下面是一个JavaScript库，可以用来查找两个JavaScript对象之间的差异:

Github URL: https://github.com/cosmicanant/recursive-diff

npm捷的url:北京方位www.npmjs.犯下/ recursiff

递归-diff库可以在浏览器中使用，也可以在基于Node.js的服务器端应用程序中使用。对于浏览器，它可以使用如下:

<script type="text" src="https://unpkg.com/recursive-diff@latest/dist/recursive-diff.min.js"/>
<script type="text/javascript">
     const ob1 = {a:1, b: [2,3]};
     const ob2 = {a:2, b: [3,3,1]};
     const delta = recursiveDiff.getDiff(ob1,ob2); 
     /* console.log(delta) will dump following data 
     [
         {path: ['a'], op: 'update', val: 2}
         {path: ['b', '0'], op: 'update',val: 3},
         {path: ['b',2], op: 'add', val: 1 },
     ]
      */
     const ob3 = recursiveDiff.applyDiff(ob1, delta); //expect ob3 is deep equal to ob2
 </script>

而在一个基于node.js的应用程序中，它可以这样使用:

const diff = require('recursive-diff');
const ob1 = {a: 1}, ob2: {b:2};
const diff = diff.getDiff(ob1, ob2);

我已经为我的一个项目写了一个函数，它将对象作为用户选项与其内部克隆进行比较。 它还可以验证，甚至替换默认值，如果用户输入坏类型的数据或删除，在纯javascript。

在IE8中100%有效。测试成功。

//  ObjectKey: ["DataType, DefaultValue"]
reference = { 
    a : ["string", 'Defaul value for "a"'],
    b : ["number", 300],
    c : ["boolean", true],
    d : {
        da : ["boolean", true],
        db : ["string", 'Defaul value for "db"'],
        dc : {
            dca : ["number", 200],
            dcb : ["string", 'Default value for "dcb"'],
            dcc : ["number", 500],
            dcd : ["boolean", true]
      },
      dce : ["string", 'Default value for "dce"'],
    },
    e : ["number", 200],
    f : ["boolean", 0],
    g : ["", 'This is an internal extra parameter']
};

userOptions = { 
    a : 999, //Only string allowed
  //b : ["number", 400], //User missed this parameter
    c: "Hi", //Only lower case or case insitive in quotes true/false allowed.
    d : {
        da : false,
        db : "HelloWorld",
        dc : {
            dca : 10,
            dcb : "My String", //Space is not allowed for ID attr
            dcc: "3thString", //Should not start with numbers
            dcd : false
      },
      dce: "ANOTHER STRING",
    },
    e: 40,
    f: true,
};


function compare(ref, obj) {

    var validation = {
        number: function (defaultValue, userValue) {
          if(/^[0-9]+$/.test(userValue))
            return userValue;
          else return defaultValue;
        },
        string: function (defaultValue, userValue) {
          if(/^[a-z][a-z0-9-_.:]{1,51}[^-_.:]$/i.test(userValue)) //This Regex is validating HTML tag "ID" attributes
            return userValue;
          else return defaultValue;
        },
        boolean: function (defaultValue, userValue) {
          if (typeof userValue === 'boolean')
            return userValue;
          else return defaultValue;
        }
    };

    for (var key in ref)
        if (obj[key] && obj[key].constructor && obj[key].constructor === Object)
          ref[key] = compare(ref[key], obj[key]);
        else if(obj.hasOwnProperty(key))
          ref[key] = validation[ref[key][0]](ref[key][1], obj[key]); //or without validation on user enties => ref[key] = obj[key]
        else ref[key] = ref[key][1];
    return ref;
}

//console.log(
    alert(JSON.stringify( compare(reference, userOptions),null,2 ))
//);

/ *结果

{
  "a": "Defaul value for \"a\"",
  "b": 300,
  "c": true,
  "d": {
    "da": false,
    "db": "Defaul value for \"db\"",
    "dc": {
      "dca": 10,
      "dcb": "Default value for \"dcb\"",
      "dcc": 500,
      "dcd": false
    },
    "dce": "Default value for \"dce\""
  },
  "e": 40,
  "f": true,
  "g": "This is an internal extra parameter"
}

*/

我想提供一个ES6解决方案…这是一个单向的diff，意味着它将返回来自o2的键/值，这些键/值与o1中的对应键/值不相同:

let o1 = {
  one: 1,
  two: 2,
  three: 3
}

let o2 = {
  two: 2,
  three: 3,
  four: 4
}

let diff = Object.keys(o2).reduce((diff, key) => {
  if (o1[key] === o2[key]) return diff
  return {
    ...diff,
    [key]: o2[key]
  }
}, {})

下面是一个JavaScript库，可以用来查找两个JavaScript对象之间的差异:

Github URL: https://github.com/cosmicanant/recursive-diff

npm捷的url:北京方位www.npmjs.犯下/ recursiff

递归-diff库可以在浏览器中使用，也可以在基于Node.js的服务器端应用程序中使用。对于浏览器，它可以使用如下:

<script type="text" src="https://unpkg.com/recursive-diff@latest/dist/recursive-diff.min.js"/>
<script type="text/javascript">
     const ob1 = {a:1, b: [2,3]};
     const ob2 = {a:2, b: [3,3,1]};
     const delta = recursiveDiff.getDiff(ob1,ob2); 
     /* console.log(delta) will dump following data 
     [
         {path: ['a'], op: 'update', val: 2}
         {path: ['b', '0'], op: 'update',val: 3},
         {path: ['b',2], op: 'add', val: 1 },
     ]
      */
     const ob3 = recursiveDiff.applyDiff(ob1, delta); //expect ob3 is deep equal to ob2
 </script>

而在一个基于node.js的应用程序中，它可以这样使用:

const diff = require('recursive-diff');
const ob1 = {a: 1}, ob2: {b:2};
const diff = diff.getDiff(ob1, ob2);

我为我自己的用例(es5环境)编写了这个，认为这可能对某些人有用，所以它是:

function deepCompare(obj1, obj2) {
    var diffObj = Array.isArray(obj2) ? [] : {}
    Object.getOwnPropertyNames(obj2).forEach(function(prop) {
        if (typeof obj2[prop] === 'object') {
            diffObj[prop] = deepCompare(obj1[prop], obj2[prop])
            // if it's an array with only length property => empty array => delete
            // or if it's an object with no own properties => delete
            if (Array.isArray(diffObj[prop]) && Object.getOwnPropertyNames(diffObj[prop]).length === 1 || Object.getOwnPropertyNames(diffObj[prop]).length === 0) {
                delete diffObj[prop]
            }
        } else if(obj1[prop] !== obj2[prop]) {
            diffObj[prop] = obj2[prop]
        }
    });
    return diffObj
}

这可能不是很有效，但是会根据第二个Obj输出一个只有不同道具的对象。

使用Lodash:

_。合并(oldObj, newObj, function (objectValue, sourceValue, key, object, source) { 如果(!)(_。isEqual(objectValue, sourceValue)) && (Object(objectValue) ! console.log(key + "\n Expected: " + sourceValue + "\n Actual: " + objectValue); } });

我不使用key/object/source，但我把它留在那里，如果你需要访问它们。 对象比较只是防止控制台将最外层元素与最内部元素之间的差异打印到控制台。

您可以在内部添加一些逻辑来处理数组。也许先对数组排序。这是一个非常灵活的解决方案。

EDIT

由_更改。合并到_。mergeWith由于lodash更新。感谢Aviron注意到这个变化。