如何循环遍历JavaScript对象中的所有成员，包括作为对象的值？
例如，我如何循环（分别访问“your_name”和“your_message”）？
var validation_messages = {
"key_1": {
"your_name": "jimmy",
"your_msg": "hello world"
},
"key_2": {
"your_name": "billy",
"your_msg": "foo equals bar"
}
}
当前回答
for(var k in validation_messages) {
var o = validation_messages[k];
do_something_with(o.your_name);
do_something_else_with(o.your_msg);
}
其他回答
AgileJon答案的优化和改进版本：
var key, obj, prop, owns = Object.prototype.hasOwnProperty;
for (key in validation_messages ) {
if (owns.call(validation_messages, key)) {
obj = validation_messages[key];
for (prop in obj ) {
// Using obj.hasOwnProperty might cause you headache if there is
// obj.hasOwnProperty = function(){return false;}
// but 'owns' will always work
if (owns.call(obj, prop)) {
console.log(prop, "=", obj[prop]);
}
}
}
}
如果使用递归，则可以返回任意深度的对象财产-
function lookdeep(object){
var collection= [], index= 0, next, item;
for(item in object){
if(object.hasOwnProperty(item)){
next= object[item];
if(typeof next== 'object' && next!= null){
collection[index++]= item +
':{ '+ lookdeep(next).join(', ')+'}';
}
else collection[index++]= [item+':'+String(next)];
}
}
return collection;
}
//example
var O={
a:1, b:2, c:{
c1:3, c2:4, c3:{
t:true, f:false
}
},
d:11
};
var lookdeepSample= 'O={'+ lookdeep(O).join(',\n')+'}';
/* returned value: (String)
O={
a:1,
b:2,
c:{
c1:3, c2:4, c3:{
t:true, f:false
}
},
d:11
}
*/
另一种选择：
var testObj = {test: true, test1: false};
for(let x of Object.keys(testObj)){
console.log(x);
}
使用Undercore.js的_.each：
_.each(validation_messages, function(value, key){
_.each(value, function(value, key){
console.log(value);
});
});
for(var key in validation_messages){
for(var subkey in validation_messages[key]){
//code here
//subkey being value, key being 'yourname' / 'yourmsg'
}
}
