.shuffle()和.shuffled()是Swift的一部分


原历史问题:

我如何随机或洗牌在Swift数组中的元素?例如,如果我的数组包含52张扑克牌,我想要洗牌数组以洗牌牌组。


当前回答

Swift 3解决方案,遵循@Nate Cook的回答:(如果索引从0开始,请参阅下面的评论)

extension Collection {
    /// Return a copy of `self` with its elements shuffled
    func shuffle() -> [Generator.Element] {
        var list = Array(self)
        list.shuffleInPlace()
        return list
    } }

extension MutableCollection where Index == Int {
    /// Shuffle the elements of `self` in-place.
    mutating func shuffleInPlace() {
        // empty and single-element collections don't shuffle
        if count < 2 { return }
        let countInt = count as! Int

    for i in 0..<countInt - 1 {
        let j = Int(arc4random_uniform(UInt32(countInt - i))) + i
            guard i != j else { continue }
            swap(&self[i], &self[j])
        }
    }
}

其他回答

以Nate的算法为例,我想看看Swift 2和协议扩展会是什么样子。

这是我想到的。

extension MutableCollectionType where Self.Index == Int {
    mutating func shuffleInPlace() {
        let c = self.count
        for i in 0..<(c - 1) {
            let j = Int(arc4random_uniform(UInt32(c - i))) + i
            swap(&self[i], &self[j])
        }
    }
}

extension MutableCollectionType where Self.Index == Int {
    func shuffle() -> Self {
        var r = self
        let c = self.count
        for i in 0..<(c - 1) {
            let j = Int(arc4random_uniform(UInt32(c - i))) + i
            swap(&r[i], &r[j])
        }
        return r
    }
}

现在,任何MutableCollectionType都可以使用这些方法,因为它使用Int作为索引

简单的例子:

extension Array {
    mutating func shuffled() {
        for _ in self {
            // generate random indexes that will be swapped
            var (a, b) = (Int(arc4random_uniform(UInt32(self.count - 1))), Int(arc4random_uniform(UInt32(self.count - 1))))
            if a == b { // if the same indexes are generated swap the first and last
                a = 0
                b = self.count - 1
            }
            swap(&self[a], &self[b])
        }
    }
}

var array = [1,2,3,4,5,6,7,8,9,10]
array.shuffled()
print(array) // [9, 8, 3, 5, 7, 6, 4, 2, 1, 10]

SWIFT 4

func createShuffledSequenceOfNumbers(max:UInt)->[UInt] {

    var array:[UInt]! = []
    var myArray:[UInt]! = []
    for i in 1...max {
        myArray.append(i)
    }
    for i in 1...max {
        array.append(i)
    }
    var tempArray:[Int]! = []
    for index in 0...(myArray.count - 1) {

        var isNotFinded:Bool = true
        while(isNotFinded){

            let randomNumber = arc4random_uniform(UInt32(myArray.count))
            let randomIndex = Int(randomNumber)

            if(!tempArray.contains(randomIndex)){
                tempArray.append(randomIndex)

                array[randomIndex] = myArray[index]
                isNotFinded = false
            }
        }
    }

    return array
}

这是最简单的方法。导入Gamplaykit到你的VC中,使用下面的代码。在Xcode 8中测试。

 import GameplayKit

 let array: NSArray = ["Jock", "Ellie", "Sue Ellen", "Bobby", "JR", "Pamela"]

 override func viewDidLoad() {
    super.viewDidLoad()

    print(array.shuffled())  
}

如果你想从数组中获得一个打乱的字符串,你可以使用下面的代码..

func suffleString() {

    let ShuffleArray = array.shuffled()

    suffleString.text = ShuffleArray.first as? String

    print(suffleString.text!)

}

Swift 3解决方案,遵循@Nate Cook的回答:(如果索引从0开始,请参阅下面的评论)

extension Collection {
    /// Return a copy of `self` with its elements shuffled
    func shuffle() -> [Generator.Element] {
        var list = Array(self)
        list.shuffleInPlace()
        return list
    } }

extension MutableCollection where Index == Int {
    /// Shuffle the elements of `self` in-place.
    mutating func shuffleInPlace() {
        // empty and single-element collections don't shuffle
        if count < 2 { return }
        let countInt = count as! Int

    for i in 0..<countInt - 1 {
        let j = Int(arc4random_uniform(UInt32(countInt - i))) + i
            guard i != j else { continue }
            swap(&self[i], &self[j])
        }
    }
}