有没有一个聪明的方法让用户在隐藏和查看密码之间切换在一个android EditText? 许多基于PC的应用程序都允许用户这样做。


当前回答

首先,这是屏幕加载图像矢量资产可见性

点击它将改变这个图像的可见性关闭

以上密码开关代码(xml代码)

<androidx.constraintlayout.widget.ConstraintLayout
    android:id="@+id/laypass"
    android:layout_width="330dp"
    android:layout_height="50dp"
    android:layout_marginTop="24dp"
    app:layout_constraintEnd_toEndOf="@+id/editText3"
    app:layout_constraintStart_toStartOf="@+id/editText3"
    app:layout_constraintTop_toBottomOf="@+id/editText3">

    <EditText
        android:id="@+id/edit_password"
        style="@style/EditTextTheme"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:background="@drawable/round"
        android:drawableLeft="@drawable/ic_password"
        android:drawablePadding="10dp"
        android:ems="10"
        android:hint="Password"
        android:inputType="textPassword"
        android:paddingLeft="10dp"
        android:paddingRight="15dp"
        android:textColor="@color/cyan92a6"
        android:textColorHint="@color/cyan92a6"
        android:textCursorDrawable="@null"
        android:textSize="18sp"
        />

    <ImageView
        android:id="@+id/show_pass_btn"
        android:layout_width="40dp"
        android:layout_height="40dp"
        android:layout_alignParentRight="true"
        android:layout_centerVertical="true"
        android:layout_marginEnd="8dp"
        android:alpha=".5"
        android:onClick="ShowHidePass"
        android:padding="5dp"
        android:src="@drawable/ic_visibility"
        app:layout_constraintBottom_toBottomOf="parent"
        app:layout_constraintEnd_toEndOf="@+id/laypass"
        app:layout_constraintTop_toTopOf="@+id/edit_password" /> 
 </androidx.constraintlayout.widget.ConstraintLayout>

按钮操作的Java代码

public void ShowHidePass(View view) {

    if(view.getId()==R.id.show_pass_btn){
        if(edit_password.getTransformationMethod().equals(PasswordTransformationMethod.getInstance())){
            ((ImageView)(view)).setImageResource(R.drawable.ic_visibility_off);
            //Show Password
            edit_password.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
        }
        else{
            ((ImageView)(view)).setImageResource(R.drawable.ic_visibility);
            //Hide Password
            edit_password.setTransformationMethod(PasswordTransformationMethod.getInstance());
        }
    }
}

其他回答

这是我的工作。这绝对对你有帮助

showpass.setOnCheckedChangeListener(new OnCheckedChangeListener() {

            @Override
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
                    if(!isChecked){

                    // show password
                    password_login.setTransformationMethod(PasswordTransformationMethod.getInstance());

                    Log.i("checker", "true");
                }

                else{
                    Log.i("checker", "false");

                     // hide password
    password_login.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
                }

            }
        });

使用复选框并相应地更改输入类型。

public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
    int start,end;
    Log.i("inside checkbox chnge",""+isChecked);
    if(!isChecked){
        start=passWordEditText.getSelectionStart();
        end=passWordEditText.getSelectionEnd();
        passWordEditText.setTransformationMethod(new PasswordTransformationMethod());;
        passWordEditText.setSelection(start,end);
    }else{
        start=passWordEditText.getSelectionStart();
        end=passWordEditText.getSelectionEnd();
        passWordEditText.setTransformationMethod(null);
        passWordEditText.setSelection(start,end);
    }
}
private boolean isPasswordVisible;

private TextInputEditText firstEditText;

...

firstEditText = findViewById(R.id.et_first);

...

    private void togglePassVisability() {
    if (isPasswordVisible) {
        String pass = firstEditText.getText().toString();
        firstEditText.setTransformationMethod(PasswordTransformationMethod.getInstance());
        firstEditText.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
        firstEditText.setText(pass);
        firstEditText.setSelection(pass.length());           
    } else {
        String pass = firstEditText.getText().toString();
        firstEditText.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
        firstEditText.setInputType(InputType.TYPE_CLASS_TEXT);
        firstEditText.setText(pass);
        firstEditText.setSelection(pass.length());
    }
    isPasswordVisible= !isPasswordVisible;
}

我的Kotlin扩展。编写一次,随处使用

fun EditText.tooglePassWord() {
this.tag = !((this.tag ?: false) as Boolean)
this.inputType = if (this.tag as Boolean)
    InputType.TYPE_TEXT_VARIATION_PASSWORD
else
    (InputType.TYPE_CLASS_TEXT or InputType.TYPE_TEXT_VARIATION_PASSWORD)

this.setSelection(this.length()) }

您可以将此方法保存在任何文件中,并在任何地方使用它 像这样使用它

ivShowPassword.click { etPassword.tooglePassWord() }

其中ivShowPassword是点击imageview(眼睛)和etPassword是编辑

显示:

editText.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);

隐藏:

editText.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);

在这些之后,光标被重置,所以:

editText.setSelection(editText.length());