Import java.util.*;

String array1[] = {"bla","bla"};
String array2[] = {"bla","bla"};

ArrayList<String> tempArray = new ArrayList<String>(Arrays.asList(array1));
tempArray.addAll(Arrays.asList(array2));
String array3[] = films.toArray(new String[1]); // size will be overwritten if needed

您可以用自己喜欢的类型/类替换字符串

我确信这可以做得更短更好，但它很有效，我懒得进一步整理。。。

如果您想在解决方案中使用ArrayList，可以尝试以下操作：

public final String [] f(final String [] first, final String [] second) {
    // Assuming non-null for brevity.
    final ArrayList<String> resultList = new ArrayList<String>(Arrays.asList(first));
    resultList.addAll(new ArrayList<String>(Arrays.asList(second)));
    return resultList.toArray(new String [resultList.size()]);
}

FunctionalJava库有一个数组包装器类，它为数组提供了方便的方法，如串联。

import static fj.data.Array.array;

…然后

Array<String> both = array(first).append(array(second));

要取回展开的数组，请调用

String[] s = both.array();

我从老的Apache Commons Lang库中找到了一个单行解决方案。ArrayUtils.addAll（T[]，T…）

代码：

String[] both = ArrayUtils.addAll(first, second);

Object[] obj = {"hi","there"};
Object[] obj2 ={"im","fine","what abt u"};
Object[] obj3 = new Object[obj.length+obj2.length];

for(int i =0;i<obj3.length;i++)
    obj3[i] = (i<obj.length)?obj[i]:obj2[i-obj.length];

这是可行的，但您需要插入自己的错误检查。

public class StringConcatenate {

    public static void main(String[] args){

        // Create two arrays to concatenate and one array to hold both
        String[] arr1 = new String[]{"s","t","r","i","n","g"};
        String[] arr2 = new String[]{"s","t","r","i","n","g"};
        String[] arrBoth = new String[arr1.length+arr2.length];

        // Copy elements from first array into first part of new array
        for(int i = 0; i < arr1.length; i++){
            arrBoth[i] = arr1[i];
        }

        // Copy elements from second array into last part of new array
        for(int j = arr1.length;j < arrBoth.length;j++){
            arrBoth[j] = arr2[j-arr1.length];
        }

        // Print result
        for(int k = 0; k < arrBoth.length; k++){
            System.out.print(arrBoth[k]);
        }

        // Additional line to make your terminal look better at completion!
        System.out.println();
    }
}

它可能不是最有效的，但除了Java自己的API之外，它不依赖其他任何东西。