我想提供一个ES6解决方案…这是一个单向的diff，意味着它将返回来自o2的键/值，这些键/值与o1中的对应键/值不相同:

let o1 = {
  one: 1,
  two: 2,
  three: 3
}

let o2 = {
  two: 2,
  three: 3,
  four: 4
}

let diff = Object.keys(o2).reduce((diff, key) => {
  if (o1[key] === o2[key]) return diff
  return {
    ...diff,
    [key]: o2[key]
  }
}, {})

下面是@sbgoran代码的typescript版本

export class deepDiffMapper {

  static VALUE_CREATED = 'created';
  static VALUE_UPDATED = 'updated';
  static VALUE_DELETED = 'deleted';
  static VALUE_UNCHANGED ='unchanged';

  protected isFunction(obj: object) {
    return {}.toString.apply(obj) === '[object Function]';
  };

  protected isArray(obj: object) {
      return {}.toString.apply(obj) === '[object Array]';
  };

  protected isObject(obj: object) {
      return {}.toString.apply(obj) === '[object Object]';
  };

  protected isDate(obj: object) {
      return {}.toString.apply(obj) === '[object Date]';
  };

  protected isValue(obj: object) {
      return !this.isObject(obj) && !this.isArray(obj);
  };

  protected compareValues (value1: any, value2: any) {
    if (value1 === value2) {
        return deepDiffMapper.VALUE_UNCHANGED;
    }
    if (this.isDate(value1) && this.isDate(value2) && value1.getTime() === value2.getTime()) {
        return deepDiffMapper.VALUE_UNCHANGED;
    }
    if ('undefined' == typeof(value1)) {
        return deepDiffMapper.VALUE_CREATED;
    }
    if ('undefined' == typeof(value2)) {
        return deepDiffMapper.VALUE_DELETED;
    }

    return deepDiffMapper.VALUE_UPDATED;
  }

  public map(obj1: object, obj2: object) {
      if (this.isFunction(obj1) || this.isFunction(obj2)) {
          throw 'Invalid argument. Function given, object expected.';
      }
      if (this.isValue(obj1) || this.isValue(obj2)) {
          return {
              type: this.compareValues(obj1, obj2),
              data: (obj1 === undefined) ? obj2 : obj1
          };
      }

      var diff = {};
      for (var key in obj1) {
          if (this.isFunction(obj1[key])) {
              continue;
          }

          var value2 = undefined;
          if ('undefined' != typeof(obj2[key])) {
              value2 = obj2[key];
          }

          diff[key] = this.map(obj1[key], value2);
      }
      for (var key in obj2) {
          if (this.isFunction(obj2[key]) || ('undefined' != typeof(diff[key]))) {
              continue;
          }

          diff[key] = this.map(undefined, obj2[key]);
      }

      return diff;

  }
}

我已经使用这段代码来完成你所描述的任务:

function mergeRecursive(obj1, obj2) {
    for (var p in obj2) {
        try {
            if(obj2[p].constructor == Object) {
                obj1[p] = mergeRecursive(obj1[p], obj2[p]);
            }
            // Property in destination object set; update its value.
            else if (Ext.isArray(obj2[p])) {
                // obj1[p] = [];
                if (obj2[p].length < 1) {
                    obj1[p] = obj2[p];
                }
                else {
                    obj1[p] = mergeRecursive(obj1[p], obj2[p]);
                }

            }else{
                obj1[p] = obj2[p];
            }
        } catch (e) {
            // Property in destination object not set; create it and set its value.
            obj1[p] = obj2[p];
        }
    }
    return obj1;
}

这将为您提供一个新对象，该对象将合并窗体中的旧对象和新对象之间的所有更改

如今，有相当多的模块可用于此。我最近写了一个模块来做到这一点，因为我不满意我发现的大量不同的模块。它被称为odiff: https://github.com/Tixit/odiff。我还列出了一些最流行的模块，以及为什么它们不能在odiff的自述中被接受，如果odiff没有你想要的属性，你可以查看一下。这里有一个例子:

var a = [{a:1,b:2,c:3},              {x:1,y: 2, z:3},              {w:9,q:8,r:7}]
var b = [{a:1,b:2,c:3},{t:4,y:5,u:6},{x:1,y:'3',z:3},{t:9,y:9,u:9},{w:9,q:8,r:7}]

var diffs = odiff(a,b)

/* diffs now contains:
[{type: 'add', path:[], index: 2, vals: [{t:9,y:9,u:9}]},
 {type: 'set', path:[1,'y'], val: '3'},
 {type: 'add', path:[], index: 1, vals: [{t:4,y:5,u:6}]}
]
*/

const diff = require("deep-object-diff").diff;
let differences = diff(obj2, obj1);

有一个每周下载量超过50万的npm模块:https://www.npmjs.com/package/deep-object-diff

我喜欢对象式的差异表示-特别是当它形成时，很容易看到结构。

const diff = require("deep-object-diff").diff;

const lhs = {
  foo: {
    bar: {
      a: ['a', 'b'],
      b: 2,
      c: ['x', 'y'],
      e: 100 // deleted
    }
  },
  buzz: 'world'
};

const rhs = {
  foo: {
    bar: {
      a: ['a'], // index 1 ('b')  deleted
      b: 2, // unchanged
      c: ['x', 'y', 'z'], // 'z' added
      d: 'Hello, world!' // added
    }
  },
  buzz: 'fizz' // updated
};

console.log(diff(lhs, rhs)); // =>
/*
{
  foo: {
    bar: {
      a: {
        '1': undefined
      },
      c: {
        '2': 'z'
      },
      d: 'Hello, world!',
      e: undefined
    }
  },
  buzz: 'fizz'
}
*/

2022年更新:

我想出了一个非常简单的算法来解决大多数边缘情况:

使物体变平 简单地比较两个扁平对象并创建一个扁平的diff对象 平展diff对象

如果你保存了被压平的物体，你就可以重复使用它，并在你真正需要的时候进行“反压平…”

let oldObject = {var1:'value1', var2:{ var1:'value1', var2:'value2'},var3:'value3'};
let newObject = {var2:{ var1:'value11', var3:'value3'},var3:'value3'};

let flatOldObject = flattenObject(oldObject)
/*
{
 'var1':'value1',
 'var2.var1':'value1',
 'var2.var2':'value2',
 'var3':'value3' 
}
*/
let flatNewObject = flattenObject(newObject)
/*
{
 'var2.var1':'value11',
 'var2.var3':'value3',
 'var3':'value3'
}
*/
let flatDiff = diffFlatten(flatOldObject, flatNewObject)
let [updated,removed] = flatDiff
/*
updated = {
 'var2.var1':'value11',
 'var2.var3':'value3'
}
removed = {
'var1':'value1'
}
*/

当然，您可以为这些步骤提供您的实现。但我的想法是:

实现

function flattenObject(obj) {
 const object = Object.create(null);
 const path = [];
 const isObject = (value) => Object(value) === value;

 function dig(obj) {
  for (let [key, value] of Object.entries(obj)) {
    path.push(key);
    if (isObject(value)) dig(value);
    else object[path.join('.')] = value;
    path.pop();
  }
 }

 dig(obj);
 return object;
}

function diffFlatten(oldFlat, newFlat) {
    const updated = Object.assign({}, oldFlat);
    const removed = Object.assign({}, newFlat);

    /**delete the unUpdated keys*/
    for (let key in newFlat) {
        if (newFlat[key] === oldFlat[key]) {
             delete updated[key];
             delete removed[key];
        }
    }

    return [updated, removed];

}

function unflatenObject(flattenObject) {
    const unFlatten = Object.create(null);
    for (let [stringKeys, value] of Object.entries(flattenObject)) {
        let chain = stringKeys.split('.')
        let object = unFlatten

        for (let [i, key] of chain.slice(0, -1).entries()) {
            if (!object[key]) {
                let needArray = Number.isInteger(Number(chain[+i + 1]))
                object[key] = needArray ? [] : Object.create(null)
            }
            object = object[key];
        }
        let lastkey = chain.pop();
        object[lastkey] = value;
    }
    return unFlatten;
}