# There is a bug in the next line.  $searchParameters != {} will always return true, because {} is creating
# a new hash reference on the fly, and the inequality operater is comparing the memory location of it
# to the memory location of $searchParameters, and they will always be different. 
# This means that the following code will always get executed as long as $nodes is defined.
# I'm leaving it there because it has always been there, and although I'm sure it was originally meant to
# mean %$searchParameters (essentially "is this hash not empty"), I'm afraid to change it.
if ( $nodes && $searchParameters != {} )
{

在初始化链表时:

last = first; /* Biblical reference */

简洁而滑稽。

有一次，我在另一个讨论中看到这样的内容:

// I can't divide with zero, so I have to divide with something very similar
result = number / 0.00000000000001;

聪明的解决方案，不是吗?(如果有人不确定，这就是个笑话)

//If you're reading this, then my program is probably a success

不是一个评论，而是一个goto标签

ICantBelieveImUsingAGoto:

从谷歌代码项目:

# This job would be great if it wasn't for the fucking customers.