你遇到过的源代码中最好的注释是什么?


当前回答

# There is a bug in the next line.  $searchParameters != {} will always return true, because {} is creating
# a new hash reference on the fly, and the inequality operater is comparing the memory location of it
# to the memory location of $searchParameters, and they will always be different. 
# This means that the following code will always get executed as long as $nodes is defined.
# I'm leaving it there because it has always been there, and although I'm sure it was originally meant to
# mean %$searchParameters (essentially "is this hash not empty"), I'm afraid to change it.
if ( $nodes && $searchParameters != {} )
{

其他回答

// TODO: Delete

大学时代:

//why the f*** we have to move this here to make it work

当我们和教授一起复习的时候,它在印刷资料中被突出了。

原因是:一些与缓冲区溢出相关的严重错误,影响了代码中其他位置的文件处理程序中不相关的变量。移动变量将使它再次工作。

// TODO: Drive an ashen stake through the foul heart of this function.

这是一个糟糕的函数。直到今天我还在做噩梦。

不是在代码中,而是在相关的bug跟踪系统中:

这不可能是我代码中的bug。我非常小心地编码。

我不知道这是有趣还是悲伤..但是和我一起工作的一个实习生有这个小宝石来计算每个单位的价格

...

// get the units from the form 
int numUnits = Integer.parseInt(request.getParameter("num_pieces")); // this break at random times

//price 
float price = Float.parseFloat(request.getParameter("price")); // same as above

// Under certain conditions the following code blows up. I don't know those conditions.
float pricePerUnit = price / (float)numUnits;

...