在安卓系统中防止双击按钮的最佳方法是什么?


当前回答

这个解决方案(Kotlin)对我很有效:

abstract class SingleClickListener : View.OnClickListener {
    private val MIN_CLICK_INTERVAL: Long = 1000
    private var mLastClickTime: Long = 0

    abstract fun onSingleClick(v: View?)

    override fun onClick(v: View?) {
        if (mLastClickTime <= 0) {
            mLastClickTime = SystemClock.uptimeMillis()
            onSingleClick(v)
            return
        }

        if (SystemClock.uptimeMillis() - mLastClickTime <= MIN_CLICK_INTERVAL) {
            return
        }

        mLastClickTime = SystemClock.uptimeMillis()

        onSingleClick(v)
    }
}

用法:

someView.setOnClickListener(object : SingleClickListener() {
    override fun onSingleClick(v: View?) {
        v?.also { klik(it) }
    }
})

或者也可以创建扩展函数,在视图上轻松添加ClickListener:

fun View.click(klik: (View) -> Unit) {
    this.setOnClickListener(object : SingleClickListener() {
        override fun onSingleClick(v: View?) {
            v?.also { klik(it) }
        }
    })
}

// Usage
class XPerimentActivity : AppCompatActivity() {
    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.activity_xperiment_layout)

        submit_button.click {
           // do your magic
        }
    }
}

其他回答

如果点击按钮,你正在打开一个新的片段,只需添加android:clickable="true"到正在打开的新片段的根视图。

你可以用Kotlin扩展函数和RxBinding来实现它

   fun View.clickWithDebounce(debounceTime: Long = 600L, action: () -> Unit): Disposable =
        RxView.clicks(this)
                .debounce(debounceTime, TimeUnit.MILLISECONDS)
                .observeOn(AndroidSchedulers.mainThread())
                .subscribe { action() }

or

fun View.clickWithDebounce(debounceTime: Long = 600L, action: () -> Unit) {
    this.setOnClickListener(object : View.OnClickListener {
        private var lastClickTime: Long = 0

        override fun onClick(v: View) {
            if (SystemClock.elapsedRealtime() - lastClickTime < debounceTime) return
            else action()

            lastClickTime = SystemClock.elapsedRealtime()
        }
    })
}

然后就是:

View.clickWithDebounce{ Your code }

Kotlin创建类SafeClickListener

class SafeClickListener(
        private var defaultInterval: Int = 1000,
        private val onSafeCLick: (View) -> Unit
) : View.OnClickListener {
    private var lastTimeClicked: Long = 0    override fun onClick(v: View) {
        if (SystemClock.elapsedRealtime() - lastTimeClicked < defaultInterval) {
            return
        }
        lastTimeClicked = SystemClock.elapsedRealtime()
        onSafeCLick(v)
    }
}

在baseClass或else中创建一个函数

fun View.setSafeOnClickListener(onSafeClick: (View) -> Unit) {val safeClickListener = SafeClickListener {
        onSafeClick(it)
    }
    setOnClickListener(safeClickListener)
}

并使用按钮点击

btnSubmit.setSafeOnClickListener {
    showSettingsScreen()
}

我知道这是一个老问题,但我分享了我找到的解决这个常见问题的最佳方案

        btnSomeButton.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            // Prevent Two Click
            Utils.preventTwoClick(view);
            // Do magic
        }
    });

在另一个文件中,比如Utils.java

    /**
 * Método para prevenir doble click en un elemento
 * @param view
 */
public static void preventTwoClick(final View view){
    view.setEnabled(false);
    view.postDelayed(
        ()-> view.setEnabled(true),
        500
    );
}

Setting the button as clickable false upon clicking and true once it is desired to make the button clickable again is the right approach. For instance, consider the following scenario: you are making a service call upon click of a button and once the service is done you want to display a dialog. For this, once the button is clicked you can set setClickable(false) and once the service responds you will do setClicklable(true) through a reference you pass to your custom dialog. When dialog invokes isShowing() you can trigger the listener and setClicklable(true).