我真的不想每次都输入\n， @matthause的答案似乎不适合我，所以我创建了自己的类

class File():

    def __init__(self, name, mode='w'):
        self.f = open(name, mode, buffering=1)
        
    def write(self, string, newline=True):
        if newline:
            self.f.write(string + '\n')
        else:
            self.f.write(string)

这就是它的实现

f = File('console.log')

f.write('This is on the first line')
f.write('This is on the second line', newline=False)
f.write('This is still on the second line')
f.write('This is on the third line')

这应该在日志文件中显示为

This is on the first line
This is on the second lineThis is still on the second line
This is on the third line

你可以在需要这种行为的特定地方装饰方法write:

#Changed behavior is localized to single place.
with open('test1.txt', 'w') as file:    
    def decorate_with_new_line(method):
        def decorated(text):
            method(f'{text}\n')
        return decorated
    file.write = decorate_with_new_line(file.write)
    
    file.write('This will be on line 1')
    file.write('This will be on line 2')
    file.write('This will be on line 3')

#Standard behavior is not affected. No class was modified.
with open('test2.txt', 'w') as file:
        
    file.write('This will be on line 1')
    file.write('This will be on line 1')
    file.write('This will be on line 1')  

我真的不想每次都输入\n， @matthause的答案似乎不适合我，所以我创建了自己的类

class File():

    def __init__(self, name, mode='w'):
        self.f = open(name, mode, buffering=1)
        
    def write(self, string, newline=True):
        if newline:
            self.f.write(string + '\n')
        else:
            self.f.write(string)

这就是它的实现

f = File('console.log')

f.write('This is on the first line')
f.write('This is on the second line', newline=False)
f.write('This is still on the second line')
f.write('This is on the third line')

这应该在日志文件中显示为

This is on the first line
This is on the second lineThis is still on the second line
This is on the third line

你可以这样做:

file.write(your_string + '\n')

正如另一个答案所建议的，但为什么在可以调用文件时使用字符串连接(缓慢，容易出错)。写两次:

file.write(your_string)
file.write("\n")

注意，写操作是被缓冲的，所以两者是一样的。

你可以通过两种方式做到这一点:

f.write("text to write\n")

或者，取决于你的Python版本(2或3):

print >>f, "text to write"         # Python 2.x
print("text to write", file=f)     # Python 3.x

这是我自己想出来的解决方法为了系统地产生n作为分离器。它使用一个字符串列表，其中每个字符串是文件的一行，但它似乎也可以为您工作。(Python 3 +)。

#Takes a list of strings and prints it to a file.
def writeFile(file, strList):
    line = 0
    lines = []
    while line < len(strList):
        lines.append(cheekyNew(line) + strList[line])
        line += 1
    file = open(file, "w")
    file.writelines(lines)
    file.close()

#Returns "\n" if the int entered isn't zero, otherwise "".
def cheekyNew(line):
    if line != 0:
        return "\n"
    return ""