在安卓系统中防止双击按钮的最佳方法是什么?
当前回答
这个解决方案(Kotlin)对我很有效:
abstract class SingleClickListener : View.OnClickListener {
private val MIN_CLICK_INTERVAL: Long = 1000
private var mLastClickTime: Long = 0
abstract fun onSingleClick(v: View?)
override fun onClick(v: View?) {
if (mLastClickTime <= 0) {
mLastClickTime = SystemClock.uptimeMillis()
onSingleClick(v)
return
}
if (SystemClock.uptimeMillis() - mLastClickTime <= MIN_CLICK_INTERVAL) {
return
}
mLastClickTime = SystemClock.uptimeMillis()
onSingleClick(v)
}
}
用法:
someView.setOnClickListener(object : SingleClickListener() {
override fun onSingleClick(v: View?) {
v?.also { klik(it) }
}
})
或者也可以创建扩展函数,在视图上轻松添加ClickListener:
fun View.click(klik: (View) -> Unit) {
this.setOnClickListener(object : SingleClickListener() {
override fun onSingleClick(v: View?) {
v?.also { klik(it) }
}
})
}
// Usage
class XPerimentActivity : AppCompatActivity() {
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_xperiment_layout)
submit_button.click {
// do your magic
}
}
}
其他回答
如果点击按钮,你正在打开一个新的片段,只需添加android:clickable="true"到正在打开的新片段的根视图。
你可以用Kotlin扩展函数和RxBinding来实现它
fun View.clickWithDebounce(debounceTime: Long = 600L, action: () -> Unit): Disposable =
RxView.clicks(this)
.debounce(debounceTime, TimeUnit.MILLISECONDS)
.observeOn(AndroidSchedulers.mainThread())
.subscribe { action() }
or
fun View.clickWithDebounce(debounceTime: Long = 600L, action: () -> Unit) {
this.setOnClickListener(object : View.OnClickListener {
private var lastClickTime: Long = 0
override fun onClick(v: View) {
if (SystemClock.elapsedRealtime() - lastClickTime < debounceTime) return
else action()
lastClickTime = SystemClock.elapsedRealtime()
}
})
}
然后就是:
View.clickWithDebounce{ Your code }
Kotlin创建类SafeClickListener
class SafeClickListener(
private var defaultInterval: Int = 1000,
private val onSafeCLick: (View) -> Unit
) : View.OnClickListener {
private var lastTimeClicked: Long = 0 override fun onClick(v: View) {
if (SystemClock.elapsedRealtime() - lastTimeClicked < defaultInterval) {
return
}
lastTimeClicked = SystemClock.elapsedRealtime()
onSafeCLick(v)
}
}
在baseClass或else中创建一个函数
fun View.setSafeOnClickListener(onSafeClick: (View) -> Unit) {val safeClickListener = SafeClickListener {
onSafeClick(it)
}
setOnClickListener(safeClickListener)
}
并使用按钮点击
btnSubmit.setSafeOnClickListener {
showSettingsScreen()
}
我知道这是一个老问题,但我分享了我找到的解决这个常见问题的最佳方案
btnSomeButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
// Prevent Two Click
Utils.preventTwoClick(view);
// Do magic
}
});
在另一个文件中,比如Utils.java
/**
* Método para prevenir doble click en un elemento
* @param view
*/
public static void preventTwoClick(final View view){
view.setEnabled(false);
view.postDelayed(
()-> view.setEnabled(true),
500
);
}
Setting the button as clickable false upon clicking and true once it is desired to make the button clickable again is the right approach. For instance, consider the following scenario: you are making a service call upon click of a button and once the service is done you want to display a dialog. For this, once the button is clicked you can set setClickable(false) and once the service responds you will do setClicklable(true) through a reference you pass to your custom dialog. When dialog invokes isShowing() you can trigger the listener and setClicklable(true).
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