在上面adamJLev的精彩回答的基础上，下面是TypeScript版本:

// Extending String prototype
interface String {
    format(...params: any[]): string;
}

// Variable number of params, mimicking C# params keyword
// params type is set to any so consumer can pass number
// or string, might be a better way to constraint types to
// string and number only using generic?
String.prototype.format = function (...params: any[]) {
    var s = this,
        i = params.length;

    while (i--) {
        s = s.replace(new RegExp('\\{' + i + '\\}', 'gm'), params[i]);
    }

    return s;
};

在上面adamJLev的精彩回答的基础上，下面是TypeScript版本:

// Extending String prototype
interface String {
    format(...params: any[]): string;
}

// Variable number of params, mimicking C# params keyword
// params type is set to any so consumer can pass number
// or string, might be a better way to constraint types to
// string and number only using generic?
String.prototype.format = function (...params: any[]) {
    var s = this,
        i = params.length;

    while (i--) {
        s = s.replace(new RegExp('\\{' + i + '\\}', 'gm'), params[i]);
    }

    return s;
};

这是Josh发布的函数的一个更快/更简单(和原型)的变体:

String.prototype.format = String.prototype.f = function() {
    var s = this,
        i = arguments.length;

    while (i--) {
        s = s.replace(new RegExp('\\{' + i + '\\}', 'gm'), arguments[i]);
    }
    return s;
};

用法:

'Added {0} by {1} to your collection'.f(title, artist)
'Your balance is {0} USD'.f(77.7) 

我经常使用它，所以我把它的别名改成了f，但是你也可以使用更详细的格式。如。“你好,{0}!”.format(名字)

使用支持EcmaScript 2015 (ES6)的现代浏览器，您可以享受模板字符串。而不是格式化，你可以直接注入变量值:

var name = "Waleed";
var message = `Hello ${name}!`;

注意模板字符串必须使用反勾号(')来编写。

下面是我的版本，它能够转义'{'，并清除那些未分配的占位符。

function getStringFormatPlaceHolderRegEx(placeHolderIndex) {
    return new RegExp('({)?\\{' + placeHolderIndex + '\\}(?!})', 'gm')
}

function cleanStringFormatResult(txt) {
    if (txt == null) return "";

    return txt.replace(getStringFormatPlaceHolderRegEx("\\d+"), "");
}

String.prototype.format = function () {
    var txt = this.toString();
    for (var i = 0; i < arguments.length; i++) {
        var exp = getStringFormatPlaceHolderRegEx(i);
        txt = txt.replace(exp, (arguments[i] == null ? "" : arguments[i]));
    }
    return cleanStringFormatResult(txt);
}
String.format = function () {
    var s = arguments[0];
    if (s == null) return "";

    for (var i = 0; i < arguments.length - 1; i++) {
        var reg = getStringFormatPlaceHolderRegEx(i);
        s = s.replace(reg, (arguments[i + 1] == null ? "" : arguments[i + 1]));
    }
    return cleanStringFormatResult(s);
}

如果你正在使用验证插件，你可以使用:

jQuery.validator。Format ("{0} {1}"， "cool"， "formatting") = 'cool formatting'

http://docs.jquery.com/Plugins/Validation/jQuery.validator.format templateargumentargumentN……