的:

mButton.setOnClickListener(new View.OnClickListener() {

    @Override
    public void onClick(View v) {

                mSlotLayout.setEnabled(false);

        //      do your work here

                Timer buttonTimer = new Timer();
                buttonTimer.schedule(new TimerTask() {

                    @Override
                    public void run() {

                        runOnUiThread(new Runnable() {

                            @Override
                            public void run() {
                                mButton.setEnabled(true);
                            }
                        });
                    }
                }, 500); // delay button enable for 0.5 sec
    }
});