我怎样才能做到这一点呢?

public class GenericClass<T>
{
    public Type getMyType()
    {
        //How do I return the type of T?
    }
}

到目前为止,我所尝试的一切总是返回Object类型,而不是使用的特定类型。


当前回答

一个简单的解决方案,这种出租车如下

public class GenericDemo<T>{
    private T type;

    GenericDemo(T t)
    {
        this.type = t;
    }

    public String getType()
    {
        return this.type.getClass().getName();
    }

    public static void main(String[] args)
    {
        GenericDemo<Integer> obj = new  GenericDemo<Integer>(5);
        System.out.println("Type: "+ obj.getType());
    }
}

其他回答

如果不能更改泛型类并使用本页中已经解释的方法之一,那么简单的方法是根据运行时实例类名获取类型类。

Class getType(GenericType runtimeClassMember){
if (ClassA.class.equals(runtimeClassMember.getClass()){
  return TypeForClassA.class;
} else if (ClassB.class.equals(runtimeClassMember.getClass()){
  return TypeForClassB.class;
} 

//throw an expectation or do whatever you want for the cases not described in the if section.
}

Ian Robertson在这篇文章中描述的技巧对我很有用。

简单粗暴的例子:

 public abstract class AbstractDAO<T extends EntityInterface, U extends QueryCriteria, V>
 {
    /**
     * Method returns class implementing EntityInterface which was used in class
     * extending AbstractDAO
     *
     * @return Class<T extends EntityInterface>
     */
    public Class<T> returnedClass()
    {
        return (Class<T>) getTypeArguments(AbstractDAO.class, getClass()).get(0);
    }

    /**
     * Get the underlying class for a type, or null if the type is a variable
     * type.
     *
     * @param type the type
     * @return the underlying class
     */
    public static Class<?> getClass(Type type)
    {
        if (type instanceof Class) {
            return (Class) type;
        } else if (type instanceof ParameterizedType) {
            return getClass(((ParameterizedType) type).getRawType());
        } else if (type instanceof GenericArrayType) {
            Type componentType = ((GenericArrayType) type).getGenericComponentType();
            Class<?> componentClass = getClass(componentType);
            if (componentClass != null) {
                return Array.newInstance(componentClass, 0).getClass();
            } else {
                return null;
            }
        } else {
            return null;
        }
    }

    /**
     * Get the actual type arguments a child class has used to extend a generic
     * base class.
     *
     * @param baseClass the base class
     * @param childClass the child class
     * @return a list of the raw classes for the actual type arguments.
     */
    public static <T> List<Class<?>> getTypeArguments(
            Class<T> baseClass, Class<? extends T> childClass)
    {
        Map<Type, Type> resolvedTypes = new HashMap<Type, Type>();
        Type type = childClass;
        // start walking up the inheritance hierarchy until we hit baseClass
        while (!getClass(type).equals(baseClass)) {
            if (type instanceof Class) {
                // there is no useful information for us in raw types, so just keep going.
                type = ((Class) type).getGenericSuperclass();
            } else {
                ParameterizedType parameterizedType = (ParameterizedType) type;
                Class<?> rawType = (Class) parameterizedType.getRawType();

                Type[] actualTypeArguments = parameterizedType.getActualTypeArguments();
                TypeVariable<?>[] typeParameters = rawType.getTypeParameters();
                for (int i = 0; i < actualTypeArguments.length; i++) {
                    resolvedTypes.put(typeParameters[i], actualTypeArguments[i]);
                }

                if (!rawType.equals(baseClass)) {
                    type = rawType.getGenericSuperclass();
                }
            }
        }

        // finally, for each actual type argument provided to baseClass, determine (if possible)
        // the raw class for that type argument.
        Type[] actualTypeArguments;
        if (type instanceof Class) {
            actualTypeArguments = ((Class) type).getTypeParameters();
        } else {
            actualTypeArguments = ((ParameterizedType) type).getActualTypeArguments();
        }
        List<Class<?>> typeArgumentsAsClasses = new ArrayList<Class<?>>();
        // resolve types by chasing down type variables.
        for (Type baseType : actualTypeArguments) {
            while (resolvedTypes.containsKey(baseType)) {
                baseType = resolvedTypes.get(baseType);
            }
            typeArgumentsAsClasses.add(getClass(baseType));
        }
        return typeArgumentsAsClasses;
    }
  }

Java泛型大多是在编译时,这意味着类型信息在运行时丢失。

class GenericCls<T>
{
    T t;
}

会被编译成什么样子

class GenericCls
{
   Object o;
}

要在运行时获得类型信息,必须将其作为ctor的参数添加。

class GenericCls<T>
{
     private Class<T> type;
     public GenericCls(Class<T> cls)
     {
        type= cls;
     }
     Class<T> getType(){return type;}
}

例子:

GenericCls<?> instance = new GenericCls<String>(String.class);
assert instance.getType() == String.class;

我发现这是一个简单易懂且容易解释的解决方案

public class GenericClass<T> {

    private Class classForT(T...t) {
        return t.getClass().getComponentType();
    }

    public static void main(String[] args) {
        GenericClass<String> g = new GenericClass<String>();

        System.out.println(g.classForT());
        System.out.println(String.class);
    }
}

使用番石榴。

import com.google.common.reflect.TypeToken;
import java.lang.reflect.Type;

public abstract class GenericClass<T> {
  private final TypeToken<T> typeToken = new TypeToken<T>(getClass()) { };
  private final Type type = typeToken.getType(); // or getRawType() to return Class<? super T>

  public Type getType() {
    return type;
  }

  public static void main(String[] args) {
    GenericClass<String> example = new GenericClass<String>() { };
    System.out.println(example.getType()); // => class java.lang.String
  }
}

不久前,我在这里发布了一些完整的示例,包括抽象类和子类。

注意:这需要实例化GenericClass的一个子类,这样它才能正确地绑定类型参数。否则它只会返回类型为T。