你实际上可以在动画块之外设置标题，只是要确保在performWithoutAnimation中调用layoutIfNeeded():

button1.setTitle("abc", forState: .Normal)
button2.setTitle("abc", forState: .Normal)
button3.setTitle("abc", forState: .Normal)
UIView.performWithoutAnimation {
    self.button1.layoutIfNeeded()
    self.button2.layoutIfNeeded()
    self.button3.layoutIfNeeded()
}

如果你有一堆按钮，考虑在超视图上调用layoutIfNeeded():

button1.setTitle("abc", forState: .Normal)
button2.setTitle("abc", forState: .Normal)
button3.setTitle("abc", forState: .Normal)
UIView.performWithoutAnimation {
    self.view.layoutIfNeeded()
}

也许生成2个动画和2个按钮是一个更好的解决方案，以避免出现动画和更改按钮文本的问题?

我创建了第二个uibutton并生成了2个动画，这个解决方案没有hickup。

    _button2.hidden = TRUE;
    _button1.hidden = FALSE;

    CGPoint startLocation = CGPointMake(_button1.center.x, button1.center.y - 70);
    CGPoint stopLocation  = CGPointMake(_button2.center.x, button2.center.y- 70);


    [UIView animateWithDuration:0.3 animations:^{ _button2.center = stopLocation;} completion:^(BOOL finished){_button2.center = stopLocation;}];
    [UIView animateWithDuration:0.3 animations:^{ _button1.center = startLocation;} completion:^(BOOL finished){_button1.center = startLocation;}];

你可以从标题标签层中删除动画:

    [[[theButton titleLabel] layer] removeAllAnimations];

结合以上的答案，可以为UIButtonTypeSystem提供以下解决方案:

if (_button.enabled)
{
    [UIView setAnimationsEnabled:NO];
    [_button setTitle:@"title" forState:UIControlStateNormal];
    [UIView setAnimationsEnabled:YES];
}
else // disabled
{
    [UIView setAnimationsEnabled:NO];
    _button.enabled = YES;
    [_button setTitle:@"title" forState:UIControlStateNormal];
    _button.enabled = NO;
    [UIView setAnimationsEnabled:YES];
}

我得到了它的工作组合的答案:

[[[button titleLabel] layer] removeAllAnimations];

    [UIView performWithoutAnimation:^{

        [button setTitle:@"Title" forState:UIControlStateNormal];

    }];

具有系统类型的UIButton在setTitle(_:for:)上有隐式动画。你可以用两种方法来解决这个问题:

设置按钮类型为自定义，从代码或接口生成器:

let button = UIButton(type: .custom)

从代码中禁用动画:

UIView.performWithoutAnimation {
    button.setTitle(title, for: .normal)
    button.layoutIfNeeded()
}