我如何检查一个字符串(NSString)包含另一个较小的字符串?
我希望是这样的:
NSString *string = @"hello bla bla";
NSLog(@"%d",[string containsSubstring:@"hello"]);
但我能找到的最接近的是:
if ([string rangeOfString:@"hello"] == 0) {
NSLog(@"sub string doesnt exist");
}
else {
NSLog(@"exists");
}
不管怎样，这是找出字符串是否包含另一个字符串的最好方法吗?
当前回答
在iOS 8和Swift中，我们可以使用localizedCaseInsensitiveContainsString方法
let string: NSString = "Café"
let substring: NSString = "É"
string.localizedCaseInsensitiveContainsString(substring) // true
其他回答
因为这似乎是谷歌中的一个高级结果，我想添加这个:
iOS 8和OS X 10.10在NSString中添加了containsString:方法。Dave DeLong关于这些系统的例子的更新版本:
NSString *string = @"hello bla bla";
if ([string containsString:@"bla"]) {
NSLog(@"string contains bla!");
} else {
NSLog(@"string does not contain bla");
}
如果不介意区分大小写的字符串。 试试这个。
NSString *string = @"Hello World!";
if([string rangeOfString:@"hello" options:NSCaseInsensitiveSearch].location !=NSNotFound)
{
NSLog(@"found");
}
else
{
NSLog(@"not found");
}
在Swift 4中:
let a = "Hello, how are you?"
a.contains("Hello") //will return true
试试这个:
Swift 4.1、4.2:
let stringData = "Black board"
//swift quick way and case sensitive
if stringData.contains("bla") {
print("data contains string");
}
//case sensitive
if stringData.range(of: "bla",options: .caseInsensitive) != nil {
print("data contains string");
}else {
print("data does not contains string");
}
objective - c:
NSString *stringData = @"Black board";
//Quick way and case sensitive
if ([stringData containsString:@"bla"]) {
NSLog(@"data contains string");
}
//Case Insensitive
if ([stringData rangeOfString:@"bla" options:NSCaseInsensitiveSearch].location != NSNotFound) {
NSLog(@"data contains string");
}else {
NSLog(@"data does not contain string");
}
下面是一个复制粘贴函数片段:
-(BOOL)Contains:(NSString *)StrSearchTerm on:(NSString *)StrText
{
return [StrText rangeOfString:StrSearchTerm
options:NSCaseInsensitiveSearch].location != NSNotFound;
}
