当我将xCode版本升级到7.4 beta时，它停止在“swap(&self[i]， &self[j])”。 致命错误:不支持与自身交换位置

我找到了I = j的原因(交换函数将爆炸)

所以我添加了一个条件，如下所示

if (i != j){
    swap(&list[i], &list[j])
}

丫!对我来说没问题。

这个答案详细介绍了如何在Swift 4.2+中使用快速和统一的算法(Fisher-Yates)进行洗牌，以及如何在之前的各种Swift版本中添加相同的功能。每个Swift版本的命名和行为都与该版本的突变和非突变排序方法相匹配。

Swift 4 + 2。

shuffle和shuffle是原生开始Swift 4.2。使用示例:

let x = [1, 2, 3].shuffled()
// x == [2, 3, 1]

let fiveStrings = stride(from: 0, through: 100, by: 5).map(String.init).shuffled()
// fiveStrings == ["20", "45", "70", "30", ...]

var numbers = [1, 2, 3, 4]
numbers.shuffle()
// numbers == [3, 2, 1, 4]

Swift 4.0和4.1

这些扩展将一个shuffle()方法添加到任何可变集合(数组和不安全的可变缓冲区)，并将一个shuffled()方法添加到任何序列:

extension MutableCollection {
    /// Shuffles the contents of this collection.
    mutating func shuffle() {
        let c = count
        guard c > 1 else { return }

        for (firstUnshuffled, unshuffledCount) in zip(indices, stride(from: c, to: 1, by: -1)) {
            // Change `Int` in the next line to `IndexDistance` in < Swift 4.1
            let d: Int = numericCast(arc4random_uniform(numericCast(unshuffledCount)))
            let i = index(firstUnshuffled, offsetBy: d)
            swapAt(firstUnshuffled, i)
        }
    }
}

extension Sequence {
    /// Returns an array with the contents of this sequence, shuffled.
    func shuffled() -> [Element] {
        var result = Array(self)
        result.shuffle()
        return result
    }
}

用法与上述Swift 4.2示例相同。

---

斯威夫特3

这些扩展将一个shuffle()方法添加到任何可变集合，并将一个shuffled()方法添加到任何序列:

extension MutableCollection where Indices.Iterator.Element == Index {
    /// Shuffles the contents of this collection.
    mutating func shuffle() {
        let c = count
        guard c > 1 else { return }

        for (firstUnshuffled , unshuffledCount) in zip(indices, stride(from: c, to: 1, by: -1)) {
            // Change `Int` in the next line to `IndexDistance` in < Swift 3.2
            let d: Int = numericCast(arc4random_uniform(numericCast(unshuffledCount)))
            guard d != 0 else { continue }
            let i = index(firstUnshuffled, offsetBy: d)
            self.swapAt(firstUnshuffled, i)
        }
    }
}

extension Sequence {
    /// Returns an array with the contents of this sequence, shuffled.
    func shuffled() -> [Iterator.Element] {
        var result = Array(self)
        result.shuffle()
        return result
    }
}

用法与上述Swift 4.2示例相同。

---

斯威夫特2

(过时的语言:你不能使用Swift 2。x将于2018年7月在iTunes Connect上发布)

extension MutableCollectionType where Index == Int {
    /// Shuffle the elements of `self` in-place.
    mutating func shuffleInPlace() {
        // empty and single-element collections don't shuffle
        if count < 2 { return }

        for i in startIndex ..< endIndex - 1 {
            let j = Int(arc4random_uniform(UInt32(count - i))) + i
            guard i != j else { continue }
            swap(&self[i], &self[j])
        }
    }
}

extension CollectionType {
    /// Return a copy of `self` with its elements shuffled.
    func shuffle() -> [Generator.Element] {
        var list = Array(self)
        list.shuffleInPlace()
        return list
    }
}

用法:

[1, 2, 3].shuffle()
// [2, 3, 1]

let fiveStrings = 0.stride(through: 100, by: 5).map(String.init).shuffle()
// ["20", "45", "70", "30", ...]

var numbers = [1, 2, 3, 4]
numbers.shuffleInPlace()
// [3, 2, 1, 4]

---

斯威夫特1.2

(过时的语言:你不能使用Swift 1。x将于2018年7月在iTunes Connect上发布)

Shuffle是一种可变数组方法

这个扩展将让你洗牌可变数组实例的地方:

extension Array {
    mutating func shuffle() {
        if count < 2 { return }
        for i in 0..<(count - 1) {
            let j = Int(arc4random_uniform(UInt32(count - i))) + i
            swap(&self[i], &self[j])
        }
    }
}
var numbers = [1, 2, 3, 4, 5, 6, 7, 8]
numbers.shuffle()                     // e.g., numbers == [6, 1, 8, 3, 2, 4, 7, 5]

shuffle是一种非突变数组方法

这个扩展可以让你检索一个数组实例的打乱副本:

extension Array {
    func shuffled() -> [T] {
        if count < 2 { return self }
        var list = self
        for i in 0..<(list.count - 1) {
            let j = Int(arc4random_uniform(UInt32(list.count - i))) + i
            swap(&list[i], &list[j])
        }
        return list
    }
}
let numbers = [1, 2, 3, 4, 5, 6, 7, 8]
let mixedup = numbers.shuffled()     // e.g., mixedup == [6, 1, 8, 3, 2, 4, 7, 5]

这是一些在playground上运行的代码。你不需要在实际的Xcode项目中导入Darwin。

import darwin

var a = [1,2,3,4,5,6,7]

func shuffle<ItemType>(item1: ItemType, item2: ItemType) -> Bool {
    return drand48() > 0.5
}

sort(a, shuffle)

println(a)

在Swift 4.2中，现在有一个可变shuffle和不可变shuffle的方法。你可以在这里阅读更多关于随机生成和数组的东西。

这里有一些可能更短的内容:

sorted(a) {_, _ in arc4random() % 2 == 0}

斯威夫特4 在for循环中洗牌数组的元素，其中i是混合比例

var cards = [Int]() //Some Array
let i = 4 // is the mixing ratio
func shuffleCards() {
    for _ in 0 ..< cards.count * i {
        let card = cards.remove(at: Int(arc4random_uniform(UInt32(cards.count))))
        cards.insert(card, at: Int(arc4random_uniform(UInt32(cards.count))))
    }
}

或者扩展为Int

func shuffleCards() {
    for _ in 0 ..< cards.count * i {
        let card = cards.remove(at: cards.count.arc4random)
        cards.insert(card, at: cards.count.arc4random)
    }
}
extension Int {
    var arc4random: Int {
        if self > 0 {
            print("Arc for random positiv self \(Int(arc4random_uniform(UInt32(self))))")
        return Int(arc4random_uniform(UInt32(self)))
        } else if self < 0 {
            print("Arc for random negotiv self \(-Int(arc4random_uniform(UInt32(abs(self)))))")
            return -Int(arc4random_uniform(UInt32(abs(self))))
        } else {
            print("Arc for random equal 0")
            return 0
        }
    }
}