EntityManager.merge()可以插入新对象并更新现有对象。

为什么要使用persist()(它只能创建新对象)?


当前回答

我发现Hibernate文档中的解释很有启发性,因为它们包含了一个用例:

The usage and semantics of merge() seems to be confusing for new users. Firstly, as long as you are not trying to use object state loaded in one entity manager in another new entity manager, you should not need to use merge() at all. Some whole applications will never use this method. Usually merge() is used in the following scenario: The application loads an object in the first entity manager the object is passed up to the presentation layer some modifications are made to the object the object is passed back down to the business logic layer the application persists these modifications by calling merge() in a second entity manager Here is the exact semantic of merge(): if there is a managed instance with the same identifier currently associated with the persistence context, copy the state of the given object onto the managed instance if there is no managed instance currently associated with the persistence context, try to load it from the database, or create a new managed instance the managed instance is returned the given instance does not become associated with the persistence context, it remains detached and is usually discarded

来自:http://docs.jboss.org/hibernate/entitymanager/3.6/reference/en/html/objectstate.html

其他回答

merge和persist之间还有一些区别(我将再次列举已经在这里发布的区别):

D1。Merge不会使传递的实体受管理,而是返回另一个受管理的实例。在另一边持久化将使传递的实体被管理:

//MERGE: passedEntity remains unmanaged, but newEntity will be managed
Entity newEntity = em.merge(passedEntity);

//PERSIST: passedEntity will be managed after this
em.persist(passedEntity);

D2。如果你删除了一个实体,然后决定持久化该实体,你只能使用persist()来做,因为merge会抛出一个IllegalArgumentException。

D3。如果您决定手动处理您的id(例如通过使用uuid),则合并 operation将触发后续的SELECT查询,以查找具有该ID的存在实体,而persist可能不需要这些查询。

D4。有些情况下,您只是不相信调用您的代码的代码,为了确保没有数据被更新,而是被插入,您必须使用持久化。

持久化和合并是为了两个不同的目的(它们根本不是替代方案)。

(编辑以扩大差异信息)

坚持:

向数据库中插入一个新的寄存器 将对象附加到实体管理器。

走:

找到具有相同id的附加对象并更新它。 如果存在,则更新并返回已附加的对象。 如果不存在,则将新寄存器插入数据库。

persist()效率:

在向数据库插入新寄存器时,它可能比merge()更有效。 它不会复制原始对象。

persist()的语义:

它确保您是在插入而不是错误地更新。

例子:

{
    AnyEntity newEntity;
    AnyEntity nonAttachedEntity;
    AnyEntity attachedEntity;

    // Create a new entity and persist it        
    newEntity = new AnyEntity();
    em.persist(newEntity);

    // Save 1 to the database at next flush
    newEntity.setValue(1);

    // Create a new entity with the same Id than the persisted one.
    AnyEntity nonAttachedEntity = new AnyEntity();
    nonAttachedEntity.setId(newEntity.getId());

    // Save 2 to the database at next flush instead of 1!!!
    nonAttachedEntity.setValue(2);
    attachedEntity = em.merge(nonAttachedEntity);

    // This condition returns true
    // merge has found the already attached object (newEntity) and returns it.
    if(attachedEntity==newEntity) {
            System.out.print("They are the same object!");
    }

    // Set 3 to value
    attachedEntity.setValue(3);
    // Really, now both are the same object. Prints 3
    System.out.println(newEntity.getValue());

    // Modify the un attached object has no effect to the entity manager
    // nor to the other objects
    nonAttachedEntity.setValue(42);
}

这种方法对于实体管理器中的任何寄存器只存在一个附加对象。

对于带id的实体,Merge()是这样的:

AnyEntity myMerge(AnyEntity entityToSave) {
    AnyEntity attached = em.find(AnyEntity.class, entityToSave.getId());
    if(attached==null) {
            attached = new AnyEntity();
            em.persist(attached);
    }
    BeanUtils.copyProperties(attached, entityToSave);

    return attached;
}

虽然如果连接到MySQL merge()可以像persist()一样有效,使用一个调用INSERT和ON DUPLICATE KEY UPDATE选项,JPA是一个非常高级的编程,你不能假设这将是任何地方的情况。

我发现Hibernate文档中的解释很有启发性,因为它们包含了一个用例:

The usage and semantics of merge() seems to be confusing for new users. Firstly, as long as you are not trying to use object state loaded in one entity manager in another new entity manager, you should not need to use merge() at all. Some whole applications will never use this method. Usually merge() is used in the following scenario: The application loads an object in the first entity manager the object is passed up to the presentation layer some modifications are made to the object the object is passed back down to the business logic layer the application persists these modifications by calling merge() in a second entity manager Here is the exact semantic of merge(): if there is a managed instance with the same identifier currently associated with the persistence context, copy the state of the given object onto the managed instance if there is no managed instance currently associated with the persistence context, try to load it from the database, or create a new managed instance the managed instance is returned the given instance does not become associated with the persistence context, it remains detached and is usually discarded

来自:http://docs.jboss.org/hibernate/entitymanager/3.6/reference/en/html/objectstate.html

另一个观察:

merge()只关心自动生成的id(在IDENTITY和SEQUENCE上测试),当表中已经存在这样一个id的记录时。在这种情况下,merge()将尝试更新记录。 然而,如果一个id不存在或者不匹配任何现有的记录,merge()将完全忽略它,并要求db分配一个新的。这有时是许多bug的来源。不要使用merge()强制新记录的id。

另一方面,Persist()甚至不允许将id传递给它。它会立即失效。在我的例子中,它是:

原因:org.hibernate.PersistentObjectException:分离实体 传递到持久化

Hibernate-jpa javadoc有一个提示:

抛出:javax.persistence.EntityExistsException——如果实体 已经存在。(如果实体已经存在,则 当持久化操作时,可能会抛出EntityExistsException 或者EntityExistsException或另一个PersistenceException 可能在同花顺或提交时抛出。)

场景X:

表:spititter(1),表:Spittles(许多)(Spittles是与FK:spitter_id关系的所有者)

这个场景的结果是节省:喷壶和两个喷壶就像被同一个喷壶拥有一样。

        Spitter spitter=new Spitter();  
    Spittle spittle3=new Spittle();     
    spitter.setUsername("George");
    spitter.setPassword("test1234");
    spittle3.setSpittle("I love java 2");       
    spittle3.setSpitter(spitter);               
    dao.addSpittle(spittle3); // <--persist     
    Spittle spittle=new Spittle();
    spittle.setSpittle("I love java");
    spittle.setSpitter(spitter);        
    dao.saveSpittle(spittle); //<-- merge!!

场景Y:

这将拯救喷壶,将拯救2喷壶,但他们不会引用同一喷壶!

        Spitter spitter=new Spitter();  
    Spittle spittle3=new Spittle();     
    spitter.setUsername("George");
    spitter.setPassword("test1234");
    spittle3.setSpittle("I love java 2");       
    spittle3.setSpitter(spitter);               
    dao.save(spittle3); // <--merge!!       
    Spittle spittle=new Spittle();
    spittle.setSpittle("I love java");
    spittle.setSpitter(spitter);        
    dao.saveSpittle(spittle); //<-- merge!!