有没有一个聪明的方法让用户在隐藏和查看密码之间切换在一个android EditText? 许多基于PC的应用程序都允许用户这样做。


当前回答

首先,这是屏幕加载图像矢量资产可见性

点击它将改变这个图像的可见性关闭

以上密码开关代码(xml代码)

<androidx.constraintlayout.widget.ConstraintLayout
    android:id="@+id/laypass"
    android:layout_width="330dp"
    android:layout_height="50dp"
    android:layout_marginTop="24dp"
    app:layout_constraintEnd_toEndOf="@+id/editText3"
    app:layout_constraintStart_toStartOf="@+id/editText3"
    app:layout_constraintTop_toBottomOf="@+id/editText3">

    <EditText
        android:id="@+id/edit_password"
        style="@style/EditTextTheme"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:background="@drawable/round"
        android:drawableLeft="@drawable/ic_password"
        android:drawablePadding="10dp"
        android:ems="10"
        android:hint="Password"
        android:inputType="textPassword"
        android:paddingLeft="10dp"
        android:paddingRight="15dp"
        android:textColor="@color/cyan92a6"
        android:textColorHint="@color/cyan92a6"
        android:textCursorDrawable="@null"
        android:textSize="18sp"
        />

    <ImageView
        android:id="@+id/show_pass_btn"
        android:layout_width="40dp"
        android:layout_height="40dp"
        android:layout_alignParentRight="true"
        android:layout_centerVertical="true"
        android:layout_marginEnd="8dp"
        android:alpha=".5"
        android:onClick="ShowHidePass"
        android:padding="5dp"
        android:src="@drawable/ic_visibility"
        app:layout_constraintBottom_toBottomOf="parent"
        app:layout_constraintEnd_toEndOf="@+id/laypass"
        app:layout_constraintTop_toTopOf="@+id/edit_password" /> 
 </androidx.constraintlayout.widget.ConstraintLayout>

按钮操作的Java代码

public void ShowHidePass(View view) {

    if(view.getId()==R.id.show_pass_btn){
        if(edit_password.getTransformationMethod().equals(PasswordTransformationMethod.getInstance())){
            ((ImageView)(view)).setImageResource(R.drawable.ic_visibility_off);
            //Show Password
            edit_password.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
        }
        else{
            ((ImageView)(view)).setImageResource(R.drawable.ic_visibility);
            //Hide Password
            edit_password.setTransformationMethod(PasswordTransformationMethod.getInstance());
        }
    }
}

其他回答

您必须询问当前文本是否已经显示了圆点,函数PasswordTransformationMethod.getInstance()允许您这样做。

这是我在kotlin中的函数:

        fun hideAndShowPassword(editText: EditText, indicator: ImageView) {

        if (editText.transformationMethod == PasswordTransformationMethod.getInstance()) {
            editText.transformationMethod = HideReturnsTransformationMethod.getInstance()
            indicator.setImageDrawable(
                ContextCompat.getDrawable(
                    editText.context,
                    R.drawable.eye
                )
            )
            indicator.imageTintList =
                ContextCompat.getColorStateList(editText.context, R.color.colorTintIcons)
        } else {
            editText.transformationMethod = PasswordTransformationMethod.getInstance()
            indicator.setImageDrawable(
                ContextCompat.getDrawable(
                    editText.context,
                    R.drawable.eye_off
                )
            )
            indicator.imageTintList =
                ContextCompat.getColorStateList(editText.context, R.color.colorTintIcons)
        }

        editText.setSelection(editText.text.length)
    }

显示:

editText.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);

隐藏:

editText.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);

在这些之后,光标被重置,所以:

editText.setSelection(editText.length());

我觉得我想回答这个问题,即使有一些好的答案,

根据文档TransformationMethod完成我们的任务

TransformationMethod TextView使用TransformationMethods来做一些事情,比如替换 字符的密码与点,或保持换行符 避免在单行文本字段中引起换行。

注意我使用黄油刀,但它是相同的,如果用户检查显示密码

@OnCheckedChanged(R.id.showpass)
    public void onChecked(boolean checked){
        if(checked){
            et_password.setTransformationMethod(null);
        }else {
            et_password.setTransformationMethod(new PasswordTransformationMethod());
            
        }
       // cursor reset his position so we need set position to the end of text
        et_password.setSelection(et_password.getText().length());
    }
you can use this

private fun showPasswordSwitch(checked: Boolean) {

    registerBinding.registerActivityEditTextPassword.also {
        // Password hide-show
        it.inputType =
            if (checked) TEXT_PASSWORD_SHOW else TEXT_PASSWORD_HIDE
           
    }
}
const val TEXT_PASSWORD_SHOW = InputType.TYPE_CLASS_TEXT or InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD

const val TEXT_PASSWORD_HIDE = InputType.TYPE_CLASS_TEXT or InputType.TYPE_TEXT_VARIATION_PASSWORD

试试这个:

passwordEditText.setInputType(1);

Or

passwordEditText.setInputType(InputType.TYPE_CLASS_TEXT);