创建和初始化对象数组的另一种方法。这与上面@Amol发布的示例类似，只是这一个使用了构造函数。一点点多态性洒了进来，我无法抗拒。

IUser[] userArray = new IUser[]
{
    new DummyUser("abc@cde.edu", "Gibberish"),
    new SmartyUser("pga@lna.it", "Italian", "Engineer")
};

上下文类：

interface IUser
{
    string EMail { get; }       // immutable, so get only an no set
    string Language { get; }
}

public class DummyUser : IUser
{
    public DummyUser(string email, string language)
    {
        m_email = email;
        m_language = language;
    }

    private string m_email;
    public string EMail
    {
        get { return m_email; }
    }

    private string m_language;
    public string Language
    {
        get { return m_language; }
    }
}

public class SmartyUser : IUser
{
    public SmartyUser(string email, string language, string occupation)
    {
        m_email = email;
        m_language = language;
        m_occupation = occupation;
    }

    private string m_email;
    public string EMail
    {
        get { return m_email; }
    }

    private string m_language;
    public string Language
    {
        get { return m_language; }
    }

    private string m_occupation;
}

只是一张纸条

以下阵列：

string[] array = new string[2];
string[] array2 = new string[] { "A", "B" };
string[] array3 = { "A" , "B" };
string[] array4 = new[] { "A", "B" };

将编译为：

string[] array = new string[2];
string[] array2 = new string[] { "A", "B" };
string[] array3 = new string[] { "A", "B" };
string[] array4 = new string[] { "A", "B" };

非空数组

var data0=新int[3]var data1=新int[3]｛1，2，3｝var data2=新int[]｛1，2，3｝var data3=新[]｛1，2，3｝var data4={1，2，3}不可编译。请改用int[]data5＝｛1，2，3｝。

空数组

var data6=新int[0]var data7=新int[]｛｝vardata8=new[]｛｝和int[]data9=new[]｝不可编译。var data10={}不可编译。请改用int[]data11={}。

作为方法的参数

只有可以指定var关键字的表达式才能作为参数传递。

Foo（新int[2]）Foo（新int[2]｛1，2｝）Foo（新int[]｛1，2｝）Foo（新[]｛1，2｝）Foo（｛1，2｝）不可编译Foo（新int[0]）Foo（新int[]｛｝）Foo（｛｝）不可编译

var contacts = new[]
{
    new 
    {
        Name = " Eugene Zabokritski",
        PhoneNumbers = new[] { "206-555-0108", "425-555-0001" }
    },
    new 
    {
        Name = " Hanying Feng",
        PhoneNumbers = new[] { "650-555-0199" }
    }
};

带有表达式的平凡解决方案。注意，使用NewArrayInit，您可以只创建一维数组。

NewArrayExpression expr = Expression.NewArrayInit(typeof(int), new[] { Expression.Constant(2), Expression.Constant(3) });
int[] array = Expression.Lambda<Func<int[]>>(expr).Compile()(); // compile and call callback

int[] array = new int[4]; 
array[0] = 10;
array[1] = 20;
array[2] = 30;

or

string[] week = new string[] {"Sunday","Monday","Tuesday"};

or

string[] array = { "Sunday" , "Monday" };

并且在多维阵列中

    Dim i, j As Integer
    Dim strArr(1, 2) As String

    strArr(0, 0) = "First (0,0)"
    strArr(0, 1) = "Second (0,1)"

    strArr(1, 0) = "Third (1,0)"
    strArr(1, 1) = "Fourth (1,1)"