final Handler handler = new Handler(); 
Timer t = new Timer(); 
t.schedule(new TimerTask() { 
    public void run() { 
        handler.post(new Runnable() { 
            public void run() { 
                //DO SOME ACTIONS HERE , THIS ACTIONS WILL WILL EXECUTE AFTER 5 SECONDS...
            }
        }); 
    } 
}, 5000); 

请看这个演示:

import java.util.Timer;
import java.util.TimerTask;

class Test {
     public static void main( String [] args ) {
          int delay = 5000;// in ms 

          Timer timer = new Timer();

          timer.schedule( new TimerTask(){
             public void run() { 
                 System.out.println("Wait, what..:");
              }
           }, delay);

           System.out.println("Would it run?");
     }
}

如果你必须使用处理器，但你在另一个线程中，你可以使用runonuithread在UI线程中运行处理器。这将避免抛出异常请求调用loop . prepare ()

runOnUiThread(new Runnable() {
    @Override
    public void run() {
        new Handler().postDelayed(new Runnable() {
            @Override
            public void run() {
                //Do something after 1 second
            }
        }, 1000);
    }
});

看起来很乱，但这是一种方法。

下面是Kotlin的答案，你们这些懒惰的人:

Handler().postDelayed({
//doSomethingHere()
}, 1000)

final Handler handler = new Handler(); 
Timer t = new Timer(); 
t.schedule(new TimerTask() { 
    public void run() { 
        handler.post(new Runnable() { 
            public void run() { 
                //DO SOME ACTIONS HERE , THIS ACTIONS WILL WILL EXECUTE AFTER 5 SECONDS...
            }
        }); 
    } 
}, 5000); 

我更喜欢使用View.postDelayed()方法，下面是简单的代码:

mView.postDelayed(new Runnable() {
    @Override
    public void run() {
        // Do something after 1000 ms
    }
}, 1000);