这是我所使用的:

import GameplayKit

extension Collection {
    func shuffled() -> [Iterator.Element] {
        let shuffledArray = (self as? NSArray)?.shuffled()
        let outputArray = shuffledArray as? [Iterator.Element]
        return outputArray ?? []
    }
    mutating func shuffle() {
        if let selfShuffled = self.shuffled() as? Self {
            self = selfShuffled
        }
    }
}

// Usage example:

var numbers = [1,2,3,4,5]
numbers.shuffle()

print(numbers) // output example: [2, 3, 5, 4, 1]

print([10, "hi", 9.0].shuffled()) // output example: [hi, 10, 9]

工作阵列扩展(突变和非突变)

Swift 4.1 / Xcode 9

上面的答案已弃用，所以我自己创建了自己的扩展，在Swift的最新版本Swift 4.1 (Xcode 9)中洗牌数组:

extension Array {

// Non-mutating shuffle
    var shuffled : Array {
        let totalCount : Int = self.count
        var shuffledArray : Array = []
        var count : Int = totalCount
        var tempArray : Array = self
        for _ in 0..<totalCount {
            let randomIndex : Int = Int(arc4random_uniform(UInt32(count)))
            let randomElement : Element = tempArray.remove(at: randomIndex)
            shuffledArray.append(randomElement)
            count -= 1
        }
        return shuffledArray
    }

// Mutating shuffle
    mutating func shuffle() {
        let totalCount : Int = self.count
        var shuffledArray : Array = []
        var count : Int = totalCount
        var tempArray : Array = self
        for _ in 0..<totalCount {
            let randomIndex : Int = Int(arc4random_uniform(UInt32(count)))
            let randomElement : Element = tempArray.remove(at: randomIndex)
            shuffledArray.append(randomElement)
            count -= 1
        }
        self = shuffledArray
    }
}

调用非突变Shuffle [Array] -> [Array]:

let array = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

print(array.shuffled)

这将以随机顺序打印数组。

调用Shuffle [Array] = [Array]:

var array = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

array.shuffle() 
// The array has now been mutated and contains all of its initial 
// values, but in a randomized shuffled order

print(array) 

这将打印数组的当前顺序，该顺序已经被随机打乱。

希望这对每个人都有用，如果你有任何问题，建议或评论，请随时提问!

以Nate的算法为例，我想看看Swift 2和协议扩展会是什么样子。

这是我想到的。

extension MutableCollectionType where Self.Index == Int {
    mutating func shuffleInPlace() {
        let c = self.count
        for i in 0..<(c - 1) {
            let j = Int(arc4random_uniform(UInt32(c - i))) + i
            swap(&self[i], &self[j])
        }
    }
}

extension MutableCollectionType where Self.Index == Int {
    func shuffle() -> Self {
        var r = self
        let c = self.count
        for i in 0..<(c - 1) {
            let j = Int(arc4random_uniform(UInt32(c - i))) + i
            swap(&r[i], &r[j])
        }
        return r
    }
}

现在，任何MutableCollectionType都可以使用这些方法，因为它使用Int作为索引

SWIFT 4

func createShuffledSequenceOfNumbers(max:UInt)->[UInt] {

    var array:[UInt]! = []
    var myArray:[UInt]! = []
    for i in 1...max {
        myArray.append(i)
    }
    for i in 1...max {
        array.append(i)
    }
    var tempArray:[Int]! = []
    for index in 0...(myArray.count - 1) {

        var isNotFinded:Bool = true
        while(isNotFinded){

            let randomNumber = arc4random_uniform(UInt32(myArray.count))
            let randomIndex = Int(randomNumber)

            if(!tempArray.contains(randomIndex)){
                tempArray.append(randomIndex)

                array[randomIndex] = myArray[index]
                isNotFinded = false
            }
        }
    }

    return array
}

你也可以使用通用交换函数，实现前面提到的Fisher-Yates:

for idx in 0..<arr.count {
  let rnd = Int(arc4random_uniform(UInt32(idx)))
  if rnd != idx {
    swap(&arr[idx], &arr[rnd])
  }
}

或者更简洁:

for idx in 0..<steps.count {
  swap(&steps[idx], &steps[Int(arc4random_uniform(UInt32(idx)))])
}

在Swift 2.0中，GameplayKit可能会来拯救你!(iOS9或更高版本支持)

import GameplayKit

func shuffle() {
    array = GKRandomSource.sharedRandom().arrayByShufflingObjectsInArray(array)
}