首先，这是屏幕加载图像矢量资产可见性

点击它将改变这个图像的可见性关闭

以上密码开关代码(xml代码)

<androidx.constraintlayout.widget.ConstraintLayout
    android:id="@+id/laypass"
    android:layout_width="330dp"
    android:layout_height="50dp"
    android:layout_marginTop="24dp"
    app:layout_constraintEnd_toEndOf="@+id/editText3"
    app:layout_constraintStart_toStartOf="@+id/editText3"
    app:layout_constraintTop_toBottomOf="@+id/editText3">

    <EditText
        android:id="@+id/edit_password"
        style="@style/EditTextTheme"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:background="@drawable/round"
        android:drawableLeft="@drawable/ic_password"
        android:drawablePadding="10dp"
        android:ems="10"
        android:hint="Password"
        android:inputType="textPassword"
        android:paddingLeft="10dp"
        android:paddingRight="15dp"
        android:textColor="@color/cyan92a6"
        android:textColorHint="@color/cyan92a6"
        android:textCursorDrawable="@null"
        android:textSize="18sp"
        />

    <ImageView
        android:id="@+id/show_pass_btn"
        android:layout_width="40dp"
        android:layout_height="40dp"
        android:layout_alignParentRight="true"
        android:layout_centerVertical="true"
        android:layout_marginEnd="8dp"
        android:alpha=".5"
        android:onClick="ShowHidePass"
        android:padding="5dp"
        android:src="@drawable/ic_visibility"
        app:layout_constraintBottom_toBottomOf="parent"
        app:layout_constraintEnd_toEndOf="@+id/laypass"
        app:layout_constraintTop_toTopOf="@+id/edit_password" /> 
 </androidx.constraintlayout.widget.ConstraintLayout>

按钮操作的Java代码

public void ShowHidePass(View view) {

    if(view.getId()==R.id.show_pass_btn){
        if(edit_password.getTransformationMethod().equals(PasswordTransformationMethod.getInstance())){
            ((ImageView)(view)).setImageResource(R.drawable.ic_visibility_off);
            //Show Password
            edit_password.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
        }
        else{
            ((ImageView)(view)).setImageResource(R.drawable.ic_visibility);
            //Hide Password
            edit_password.setTransformationMethod(PasswordTransformationMethod.getInstance());
        }
    }
}

只需在Xml文件中创建一个复选框

然后简单的用Java代码编写这个函数

checkbox = findViewById(R.id.checkbox);
        checkbox.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener(){
            @Override
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked){

                if (isChecked) {
                    password.setTransformationMethod(null);
                }
                else{
                    password.setTransformationMethod(new PasswordTransformationMethod());
                }
            }

        });

if (inputPassword.getTransformationMethod() == PasswordTransformationMethod.getInstance()) {
 //password is visible
                inputPassword.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
            }
else if(inputPassword.getTransformationMethod() == HideReturnsTransformationMethod.getInstance()) {
 //password is hidden
                inputPassword.setTransformationMethod(PasswordTransformationMethod.getInstance());
            }

要显示圆点而不是密码，请设置PasswordTransformationMethod:

yourEditText.setTransformationMethod(new PasswordTransformationMethod());

当然，您可以在XML布局中的edittext元素中默认设置此选项

android:password

要重新显示可读密码，只需传递null作为转换方法:

yourEditText.setTransformationMethod(null);

我使用了一个OnClickListener()，它与我想用作toogle的按钮相关联。

private EditText email_et, contraseña_et;
protected void onCreate(Bundle savedInstanceState) {
....
contraseña_et = (EditText) findViewById(R.id.contraseña_et);
....
vercontra_btn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            int inputType = contraseña_et.getInputType();
            if (inputType == 129){
                contraseña_et.setInputType(1);
            } else {
                contraseña_et.setInputType(129);
            }
            contraseña_et.setSelection(contraseña_et.getText().length());
        }
    });

阅读文档，int值似乎是不同的，所以我调试找到正确的值，它的工作棒极了，这是一个更容易一点的方式。

[顺便说一下，Contraseña是西班牙语的密码]

我可以添加ShowPassword / HidePassword代码，只需几行，在一个块中独立:

protected void onCreate(Bundle savedInstanceState) {
    ...
    etPassword = (EditText)findViewById(R.id.password);
    etPassword.setTransformationMethod(new PasswordTransformationMethod()); // Hide password initially

    checkBoxShowPwd = (CheckBox)findViewById(R.id.checkBoxShowPwd);
    checkBoxShowPwd.setText(getString(R.string.label_show_password)); // Hide initially, but prompting "Show Password"
    checkBoxShowPwd.setOnCheckedChangeListener( new CompoundButton.OnCheckedChangeListener() {
        public void onCheckedChanged(CompoundButton arg0, boolean isChecked) {
            if (isChecked) {
                etPassword.setTransformationMethod(null); // Show password when box checked
                checkBoxShowPwd.setText(getString(R.string.label_hide_password)); // Prompting "Hide Password"
            } else {
                etPassword.setTransformationMethod(new PasswordTransformationMethod()); // Hide password when box not checked
                checkBoxShowPwd.setText(getString(R.string.label_show_password)); // Prompting "Show Password"
            }
        }
    } );
    ...