在安卓系统中防止双击按钮的最佳方法是什么?


当前回答

只有2步,你可以在你的应用程序的任何地方使用它。

步骤1。创建一个单例管理器[避免多次点击]

package com.im.av.mediator;

import android.os.SystemClock;

import java.util.HashMap;

/**
 * Created by ShuHeng on 16/6/1.
 */
public class ClickManager {



    private HashMap<Integer,Long> laskClickTimeMap=new HashMap<Integer,Long>();
    public volatile static ClickManager mInstance =null;

    public static ClickManager getInstance(){
        if (mInstance == null) {
            synchronized(ClickManager.class) {
                if (mInstance == null) {
                    mInstance = new ClickManager();
                }
            }
        }
        return mInstance;
    }
   public boolean isClickable1s(Integer key){
       Long keyLong = laskClickTimeMap.get(key);
       if(keyLong==null){
           laskClickTimeMap.put(key,SystemClock.elapsedRealtime());
           return true;
       }else{
           if (SystemClock.elapsedRealtime() - keyLong.longValue() < 1000){
               return false;
           }else{
               laskClickTimeMap.put(key,new Long(SystemClock.elapsedRealtime()));
               return true;
           }
       }
   }
}  

步骤2。添加一行,避免多次单击。

@Override
public void onClick(View v) {
    // TODO Auto-generated method stub
    int id = v.getId();
    if (id == R.id.iv_back) {
        if(!ClickManager.getInstance().isClickable1s(R.id.iv_back))return;
        //do something
    } else if (id == R.id.iv_light) {
        if(!ClickManager.getInstance().isClickable1s(R.id.iv_light))return;
        //do something
    } else if (id == R.id.iv_camerarotate) {
        if(!ClickManager.getInstance().isClickable1s(R.id.iv_camerarotate))return;
           //do something
    } else if (id == R.id.btn_delete_last_clip) {
        if(!ClickManager.getInstance().isClickable1s(R.id.btn_delete_last_clip))return;
          //do something

    } else if (id == R.id.iv_ok) {
        if(!ClickManager.getInstance().isClickable1s(R.id.iv_ok))return;
        //do something
    }
}

其他回答

当UI线程阻塞时,单击事件队列。对于按钮单击事件,请尽快将其更改为后台任务,以避免单击事件在彼此后面排队。

在activity类中声明一个volatile boolean或lock:

private volatile boolean saving = false;

创建一个onClickListener按钮,通过保存和启动一个后台任务来完成工作:

saveButton.setOnClickListener(new View.OnClickListener() {

    @Override
    public void onClick(View view) {
        if (!saving) {
            saving = true;
            new SaveAsyncTask().execute();
        }
    }
});

创建一个内部的SaveAsyncTask类来在后台完成工作:

class SaveAsyncTask extends AsyncTask {

    @Override
    protected Object doInBackground(Object[] objects) {
        // Do something here, simulate a 3 second task
        SystemClock.sleep(3000);
        saving = false;
        return null;
    }
}

更可取的解决方案是,

onclick(){
  btn.setEnabled(false);
  btn.setClickable(false);
  //yourwork
  myWork();
}

myWork(){
 //your tasks.
 btn.setEnabled(true);
 btn.setClickable(true);
}

由于一个环节很容易被忽略,我不得不一遍又一遍地重复这个环节

这个解决方案既快速又简洁。

基本上你只是在应用程序的基本样式中防止双击,并在点击监听器上实现标准。这就像一种魔力,在不同的观点的同时进行触摸。

<style name="AppTheme" parent="Theme.AppCompat.NoActionBar">
...
<item name="android:splitMotionEvents">false</item>
<item name="android:windowEnableSplitTouch">false</item>
</style>

如果你的应用程序使用某种手势事件,这不是正确的答案。

我的解决方案是尝试使用一个布尔变量:

public class Blocker {
    private static final int DEFAULT_BLOCK_TIME = 1000;
    private boolean mIsBlockClick;

    /**
     * Block any event occurs in 1000 millisecond to prevent spam action
     * @return false if not in block state, otherwise return true.
     */
    public boolean block(int blockInMillis) {
        if (!mIsBlockClick) {
            mIsBlockClick = true;
            new Handler().postDelayed(new Runnable() {
                @Override
                public void run() {
                    mIsBlockClick = false;
                }
            }, blockInMillis);
            return false;
        }
        return true;
    }

    public boolean block() {
        return block(DEFAULT_BLOCK_TIME);
    }
}

并使用如下:

view.setOnClickListener(new View.OnClickListener() {
            private Blocker mBlocker = new Blocker();

            @Override
            public void onClick(View v) {
                if (!mBlocker.block(block-Time-In-Millis)) {
                    // do your action   
                }
            }
        });

更新:Kotlin解决方案,使用视图扩展

fun View.safeClick(listener: View.OnClickListener, blockInMillis: Long = 500) {
    var lastClickTime: Long = 0
    this.setOnClickListener {
        if (SystemClock.elapsedRealtime() - lastClickTime < blockInMillis) return@setOnClickListener
        lastClickTime = SystemClock.elapsedRealtime()
        listener.onClick(this)
    }
}

如果你在onClick()中进行计算密集型工作,则禁用按钮或设置不可点击是不够的,因为单击事件可以在禁用按钮之前排队。我写了一个实现OnClickListener的抽象基类,你可以重写,通过忽略任何排队点击来修复这个问题:

/** 
 * This class allows a single click and prevents multiple clicks on
 * the same button in rapid succession. Setting unclickable is not enough
 * because click events may still be queued up.
 * 
 * Override onOneClick() to handle single clicks. Call reset() when you want to
 * accept another click.
 */
public abstract class OnOneOffClickListener implements OnClickListener {
    private boolean clickable = true;

    /**
     * Override onOneClick() instead.
     */
    @Override
    public final void onClick(View v) {
        if (clickable) {
            clickable = false;
            onOneClick(v);
            //reset(); // uncomment this line to reset automatically
        }
    }

    /**
     * Override this function to handle clicks.
     * reset() must be called after each click for this function to be called
     * again.
     * @param v
     */
    public abstract void onOneClick(View v);

    /**
     * Allows another click.
     */
    public void reset() {
        clickable = true;
    }
}

用法与OnClickListener相同,但重写OnOneClick()代替:

OnOneOffClickListener clickListener = new OnOneOffClickListener() {
    @Override
    public void onOneClick(View v) {

        // Do stuff

        this.reset(); // or you can reset somewhere else with clickListener.reset();
    }
};
myButton.setOnClickListener(clickListener);