关于merge的更多细节将帮助你使用merge over persist:

Returning a managed instance other than the original entity is a critical part of the merge process. If an entity instance with the same identifier already exists in the persistence context, the provider will overwrite its state with the state of the entity that is being merged, but the managed version that existed already must be returned to the client so that it can be used. If the provider did not update the Employee instance in the persistence context, any references to that instance will become inconsistent with the new state being merged in. When merge() is invoked on a new entity, it behaves similarly to the persist() operation. It adds the entity to the persistence context, but instead of adding the original entity instance, it creates a new copy and manages that instance instead. The copy that is created by the merge() operation is persisted as if the persist() method were invoked on it. In the presence of relationships, the merge() operation will attempt to update the managed entity to point to managed versions of the entities referenced by the detached entity. If the entity has a relationship to an object that has no persistent identity, the outcome of the merge operation is undefined. Some providers might allow the managed copy to point to the non-persistent object, whereas others might throw an exception immediately. The merge() operation can be optionally cascaded in these cases to prevent an exception from occurring. We will cover cascading of the merge() operation later in this section. If an entity being merged points to a removed entity, an IllegalArgumentException exception will be thrown. Lazy-loading relationships are a special case in the merge operation. If a lazy-loading relationship was not triggered on an entity before it became detached, that relationship will be ignored when the entity is merged. If the relationship was triggered while managed and then set to null while the entity was detached, the managed version of the entity will likewise have the relationship cleared during the merge."

以上所有信息都摘自Mike Keith和Merrick Schnicariol的“Pro JPA 2掌握Java™Persistence API”。第六章。分段分离与合并。这本书实际上是作者专门介绍JPA的第二本书。这本新书比前一本有许多新信息。我非常推荐那些将认真参与JPA的人阅读这本书。我很抱歉匿名发布了我的第一个答案。

您可能来这里寻求关于何时使用持久化和何时使用合并的建议。我认为这取决于具体情况:您需要创建新记录的可能性有多大，以及检索持久数据的难度有多大。

让我们假设您可以使用自然键/标识符。

Data needs to be persisted, but once in a while a record exists and an update is called for. In this case you could try a persist and if it throws an EntityExistsException, you look it up and combine the data: try { entityManager.persist(entity) } catch(EntityExistsException exception) { /* retrieve and merge */ } Persisted data needs to be updated, but once in a while there is no record for the data yet. In this case you look it up, and do a persist if the entity is missing: entity = entityManager.find(key); if (entity == null) { entityManager.persist(entity); } else { /* merge */ }

如果你没有自然的键/标识符，你将很难弄清楚实体是否存在，或者如何查找它。

合并也可以用两种方式处理:

如果更改通常很小，请将其应用到托管实体。 如果更改很常见，则从持久化实体以及未更改的数据复制ID。然后调用EntityManager::merge()替换旧的内容。

我在我的实体上得到了lazyLoading异常，因为我试图访问一个会话中的惰性加载集合。

我要做的是在一个单独的请求中，从会话检索实体，然后尝试访问我的jsp页面中的一个集合，这是有问题的。

为了缓解这个问题，我在控制器中更新了相同的实体，并将其传递给我的jsp，尽管我想象当我在会话中重新保存时，它也可以通过SessionScope访问，而不会抛出一个LazyLoadingException，这是示例2的修改:

以下是我行之有效的方法:

// scenario 2 MY WAY
// tran starts
e = new MyEntity();
e = em.merge(e); // re-assign to the same entity "e"

//access e from jsp and it will work dandy!!

场景X:

表:spititter(1)，表:Spittles(许多)(Spittles是与FK:spitter_id关系的所有者)

这个场景的结果是节省:喷壶和两个喷壶就像被同一个喷壶拥有一样。

        Spitter spitter=new Spitter();  
    Spittle spittle3=new Spittle();     
    spitter.setUsername("George");
    spitter.setPassword("test1234");
    spittle3.setSpittle("I love java 2");       
    spittle3.setSpitter(spitter);               
    dao.addSpittle(spittle3); // <--persist     
    Spittle spittle=new Spittle();
    spittle.setSpittle("I love java");
    spittle.setSpitter(spitter);        
    dao.saveSpittle(spittle); //<-- merge!!

场景Y:

这将拯救喷壶，将拯救2喷壶，但他们不会引用同一喷壶!

        Spitter spitter=new Spitter();  
    Spittle spittle3=new Spittle();     
    spitter.setUsername("George");
    spitter.setPassword("test1234");
    spittle3.setSpittle("I love java 2");       
    spittle3.setSpitter(spitter);               
    dao.save(spittle3); // <--merge!!       
    Spittle spittle=new Spittle();
    spittle.setSpittle("I love java");
    spittle.setSpitter(spitter);        
    dao.saveSpittle(spittle); //<-- merge!!

通过回答，有一些关于“Cascade”和id生成的细节缺失。看到问题

此外，值得一提的是，您可以为合并和持久化使用单独的Cascade注释:Cascade。合并和级联。PERSIST将根据使用的方法进行处理。

规格是你的朋友;)

我注意到，当我使用em.merge时，每个INSERT都有一个SELECT语句，即使JPA没有为我生成字段——主键字段是我自己设置的UUID。我切换到em.persist(myEntityObject)，然后只得到INSERT语句。