从《雷神之锤III》的资料中，我在一些随机的帖子中偶然发现了这一点。该文件的完整源代码可以在这里找到。这是一种非常快速的求平方根倒数的方法。至于最好的评论呢?当然，这是一种常见的方法，但考虑到它附着在直线上，它的神奇之处在于它的伟大之处。

float Q_rsqrt( float number )
{
  long i;
  float x2, y;
  const float threehalfs = 1.5F;

  x2 = number * 0.5F;
  y  = number;
  i  = * ( long * ) &y;  // evil floating point bit level hacking
  i  = 0x5f3759df - ( i >> 1 ); // what the fuck?
  y  = * ( float * ) &i;
  y  = y * ( threehalfs - ( x2 * y * y ) ); // 1st iteration
  // y  = y * ( threehalfs - ( x2 * y * y ) ); // 2nd iteration, this can be removed

  #ifndef Q3_VM
  #ifdef __linux__
    assert( !isnan(y) ); // bk010122 - FPE?
  #endif
  #endif
  return y;
}

我在一个充满显式怪异类型转换的函数中见过这段代码:

// Since today's CPUs are really fast, this is dedicated to those who said:
// " You can't use Moore's Law as an excuse to write bad software. "

代码太可怕了:)

// I dedicate all this code, all my work, to my wife, Darlene, who will 
// have to support me and our three children and the dog once it gets 
// released into the public.

-- Comment this later

这是一个4000多行的PL/SQL过程的第2行。唯一的评论。手术已经进行了4年了，后来还是没来…

// Bad Christian, No cookie

这里的Cookie不是指浏览器Cookie

int Q13Factor = 8125; // 2^13 for Q13