我如何才能最好地编写一个查询,从总共600k中随机选择10行?


当前回答

我改进了@Riedsio的答案。这是我在一个有间隙的大型均匀分布表上能找到的最有效的查询(测试从一个有> 2.6B行的表中获得1000个随机行)。

(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max := (SELECT MAX(id) FROM table)) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
(SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1)

让我来解释一下发生了什么。

(SELECT MAX(id) FROM table) 我在计算并保存最大值。对于非常大的表,每次需要一行时计算MAX(id)都会有轻微的开销 SELECT FLOOR(rand() * @max) + 1 as rand) 获取一个随机id SELECT id FROM table INNER JOIN(… 这就填补了空白。基本上,如果你在间隙中随机选择一个数字,它就会选择下一个id。假设间隙是均匀分布的,这应该不是问题。

进行联合可以帮助您将所有内容放入一个查询中,从而避免进行多个查询。它还可以节省计算MAX(id)的开销。根据您的应用程序,这可能非常重要,也可能无关紧要。

注意,这只获取id,并以随机顺序获取它们。如果你想做更高级的事情,我建议你这样做:

SELECT t.id, t.name -- etc, etc
FROM table t
INNER JOIN (
    (SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max := (SELECT MAX(id) FROM table)) + 1 as rand) r on id > rand LIMIT 1) UNION
    (SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
    (SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
    (SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
    (SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
    (SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
    (SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
    (SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
    (SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1) UNION
    (SELECT id FROM table INNER JOIN (SELECT FLOOR(RAND() * @max) + 1 as rand) r on id > rand LIMIT 1)
) x ON x.id = t.id
ORDER BY t.id

其他回答

SELECT
  * 
FROM
  table_with_600k_rows
WHERE
  RAND( ) 
ORDER BY
  id DESC 
LIMIT 30;

Id是主键,按Id排序, 解释table_with_600k_rows,发现该行不扫描整个表

我想这是最好的办法了。

SELECT id, id * RAND( ) AS random_no, first_name, last_name
FROM user
ORDER BY random_no

使用这个查询:

select floor(RAND() * (SELECT MAX(key) FROM table)) from table limit 10

查询时间:0.016秒

我知道这不是你想要的,但我将给你的答案是我在一个小网站的生产中使用的。

根据您访问随机值的次数,不值得使用MySQL,因为您将无法缓存答案。我们在那里有一个按钮来访问一个随机页面,用户可以每分钟点击几次,如果他愿意的话。这将导致MySQL的大量使用,至少对我来说,MySQL是优化的最大问题。

我会采用另一种方法,你可以把答案存储在缓存中。调用MySQL:

SELECT min(id) as min, max(id) as max FROM your_table

使用min和max Id,您可以在服务器中计算一个随机数。在python中:

random.randint(min, max)

然后,用你的随机数,你可以在你的表中得到一个随机Id:

SELECT * 
FROM your_table 
WHERE id >= %s 
ORDER BY id ASC 
LIMIT 1

在这种方法中,对数据库执行两次调用,但是可以缓存它们,并且在很长一段时间内不访问数据库,从而提高性能。注意,如果表中有洞,这不是随机的。有超过一行很容易,因为你可以使用python创建Id,并为每行执行一个请求,但由于它们是缓存的,这是可以的。

如果你的表中有太多的洞,你可以尝试同样的方法,但是现在是记录的总数:

SELECT COUNT(*) as total FROM your_table

然后在python中你可以这样写:

random.randint(0, total)

为了获取一个随机结果,你可以使用如下所示的LIMIT:

SELECT * 
FROM your_table 
ORDER BY id ASC 
LIMIT %s, 1

注意它会在X个随机行之后得到1个值。即使您的表中有洞,它也将是完全随机的,但它将为您的数据库带来更多的开销。

另一个简单的解决方案是对行进行排名,并随机获取其中之一,有了这个解决方案,你将不需要在表中有任何基于“Id”的列。

SELECT d.* FROM (
SELECT  t.*,  @rownum := @rownum + 1 AS rank
FROM mytable AS t,
    (SELECT @rownum := 0) AS r,
    (SELECT @cnt := (SELECT RAND() * (SELECT COUNT(*) FROM mytable))) AS n
) d WHERE rank >= @cnt LIMIT 10;

您可以根据需要更改限制值,以便访问尽可能多的行,但大多数情况下是连续的值。

然而,如果你不想要连续的随机值,那么你可以获取一个更大的样本并从中随机选择。就像……

SELECT * FROM (
SELECT d.* FROM (
    SELECT  c.*,  @rownum := @rownum + 1 AS rank
    FROM buildbrain.`commits` AS c,
        (SELECT @rownum := 0) AS r,
        (SELECT @cnt := (SELECT RAND() * (SELECT COUNT(*) FROM buildbrain.`commits`))) AS rnd
) d 
WHERE rank >= @cnt LIMIT 10000 
) t ORDER BY RAND() LIMIT 10;