我试图用多个其他单词替换字符串中的多个单词。字符串是“我有一只猫，一只狗和一只山羊。”
然而，这并不会产生“我有一只狗、一只山羊和一只猫”，而是产生“我有一只猫、一只猫和一只猫”。是否有可能在JavaScript中同时用多个其他字符串替换多个字符串，以便产生正确的结果?
var str = "I have a cat, a dog, and a goat.";
str = str.replace(/cat/gi, "dog");
str = str.replace(/dog/gi, "goat");
str = str.replace(/goat/gi, "cat");
//this produces "I have a cat, a cat, and a cat"
//but I wanted to produce the string "I have a dog, a goat, and a cat".
当前回答
以防有人想知道为什么原来海报上的解决方案不管用:
var str = "I have a cat, a dog, and a goat.";
str = str.replace(/cat/gi, "dog");
// now str = "I have a dog, a dog, and a goat."
str = str.replace(/dog/gi, "goat");
// now str = "I have a goat, a goat, and a goat."
str = str.replace(/goat/gi, "cat");
// now str = "I have a cat, a cat, and a cat."
其他回答
试试我的解决方案。请随意改进
函数multiReplace(字符串，regex，替换){ 返回str.replace(regex, function(x) { //检查替换键以防止错误，如果为false则返回原始值 return Object.keys(replace).includes(x) ?替换[x]: x; })； } var str = "我有一只猫，一只狗，和一只山羊。"; //(json)使用value替换键 Var替换= { “猫”:“狗”, “狗”:“山羊”, “山羊”:“猫”, ｝ console.log(multiReplace(str， /Cat|dog|goat/g, replace))
我们也可以使用split()和join()方法:
var str = "我有一只猫，一只狗，和一只山羊。"; str = str.split(“猫”)。映射(x =>{返回x.split("dog"))。地图(y = >{返回y.split(“山羊”). join(“猫”);}). join(“山羊”);}). join(“狗”); console.log (str);
注意!
如果您正在使用动态提供的映射，这里的解决方案都不够!
在这种情况下，有两种解决方法:(1)使用分割连接技术，(2)使用正则表达式和特殊字符转义技术。
这是一个分割连接技术，它比另一个快得多(至少快50%):
var str = "I have {abc} a c|at, a d(og, and a g[oat] {1} {7} {11." var mapObj = { 'c|at': "d(og", 'd(og': "g[oat", 'g[oat]': "c|at", }; var entries = Object.entries(mapObj); console.log( entries .reduce( // Replace all the occurrences of the keys in the text into an index placholder using split-join (_str, [key], i) => _str.split(key).join(`{${i}}`), // Manipulate all exisitng index placeholder -like formats, in order to prevent confusion str.replace(/\{(?=\d+\})/g, '{-') ) // Replace all index placeholders to the desired replacement values .replace(/\{(\d+)\}/g, (_,i) => entries[i][1]) // Undo the manipulation of index placeholder -like formats .replace(/\{-(?=\d+\})/g, '{') );
这一个，是Regex特殊字符转义技术，它也有用，但慢得多:
var str = "I have a c|at, a d(og, and a g[oat]." var mapObj = { 'c|at': "d(og", 'd(og': "g[oat", 'g[oat]': "c|at", }; console.log( str.replace( new RegExp( // Convert the object to array of keys Object.keys(mapObj) // Escape any special characters in the search key .map(key => key.replace(/[-[\]{}()*+?.,\\^$|#\s]/g, '\\$&')) // Create the Regex pattern .join('|'), // Additional flags can be used. Like `i` - case-insensitive search 'g' ), // For each key found, replace with the appropriate value match => mapObj[match] ) );
后者的优点是，它也可以用于不区分大小写的搜索。
你可以试试这个。买不聪明。
var str = "我有一只猫，一只狗，和一只山羊。"; console.log (str); str = str.replace(/cat/gi， "XXX"); console.log (str); STR = STR .replace(/goat/gi， "cat"); console.log (str); STR = STR .replace(/dog/gi， "goat"); console.log (str); str = str.replace(/XXX/gi， "dog"); console.log (str); 把: 我有一只狗，一只山羊和一只猫。
我写了这个npm包stringinject https://www.npmjs.com/package/stringinject，它允许你做以下事情
var string = stringInject("this is a {0} string for {1}", ["test", "stringInject"]);
这将替换{0}和{1}与数组项，并返回以下字符串
"this is a test string for stringInject"
或者你可以像这样用对象键和值替换占位符:
var str = stringInject("My username is {username} on {platform}", { username: "tjcafferkey", platform: "GitHub" });
"My username is tjcafferkey on Github"
