如何循环遍历JavaScript对象中的所有成员,包括作为对象的值?

例如,我如何循环(分别访问“your_name”和“your_message”)?

var validation_messages = {
    "key_1": {
        "your_name": "jimmy",
        "your_msg": "hello world"
    },
    "key_2": {
        "your_name": "billy",
        "your_msg": "foo equals bar"
    }
}

当前回答

var validation_messages = {
    "key_1": {
        "your_name": "jimmy",
        "your_msg": "hello world"
    },
    "key_2": {
        "your_name": "billy",
        "your_msg": "foo equals bar"
    }
}
for (var i in validation_messages) {
    console.log("i = \"" + i + "\"");
    console.log("validation_messages[\"" + i + "\"] = ");
    console.log(validation_messages[i]);
    console.log("\n");
    for (var j in validation_messages[i]) {
        console.log("j = \"" + j + "\"");
        console.log("validation_messages[\"" + i + "\"][\"" + j + "\"] = \"" + validation_messages[i][j] + "\"");
        console.log("\n");
    }
    console.log('\n');
}

输出:

i = "key_1"
validation_messages["key_1"] = 
{
  your_name:"jimmy",
  your_msg:"hello world"
}

j = "your_name"
validation_messages["key_1"]["your_name"] = "jimmy"

j = "your_msg"
validation_messages["key_1"]["your_msg"] = "hello world"


i = "key_2"
validation_messages["key_2"] = 
{
  your_name:"billy",
  your_msg:"foo equals bar"
}

j = "your_name"
validation_messages["key_2"]["your_name"] = "billy"

j = "your_msg"
validation_messages["key_2"]["your_msg"] = "foo equals bar"

其他回答

for(var k in validation_messages) {
    var o = validation_messages[k];
    do_something_with(o.your_name);
    do_something_else_with(o.your_msg);
}

这个问题

for (var key in validation_messages) {
   var obj = validation_messages[key];
   for (var prop in obj) {
      alert(prop + " = " + obj[prop]);
   }
}

就是您还将循环遍历原始对象的原型。

有了这个,你可以避免:

for (var key in validation_messages) {
   if (validation_messages.hasOwnProperty(key)) {
      var obj = validation_messages[key];
      for (var prop in obj) {
         if (obj.hasOwnProperty(prop)) {
            alert(prop + " = " + obj[prop]);
         }
      }
   }
}

AgileJon答案的优化和改进版本:

var key, obj, prop, owns = Object.prototype.hasOwnProperty;

for (key in validation_messages ) {

    if (owns.call(validation_messages, key)) {

        obj = validation_messages[key];

        for (prop in obj ) {

            // Using obj.hasOwnProperty might cause you headache if there is
            // obj.hasOwnProperty = function(){return false;}
            // but 'owns' will always work
            if (owns.call(obj, prop)) {
                console.log(prop, "=", obj[prop]);
            }
        }
    }
}

异国情调的单深度穿越

JSON.stringify(validation_messages,(field,value)=>{
  if(!field) return value;

  // ... your code

  return value;
})

在这个解决方案中,我们使用了替换器,它允许深入遍历整个对象和嵌套对象-在每个级别上,您将获得所有字段和值。如果您需要获取每个字段的完整路径,请查看此处。

var验证消息={“key_1”:{“your_name”:“jimmy”,“your_msg”:“hello world”},“key_2”:{“your_name”:“billy”,“your_msg”:“foo等于bar”,“深”:{“颜色”:“红色”,“大小”:“10px”}}}JSON.stringify(validation_messages,(字段,值)=>{if(!field)返回值;console.log(`key:${field.padEnd(11)}-value:${value}`);返回值;})

2020年,您需要不可变的通用函数

这将遍历由子对象、数组和字符串组成的多维对象,并应用自定义函数:

export const iterate = (object, func) => {
  const entries = Object.entries(object).map(([key, value]) =>
    Array.isArray(value)
      ? [key, value.map(e => iterate(e, func))]
      : typeof value === 'object'
      ? [key, iterate(value, func)]
      : [key, func(value)]
  );
  return Object.fromEntries(entries);
};

用法:

const r = iterate(data, e=>'converted_'+e);
console.log(r);