在安卓系统中防止双击按钮的最佳方法是什么?
当前回答
通用解决方案
@Override
public void onClick(View v) {
tempDisableButton(v);
//all the buttons view..
}
public void tempDisableButton(View viewBtn) {
final View button = viewBtn;
button.setEnabled(false);
button.postDelayed(new Runnable() {
@Override
public void run() {
button.setEnabled(true);
}
}, 3000);
}
其他回答
当UI线程阻塞时,单击事件队列。对于按钮单击事件,请尽快将其更改为后台任务,以避免单击事件在彼此后面排队。
在activity类中声明一个volatile boolean或lock:
private volatile boolean saving = false;
创建一个onClickListener按钮,通过保存和启动一个后台任务来完成工作:
saveButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
if (!saving) {
saving = true;
new SaveAsyncTask().execute();
}
}
});
创建一个内部的SaveAsyncTask类来在后台完成工作:
class SaveAsyncTask extends AsyncTask {
@Override
protected Object doInBackground(Object[] objects) {
// Do something here, simulate a 3 second task
SystemClock.sleep(3000);
saving = false;
return null;
}
}
KLEANEST Kotlin惯用方式:
class OnSingleClickListener(private val block: () -> Unit) : View.OnClickListener {
private var lastClickTime = 0L
override fun onClick(view: View) {
if (SystemClock.elapsedRealtime() - lastClickTime < 1000) {
return
}
lastClickTime = SystemClock.elapsedRealtime()
block()
}
}
fun View.setOnSingleClickListener(block: () -> Unit) {
setOnClickListener(OnSingleClickListener(block))
}
用法:
button.setOnSingleClickListener { ... }
或者加上一个控制油门的附加参数
class OnClickListenerThrottled(private val block: () -> Unit, private val wait: Long) : View.OnClickListener {
private var lastClickTime = 0L
override fun onClick(view: View) {
if (SystemClock.elapsedRealtime() - lastClickTime < wait) {
return
}
lastClickTime = SystemClock.elapsedRealtime()
block()
}
}
/**
* A throttled click listener that only invokes [block] at most once per every [wait] milliseconds.
*/
fun View.setOnClickListenerThrottled(wait: Long = 1000L, block: () -> Unit) {
setOnClickListener(OnClickListenerThrottled(block, wait))
}
Usages:
button.setOnClickListenerThrottled(2000L) { /** some action */}
or
button.setOnClickListenerThrottled { /** some action */}
我的解决方案(Kotlin):
class OnDebouncedClickListener(private val delayInMilliSeconds: Long, val action: () -> Unit) : View.OnClickListener {
var enable = true
override fun onClick(view: View?) {
if (enable) {
enable = false
view?.postDelayed(delayInMilliSeconds) { enable = true }
action()
}
}
}
fun View.setOnDebouncedClickListener(delayInMilliSeconds: Long = 500, action: () -> Unit) {
val onDebouncedClickListener = OnDebouncedClickListener(delayInMilliSeconds, action)
setOnClickListener(onDebouncedClickListener)
}
使用:
button.apply {
setOnDebouncedClickListener {
//your action on click
}
}
使用setEnabled(false)禁用按钮,直到用户可以安全地再次单击它。
The Best and simple solution i found is
1. to create a boolean and set as false (default) like
private boolean itemClicked = false;
/* for a safer side you can also declare boolean false in onCreate() also. */
and at onclick() method check
2. if(!itemClicked)
{
itemClicked = true;
// rest of your coding functionality goes here of onClick method.
}
3. last step is to set boolean false in onResume()
@override
onResume()
{
super.onResume(0);
itemClicked = false;
}
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