我需要在Java中连接两个字符串数组。

void f(String[] first, String[] second) {
    String[] both = ???
}

哪种方法最简单?


当前回答

应该会成功的。这是假设String[]第一个,String[]第二个

List<String> myList = new ArrayList<String>(Arrays.asList(first));
myList.addAll(new ArrayList<String>(Arrays.asList(second)));
String[] both = myList.toArray(new String[myList.size()]);

其他回答

    void f(String[] first, String[] second) {
    String[] both = new String[first.length+second.length];
    for(int i=0;i<first.length;i++)
        both[i] = first[i];
    for(int i=0;i<second.length;i++)
        both[first.length + i] = second[i];
}

这一个在不了解任何其他类/库等的情况下工作。它适用于任何数据类型。只需将String替换为int、double或char等任意值。它的工作效率很高。

这是可行的,但您需要插入自己的错误检查。

public class StringConcatenate {

    public static void main(String[] args){

        // Create two arrays to concatenate and one array to hold both
        String[] arr1 = new String[]{"s","t","r","i","n","g"};
        String[] arr2 = new String[]{"s","t","r","i","n","g"};
        String[] arrBoth = new String[arr1.length+arr2.length];

        // Copy elements from first array into first part of new array
        for(int i = 0; i < arr1.length; i++){
            arrBoth[i] = arr1[i];
        }

        // Copy elements from second array into last part of new array
        for(int j = arr1.length;j < arrBoth.length;j++){
            arrBoth[j] = arr2[j-arr1.length];
        }

        // Print result
        for(int k = 0; k < arrBoth.length; k++){
            System.out.print(arrBoth[k]);
        }

        // Additional line to make your terminal look better at completion!
        System.out.println();
    }
}

它可能不是最有效的,但除了Java自己的API之外,它不依赖其他任何东西。

只是想添加,您也可以使用System.arraycopy:

import static java.lang.System.out;
import static java.lang.System.arraycopy;
import java.lang.reflect.Array;
class Playground {
    @SuppressWarnings("unchecked")
    public static <T>T[] combineArrays(T[] a1, T[] a2) {
        T[] result = (T[]) Array.newInstance(a1.getClass().getComponentType(), a1.length+a2.length);
        arraycopy(a1,0,result,0,a1.length);
        arraycopy(a2,0,result,a1.length,a2.length);
        return result;
    }
    public static void main(String[ ] args) {
        String monthsString = "JANFEBMARAPRMAYJUNJULAUGSEPOCTNOVDEC";
        String[] months = monthsString.split("(?<=\\G.{3})");
        String daysString = "SUNMONTUEWEDTHUFRISAT";
        String[] days = daysString.split("(?<=\\G.{3})");
        for (String m : months) {
            out.println(m);
        }
        out.println("===");
         for (String d : days) {
            out.println(d);
        }
        out.println("===");
        String[] results = combineArrays(months, days);
        for (String r : results) {
            out.println(r);
        }
        out.println("===");
    }
}
public String[] concat(String[]... arrays)
{
    int length = 0;
    for (String[] array : arrays) {
        length += array.length;
    }
    String[] result = new String[length];
    int destPos = 0;
    for (String[] array : arrays) {
        System.arraycopy(array, 0, result, destPos, array.length);
        destPos += array.length;
    }
    return result;
}

我刚刚发现了这个问题,很抱歉,很晚了,我看到了很多太遥远的答案,使用某些库,使用将数据从数组转换为流并返回到数组等功能。但是,我们只需要使用一个简单的循环,问题就解决了

public String[] concat(String[] firstArr,String[] secondArr){
        //if both is empty just return
        if(firstArr.length==0 && secondArr.length==0)return new String[0];

        String[] res = new String[firstArr.length+secondArr.length];
        int idxFromFirst=0;

        //loop over firstArr, idxFromFirst will be used as starting offset for secondArr
        for(int i=0;i<firstArr.length;i++){
            res[i] = firstArr[i];
            idxFromFirst++;
        }

        //loop over secondArr, with starting offset idxFromFirst (the offset track from first array)
        for(int i=0;i<secondArr.length;i++){
            res[idxFromFirst+i]=secondArr[i];
        }

        return res;
    }

就这样,对吧?他没有说他关心订单或任何事情。这应该是最简单的方法。