你睡了一会儿,你邀请丹,你告诉丹带来一个XBox控制器。

丹邀请保罗,丹要求保罗带来一个控制者,有多少控制者被带到派对?

function sleepOver(howManyControllersToBring) {

    var numberOfDansControllers = howManyControllersToBring;

    return function danInvitedPaul(numberOfPaulsControllers) {
        var totalControllers = numberOfDansControllers + numberOfPaulsControllers;
        return totalControllers;
    }
}

var howManyControllersToBring = 1;

var inviteDan = sleepOver(howManyControllersToBring);

// The only reason Paul was invited is because Dan was invited. 
// So we set Paul's invitation = Dan's invitation.

var danInvitedPaul = inviteDan(howManyControllersToBring);

alert("There were " + danInvitedPaul + " controllers brought to the party.");

也许你应该考虑一个以对象为导向的结构而不是内部功能。

    var calculate = {
        number: 0,
        init: function (num) {
            this.number = num;
        },
        add: function (val) {
            this.number += val;
        },
        rem: function (val) {
            this.number -= val;
        }
    };

并从 calculate.number 变量中阅读结果,谁需要“返回”无论如何。

//Addition
First think about scope which defines what variable you have to access to (In Javascript);

//there are two kinds of scope
Global Scope which include variable declared outside function or curly brace

let globalVariable = "foo";

一件事要记住,一旦你宣布了一个全球变量,你可以在你的代码中的任何地方使用它,即使在功能中;

包含仅在您的代码的特定部分可用的变量的本地范围:

函数范围是当您在函数中宣布变量时,您只能在函数内访问变量。

function User(){
    let name = "foo";
    alert(name);
}
alert(name);//error

//Block scope is when you declare a variable within a block then you can  access that variable only within a block 
{
    let user = "foo";
    alert(user);
}
alert(user);
//Uncaught ReferenceError: user is not defined at.....

//A Closure

function User(fname){
    return function(lname){
        return fname + " " lname;
    }
}
let names = User("foo");
alert(names("bar"));

//When you create a function within a function you've created a closure, in our example above since the outer function is returned the inner function got access to outer function's scope

我倾向于通过好/坏的比较更好地学习,我喜欢看到工作代码跟随不工作的代码,有人可能会遇到,我把一个 jsFiddle 组合起来,它进行比较,并试图将差异推向我能找到的最简单的解释。

关闭是正确的:

console.log('CLOSURES DONE RIGHT');

var arr = [];

function createClosure(n) {
    return function () {
        return 'n = ' + n;
    }
}

for (var index = 0; index < 10; index++) {
    arr[index] = createClosure(index);
}

for (var index of arr) {
    console.log(arr[index]());
}

关闭错误:

console.log('CLOSURES DONE WRONG');

function createClosureArray() {
    var badArr = [];

    for (var index = 0; index < 10; index++) {
        badArr[index] = function () {
            return 'n = ' + index;
        };
    }
    return badArr;
}

var badArr = createClosureArray();

for (var index of badArr) {
    console.log(badArr[index]());
}

在上面的代码中,路径在创建ClosureArray()函数中移动,函数现在只会返回完成的路径,这在第一眼看起来更直观。

结果

一个关闭是内部函数在其外部函数中有变量的访问,这可能是最简单的单线解释,你可以获得关闭。

我只是将它们指向Mozilla关闭页面,这是我发现的关闭基础和实用使用的最佳,最简短和简单的解释,强烈建议任何人学习JavaScript。

而且是的,我甚至会推荐给一个6岁的人 - 如果6岁的人正在学习关闭,那么他们准备好理解文章中提供的简短和简单的解释。

能否向五岁男孩解释关闭?

我仍然认为谷歌的解释工作得很好,简要:

/*
*    When a function is defined in another function and it
*    has access to the outer function's context even after
*    the outer function returns.
*
* An important concept to learn in JavaScript.
*/

function outerFunction(someNum) {
    var someString = 'Hey!';
    var content = document.getElementById('content');
    function innerFunction() {
        content.innerHTML = someNum + ': ' + someString;
        content = null; // Internet Explorer memory leak for DOM reference
    }
    innerFunction();
}

outerFunction(1);​

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