你遇到过的源代码中最好的注释是什么?
当前回答
# There is a bug in the next line. $searchParameters != {} will always return true, because {} is creating
# a new hash reference on the fly, and the inequality operater is comparing the memory location of it
# to the memory location of $searchParameters, and they will always be different.
# This means that the following code will always get executed as long as $nodes is defined.
# I'm leaving it there because it has always been there, and although I'm sure it was originally meant to
# mean %$searchParameters (essentially "is this hash not empty"), I'm afraid to change it.
if ( $nodes && $searchParameters != {} )
{
其他回答
在初始化链表时:
last = first; /* Biblical reference */
简洁而滑稽。
有一次,我在另一个讨论中看到这样的内容:
// I can't divide with zero, so I have to divide with something very similar
result = number / 0.00000000000001;
聪明的解决方案,不是吗?(如果有人不确定,这就是个笑话)
//If you're reading this, then my program is probably a success
不是一个评论,而是一个goto标签
ICantBelieveImUsingAGoto:
从谷歌代码项目:
# This job would be great if it wasn't for the fucking customers.
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