######get resize coordinate after resize the image using this function#####
def scale_img_pixel(points,original_dim,resize_dim):
        multi_list = [points]
        new_point_list = []
        multi_list_point = []
        for point in multi_list:
            multi_list_point.append([point[0],point[1]])
            multi_list_point.append([point[2],point[3]])
        for lsingle_point in multi_list_point:
            x1 = int((lsingle_point[0] * (resize_dim[0] / original_dim[0])))
            y1 = int((lsingle_point[1] * (resize_dim[1] / original_dim[1])))
            new_point_list.append(x1)
            new_point_list.append(y1)
            
        return new_point_list
    
    
    points = [774,265,909,409]
    original_dim = (1237,1036)
    resize_dim = (640,480)
    result = scale_img_pixel(points,original_dim,resize_dim)
    print("result: ", result)  

from PIL import Image

img = Image.open('/your image path/image.jpg') # image extension *.png,*.jpg
new_width  = 200
new_height = 300
img = img.resize((new_width, new_height), Image.ANTIALIAS)
img.save('output image name.png') # format may what you want *.png, *jpg, *.gif

定义最大大小。 然后，通过取min(maxwidth/width, maxheight/height)来计算调整大小的比率。

合适的尺寸是旧尺寸*比例。

当然，还有一个库方法可以做到这一点:Image.thumbnail方法。 下面是来自PIL文档的一个(编辑过的)示例。

import os, sys
import Image

size = 128, 128

for infile in sys.argv[1:]:
    outfile = os.path.splitext(infile)[0] + ".thumbnail"
    if infile != outfile:
        try:
            im = Image.open(infile)
            im.thumbnail(size, Image.Resampling.LANCZOS)
            im.save(outfile, "JPEG")
        except IOError:
            print "cannot create thumbnail for '%s'" % infile

from PIL import Image
from resizeimage import resizeimage

def resize_file(in_file, out_file, size):
    with open(in_file) as fd:
        image = resizeimage.resize_thumbnail(Image.open(fd), size)
    image.save(out_file)
    image.close()

resize_file('foo.tif', 'foo_small.jpg', (256, 256))

我使用这个库:

pip install python-resize-image

我试图为幻灯片视频调整一些图像的大小，因此，我想要的不仅仅是一个最大维度，而是一个最大宽度和最大高度(视频帧的大小)。 而且总有可能拍一个人像视频…… 图像。缩略图方法是有前途的，但我不能使它放大一个较小的图像。

所以当我在这里(或其他地方)找不到明显的方法时，我写了这个函数，并把它放在这里:

from PIL import Image

def get_resized_img(img_path, video_size):
    img = Image.open(img_path)
    width, height = video_size  # these are the MAX dimensions
    video_ratio = width / height
    img_ratio = img.size[0] / img.size[1]
    if video_ratio >= 1:  # the video is wide
        if img_ratio <= video_ratio:  # image is not wide enough
            width_new = int(height * img_ratio)
            size_new = width_new, height
        else:  # image is wider than video
            height_new = int(width / img_ratio)
            size_new = width, height_new
    else:  # the video is tall
        if img_ratio >= video_ratio:  # image is not tall enough
            height_new = int(width / img_ratio)
            size_new = width, height_new
        else:  # image is taller than video
            width_new = int(height * img_ratio)
            size_new = width_new, height
    return img.resize(size_new, resample=Image.LANCZOS)

如果你试图保持相同的纵横比，那么你不会调整原始大小的一些百分比吗?

例如，原来大小的一半

half = 0.5
out = im.resize( [int(half * s) for s in im.size] )