我如何检查一个字符串(NSString)包含另一个较小的字符串?
我希望是这样的:
NSString *string = @"hello bla bla";
NSLog(@"%d",[string containsSubstring:@"hello"]);
但我能找到的最接近的是:
if ([string rangeOfString:@"hello"] == 0) {
NSLog(@"sub string doesnt exist");
}
else {
NSLog(@"exists");
}
不管怎样，这是找出字符串是否包含另一个字符串的最好方法吗?
当前回答
最佳解决方案。就这么简单!如果你想找个词或者 字符串的一部分。您可以使用此代码。在本例中，我们将检查word的值是否包含"acter"。
NSString *word =@"find a word or character here";
if ([word containsString:@"acter"]){
NSLog(@"It contains acter");
} else {
NSLog (@"It does not contain acter");
}
其他回答
试试这个:
Swift 4.1、4.2:
let stringData = "Black board"
//swift quick way and case sensitive
if stringData.contains("bla") {
print("data contains string");
}
//case sensitive
if stringData.range(of: "bla",options: .caseInsensitive) != nil {
print("data contains string");
}else {
print("data does not contains string");
}
objective - c:
NSString *stringData = @"Black board";
//Quick way and case sensitive
if ([stringData containsString:@"bla"]) {
NSLog(@"data contains string");
}
//Case Insensitive
if ([stringData rangeOfString:@"bla" options:NSCaseInsensitiveSearch].location != NSNotFound) {
NSLog(@"data contains string");
}else {
NSLog(@"data does not contain string");
}
最佳解决方案。就这么简单!如果你想找个词或者 字符串的一部分。您可以使用此代码。在本例中，我们将检查word的值是否包含"acter"。
NSString *word =@"find a word or character here";
if ([word containsString:@"acter"]){
NSLog(@"It contains acter");
} else {
NSLog (@"It does not contain acter");
}
i的解决方案的一个改进版本，NSString上的一个类别，它不仅会告诉，如果一个字符串在另一个字符串中被找到，而且还需要一个引用范围，是:
@interface NSString (Contains)
-(BOOL)containsString: (NSString*)substring
atRange:(NSRange*)range;
-(BOOL)containsString:(NSString *)substring;
@end
@implementation NSString (Contains)
-(BOOL)containsString:(NSString *)substring
atRange:(NSRange *)range{
NSRange r = [self rangeOfString : substring];
BOOL found = ( r.location != NSNotFound );
if (range != NULL) *range = r;
return found;
}
-(BOOL)containsString:(NSString *)substring
{
return [self containsString:substring
atRange:NULL];
}
@end
像这样使用它:
NSString *string = @"Hello, World!";
//If you only want to ensure a string contains a certain substring
if ([string containsString:@"ello" atRange:NULL]) {
NSLog(@"YES");
}
// Or simply
if ([string containsString:@"ello"]) {
NSLog(@"YES");
}
//If you also want to know substring's range
NSRange range;
if ([string containsString:@"ello" atRange:&range]) {
NSLog(@"%@", NSStringFromRange(range));
}
联机(更少的代码。DRY，因为你只有一个NSLog):
NSString *string = @"hello bla bla";
NSLog(@"String %@", ([string rangeOfString:@"bla"].location == NSNotFound) ? @"not found" : @"cotains bla");
如果不介意区分大小写的字符串。 试试这个。
NSString *string = @"Hello World!";
if([string rangeOfString:@"hello" options:NSCaseInsensitiveSearch].location !=NSNotFound)
{
NSLog(@"found");
}
else
{
NSLog(@"not found");
}
