我在操场上做了一些实验，得到了一些结论。

博士TL;

如您所见，在类的情况下，使用类func还是静态func只是一个习惯问题。

游乐场的例子，并附有解释:

class Dog {
    final func identity() -> String {
        return "Once a woofer, forever a woofer!"
    }

    class func talk() -> String {
        return "Woof woof!"
    }

    static func eat() -> String {
        return "Miam miam"
    }

    func sleep() -> String {
        return "Zzz"
    }
}

class Bulldog: Dog {
    // Can not override a final function
//    override final func identity() -> String {
//        return "I'm once a dog but now I'm a cat"
//    }

    // Can not override a "class func", but redeclare is ok
    func talk() -> String {
        return "I'm a bulldog, and I don't woof."
    }

    // Same as "class func"
    func eat() -> String {
        return "I'm a bulldog, and I don't eat."
    }

    // Normal function can be overridden
    override func sleep() -> String {
        return "I'm a bulldog, and I don't sleep."
    }
}

let dog = Dog()
let bullDog = Bulldog()

// FINAL FUNC
//print(Dog.identity()) // compile error
print(dog.identity()) // print "Once a woofer, forever a woofer!"
//print(Bulldog.identity()) // compile error
print(bullDog.identity()) // print "Once a woofer, forever a woofer!"

// => "final func" is just a "normal" one but prevented to be overridden nor redeclared by subclasses.


// CLASS FUNC
print(Dog.talk()) // print "Woof woof!", called directly from class
//print(dog.talk()) // compile error cause "class func" is meant to be called directly from class, not an instance.
print(Bulldog.talk()) // print "Woof woof!" cause it's called from Bulldog class, not bullDog instance.
print(bullDog.talk()) // print "I'm a bulldog, and I don't woof." cause talk() is redeclared and it's called from bullDig instance

// => "class func" is like a "static" one, must be called directly from class or subclassed, can be redeclared but NOT meant to be overridden.

// STATIC FUNC
print(Dog.eat()) // print "Miam miam"
//print(dog.eat()) // compile error cause "static func" is type method
print(Bulldog.eat()) // print "Miam miam"
print(bullDog.eat()) // print "I'm a bulldog, and I don't eat."

// NORMAL FUNC
//print(Dog.sleep()) // compile error
print(dog.sleep()) // print "Zzz"
//print(Bulldog.sleep()) // compile error
print(bullDog.sleep()) // print "I'm a bulldog, and I don't sleep."

是不是简单地说，static是用于结构体和枚举的静态函数，class是用于类和协议?

这是主要的区别。其他一些不同之处在于类函数是动态分派的，并且可以被子类覆盖。

协议使用class关键字，但它不排除实现协议的结构，而是使用static。Class是为协议选择的，这样就不需要第三个关键字来表示静态或类。

下面是克里斯·拉特纳对这个话题的看法:

我们考虑统一语法(例如使用“type”作为关键字)，但这实际上并不能简化事情。关键字“类”和“静态”有助于熟悉并具有相当的描述性(一旦您理解了+方法的工作方式)，并为潜在地向类添加真正的静态方法打开了大门。这个模型的主要奇怪之处在于协议必须选择一个关键字(我们选择了“类”)，但总的来说，这是正确的权衡。

下面是一个片段，展示了类函数的一些重写行为:

class MyClass {
    class func myFunc() {
        println("myClass")
    }
}

class MyOtherClass: MyClass {
    override class func myFunc() {
        println("myOtherClass")
    }
}

var x: MyClass = MyOtherClass()
x.dynamicType.myFunc() //myOtherClass
x = MyClass()
x.dynamicType.myFunc() //myClass

这个例子将清楚每一个方面!

import UIKit

class Parent {
    final func finalFunc() -> String { // Final Function, cannot be redeclared.
        return "Parent Final Function."
    }

    static func staticFunc() -> String { // Static Function, can be redeclared.
        return "Parent Static Function."
    }

    func staticFunc() -> String { // Above function redeclared as Normal function.
        return "Parent Static Function, redeclared with same name but as non-static(normal) function."
    }

    class func classFunc() -> String { // Class Function, can be redeclared.
        return "Parent Class Function."
    }

    func classFunc() -> String { // Above function redeclared as Normal function.
        return "Parent Class Function, redeclared with same name but as non-class(normal) function."
    }

    func normalFunc() -> String { // Normal function, obviously cannot be redeclared.
        return "Parent Normal Function."
    }
}

class Child:Parent {

    // Final functions cannot be overridden.

    override func staticFunc() -> String { // This override form is of the redeclared version i.e: "func staticFunc()" so just like any other function of normal type, it can be overridden.
        return "Child Static Function redeclared and overridden, can simply be called Child Normal Function."
    }

    override class func classFunc() -> String { // Class function, can be overidden.
        return "Child Class Function."
    }

    override func classFunc() -> String { // This override form is of the redeclared version i.e: "func classFunc()" so just like any other function of normal type, it can be overridden.
        return "Child Class Function, redeclared and overridden, can simply be called Child Normal Function."
    }

    override func normalFunc() -> String { // Normal function, can be overridden.
        return "Child Normal Function."
    }
}

let parent = Parent()
let child = Child()

// Final
print("1. " + parent.finalFunc())   // 1. Can be called by object.
print("2. " + child.finalFunc())    // 2. Can be called by object, parent(final) function will be called.
// Parent.finalFunc()               // Cannot be called by class name directly.
// Child.finalFunc()                // Cannot be called by class name directly.

// Static
print("3. " + parent.staticFunc())  // 3. Cannot be called by object, this is redeclared version (i.e: a normal function).
print("4. " + child.staticFunc())   // 4. Cannot be called by object, this is override form redeclared version (normal function).
print("5. " + Parent.staticFunc())  // 5. Can be called by class name directly.
print("6. " + Child.staticFunc())   // 6. Can be called by class name direcly, parent(static) function will be called.

// Class
print("7. " + parent.classFunc())   // 7. Cannot be called by object, this is redeclared version (i.e: a normal function).
print("8. " + child.classFunc())    // 8. Cannot be called by object, this is override form redeclared version (normal function).
print("9. " + Parent.classFunc())   // 9. Can be called by class name directly.
print("10. " + Child.classFunc())   // 10. Can be called by class name direcly, child(class) function will be called.

// Normal
print("11. " + parent.normalFunc())  // 11. Can be called by object.
print("12. " + child.normalFunc())   // 12. Can be called by object, child(normal) function will be called.
// Parent.normalFunc()               // Cannot be called by class name directly.
// Child.normalFunc()                // Cannot be called by class name directly.

/*
 Notes:
 ___________________________________________________________________________
 |Types------Redeclare------Override------Call by object------Call by Class|
 |Final----------0--------------0---------------1------------------0-------|
 |Static---------1--------------0---------------0------------------1-------|
 |Class----------1--------------1---------------0------------------1-------|
 |Normal---------0--------------1---------------1------------------0-------|
 ---------------------------------------------------------------------------

 Final vs Normal function: Both are same but normal methods can be overridden.
 Static vs Class function: Both are same but class methods can be overridden.
 */

输出:

这被称为类型方法，并且像实例方法一样使用点语法调用。但是，在类型上调用类型方法，而不是在该类型的实例上调用类型方法。下面是如何在一个名为SomeClass的类上调用类型方法:

若要声明类型变量属性，请使用静态声明修饰符标记声明。类可以用类声明修饰符标记类型计算属性，以允许子类重写超类的实现。类型属性在类型属性中讨论。 请注意 在类声明中，关键字static与同时使用类和final声明修饰符标记声明具有相同的效果。

来源:Swift编程语言-类型变量属性

static和class关键字都允许我们将方法附加到类而不是类的实例。例如，您可以创建一个具有名称和年龄等属性的Student类，然后创建一个静态方法numberOfStudents，该方法由Student类本身而不是单个实例拥有。

静态和类的不同之处在于它们支持继承的方式。当你创建一个静态方法时，它被类拥有，不能被子类改变，而当你使用类时，它可能会在需要时被覆盖。

下面是一个示例代码:

class Vehicle {
    static func getCurrentSpeed() -> Int {
        return 0
    }
    
    class func getCurrentNumberOfPassengers() -> Int {
        return 0
    } 
}

class Bicycle: Vehicle {
    //This is not allowed
    //Compiler error: "Cannot override static method"
    //static override func getCurrentSpeed() -> Int {
        //return 15
    //}
    
    class override func getCurrentNumberOfPassengers() -> Int {
        return 1
    }
}