在安卓系统中防止双击按钮的最佳方法是什么?


当前回答

通用解决方案

@Override
        public void onClick(View v) {
            tempDisableButton(v);
            //all the buttons view..
        }

public void tempDisableButton(View viewBtn) {
        final View button = viewBtn;

        button.setEnabled(false);
        button.postDelayed(new Runnable() {
            @Override
            public void run() {
                button.setEnabled(true);
            }
        }, 3000);
    }

其他回答

当UI线程阻塞时,单击事件队列。对于按钮单击事件,请尽快将其更改为后台任务,以避免单击事件在彼此后面排队。

在activity类中声明一个volatile boolean或lock:

private volatile boolean saving = false;

创建一个onClickListener按钮,通过保存和启动一个后台任务来完成工作:

saveButton.setOnClickListener(new View.OnClickListener() {

    @Override
    public void onClick(View view) {
        if (!saving) {
            saving = true;
            new SaveAsyncTask().execute();
        }
    }
});

创建一个内部的SaveAsyncTask类来在后台完成工作:

class SaveAsyncTask extends AsyncTask {

    @Override
    protected Object doInBackground(Object[] objects) {
        // Do something here, simulate a 3 second task
        SystemClock.sleep(3000);
        saving = false;
        return null;
    }
}

KLEANEST Kotlin惯用方式:

class OnSingleClickListener(private val block: () -> Unit) : View.OnClickListener {

    private var lastClickTime = 0L

    override fun onClick(view: View) {
        if (SystemClock.elapsedRealtime() - lastClickTime < 1000) {
            return
        }
        lastClickTime = SystemClock.elapsedRealtime()

        block()
    }
}

fun View.setOnSingleClickListener(block: () -> Unit) {
    setOnClickListener(OnSingleClickListener(block))
}

用法:

button.setOnSingleClickListener { ... }

或者加上一个控制油门的附加参数

class OnClickListenerThrottled(private val block: () -> Unit, private val wait: Long) : View.OnClickListener {

    private var lastClickTime = 0L

    override fun onClick(view: View) {
        if (SystemClock.elapsedRealtime() - lastClickTime < wait) {
            return
        }
        lastClickTime = SystemClock.elapsedRealtime()

        block()
    }
}

/**
 * A throttled click listener that only invokes [block] at most once per every [wait] milliseconds.
 */
fun View.setOnClickListenerThrottled(wait: Long = 1000L, block: () -> Unit) {
    setOnClickListener(OnClickListenerThrottled(block, wait))
}

Usages:

button.setOnClickListenerThrottled(2000L) { /** some action */}
or
button.setOnClickListenerThrottled { /** some action */}

我的解决方案(Kotlin):

class OnDebouncedClickListener(private val delayInMilliSeconds: Long, val action: () -> Unit) : View.OnClickListener {
    var enable = true

    override fun onClick(view: View?) {
        if (enable) {
            enable = false
            view?.postDelayed(delayInMilliSeconds) { enable = true }
            action()
        }
    }
}

fun View.setOnDebouncedClickListener(delayInMilliSeconds: Long = 500, action: () -> Unit) {
    val onDebouncedClickListener = OnDebouncedClickListener(delayInMilliSeconds, action)
    setOnClickListener(onDebouncedClickListener)
}

使用:

button.apply {       
            setOnDebouncedClickListener {
                //your action on click
            }
        }

使用setEnabled(false)禁用按钮,直到用户可以安全地再次单击它。

The Best and simple solution i found is 
1. to create a boolean and set as false (default) like
private boolean itemClicked = false;

/* for a safer side you can also declare boolean false in onCreate() also. */
and at onclick() method check 
2. if(!itemClicked)
{
itemClicked = true;
// rest of your coding functionality goes here of onClick method.
}
3. last step is to set boolean false in onResume()
@override
onResume()
{
super.onResume(0);
itemClicked = false;
}