你遇到过的源代码中最好的注释是什么?


当前回答

一些来自Linux内核的代码:

/* Sun, you just can't beat me, you just can't.  Stop trying,
* give up.  I'm serious, I am going to kick the living shit
* out of you, game over, lights out.
*/

-

/* 2,191 lines of complete and utter shit coming up... */

-

#if 0 /* XXX No fucking way dude... */

其他回答

// TODO - Comment this function
/* You are not meant to understand this */ 
virgin = 0;     /* you're not a virgin anymore, sweety */
catch (Exception ex)
{ 
    // just die already.
}

从《雷神之锤III》的资料中,我在一些随机的帖子中偶然发现了这一点。该文件的完整源代码可以在这里找到。这是一种非常快速的求平方根倒数的方法。至于最好的评论呢?当然,这是一种常见的方法,但考虑到它附着在直线上,它的神奇之处在于它的伟大之处。

float Q_rsqrt( float number )
{
  long i;
  float x2, y;
  const float threehalfs = 1.5F;

  x2 = number * 0.5F;
  y  = number;
  i  = * ( long * ) &y;  // evil floating point bit level hacking
  i  = 0x5f3759df - ( i >> 1 ); // what the fuck?
  y  = * ( float * ) &i;
  y  = y * ( threehalfs - ( x2 * y * y ) ); // 1st iteration
  // y  = y * ( threehalfs - ( x2 * y * y ) ); // 2nd iteration, this can be removed

  #ifndef Q3_VM
  #ifdef __linux__
    assert( !isnan(y) ); // bk010122 - FPE?
  #endif
  #endif
  return y;
}