骆驼案变蛇案

import re

name = 'CamelCaseName'
name = re.sub(r'(?<!^)(?=[A-Z])', '_', name).lower()
print(name)  # camel_case_name

如果你这样做了很多次，上面的速度很慢，提前编译正则表达式:

pattern = re.compile(r'(?<!^)(?=[A-Z])')
name = pattern.sub('_', name).lower()

为了处理更高级的情况(这是不可逆的了):

def camel_to_snake(name):
    name = re.sub('(.)([A-Z][a-z]+)', r'\1_\2', name)
    return re.sub('([a-z0-9])([A-Z])', r'\1_\2', name).lower()

print(camel_to_snake('camel2_camel2_case'))  # camel2_camel2_case
print(camel_to_snake('getHTTPResponseCode'))  # get_http_response_code
print(camel_to_snake('HTTPResponseCodeXYZ'))  # http_response_code_xyz

添加带有两个或两个以上下划线的also大小写:

def to_snake_case(name):
    name = re.sub('(.)([A-Z][a-z]+)', r'\1_\2', name)
    name = re.sub('__([A-Z])', r'_\1', name)
    name = re.sub('([a-z0-9])([A-Z])', r'\1_\2', name)
    return name.lower()

斯内克案转帕斯卡案

name = 'snake_case_name'
name = ''.join(word.title() for word in name.split('_'))
print(name)  # SnakeCaseName

在标准库中没有，但我发现这个模块似乎包含您需要的功能。

避免使用库和正则表达式:

def camel_to_snake(s):
    return ''.join(['_'+c.lower() if c.isupper() else c for c in s]).lstrip('_')

>>> camel_to_snake('ThisIsMyString')
'this_is_my_string'

为了好玩:

>>> def un_camel(input):
...     output = [input[0].lower()]
...     for c in input[1:]:
...             if c in ('ABCDEFGHIJKLMNOPQRSTUVWXYZ'):
...                     output.append('_')
...                     output.append(c.lower())
...             else:
...                     output.append(c)
...     return str.join('', output)
...
>>> un_camel("camel_case")
'camel_case'
>>> un_camel("CamelCase")
'camel_case'

或者，更有趣的是:

>>> un_camel = lambda i: i[0].lower() + str.join('', ("_" + c.lower() if c in "ABCDEFGHIJKLMNOPQRSTUVWXYZ" else c for c in i[1:]))
>>> un_camel("camel_case")
'camel_case'
>>> un_camel("CamelCase")
'camel_case'

如果你使用谷歌的(几乎)确定性骆驼案例算法，那么就不需要处理像HTMLDocument这样的东西，因为它应该是HTMLDocument，那么这种基于正则表达式的方法很简单。它用下划线替换所有的大写字母或数字。Note不处理多位数数字。

import re

def to_snake_case(camel_str):
    return re.sub('([A-Z0-9])', r'_\1', camel_str).lower().lstrip('_')

使用正则表达式可能是最短的，但这个解决方案更具可读性:

def to_snake_case(s):
    snake = "".join(["_"+c.lower() if c.isupper() else c for c in s])
    return snake[1:] if snake.startswith("_") else snake