我最喜欢的SQL反模式:

对非唯一列进行JOIN，并使用SELECT DISTINCT修剪结果。

创建连接多个表的视图，只是为了从一个表中选择少数列。

 CREATE VIEW my_view AS 
     SELECT * FROM table1
     JOIN table2 ON (...)
     JOIN table3 ON (...);

 SELECT col1, col2 FROM my_view WHERE col3 = 123;

FROM TableA, TableB WHERE语法用于连接而不是FROM TableA内部连接TableB上 假设查询将以某种方式返回，而不放入ORDER BY子句，因为这是在查询工具中测试时显示的方式。

没有使用With子句或适当的连接并依赖子查询。

反模式:

select 
 ...
from data
where RECORD.STATE IN (
          SELECT STATEID
            FROM STATE
           WHERE NAME IN
                    ('Published to test',
                     'Approved for public',
                     'Published to public',
                     'Archived'
                    ))

好: 我喜欢使用with子句使我的意图更易于阅读。

with valid_states as (
          SELECT STATEID
            FROM STATE
           WHERE NAME IN
                    ('Published to test',
                     'Approved for public',
                     'Published to public',
                     'Archived'
                    )
select  ... from data, valid_states
where data.state = valid_states.state

最好的:

select 
  ... 
from data join states using (state)
where 
states.state in  ('Published to test',
                     'Approved for public',
                     'Published to public',
                     'Archived'
                    )

使用无意义的表别名:

from employee t1,
department t2,
job t3,
...

使得阅读一个大的SQL语句比它需要的要困难得多

我看到视图定义是这样的:

CREATE OR REPLACE FORCE VIEW PRICE (PART_NUMBER, PRICE_LIST, LIST_VERSION ...)
AS
  SELECT sp.MKT_PART_NUMBER,
    sp.PRICE_LIST,
    sp.LIST_VERSION,
    sp.MIN_PRICE,
    sp.UNIT_PRICE,
    sp.MAX_PRICE,
...

视图中大约有50个列。有些开发人员以不提供列别名而折磨他人为傲，因此必须计算两个位置的列偏移量，以便能够找出视图中对应的列。

像这样将冗余表连接到查询中:

select emp.empno, dept.deptno
from emp
join dept on dept.deptno = emp.deptno;