我使用jQuery。点击来处理Raphael图形上的鼠标点击事件,同时,我需要处理鼠标拖动事件,鼠标拖动在Raphael中由鼠标下拉,鼠标上拉和鼠标移动组成。

很难区分点击和拖动,因为点击也包含鼠标下拉和鼠标上拉,我怎么能区分鼠标“点击”和鼠标“拖动”然后在Javascript?


当前回答

来自@Przemek的回答,

函数listenClickOnly(元素,回调,阈值=10){ 让拖动= 0; 元素。addEventListener('mousedown', () => drag = 0); 元素。addEventListener('mousemove', () => drag++); 元素。addEventListener('mouseup', e => { 如果(拖动<阈值)回调(e); }); } listenClickOnly ( 文档, () => console.log('click'), 10 );

其他回答

如果你想使用Rxjs:

var element = document; Rx.Observable .merge( Rx.Observable.fromEvent(element, 'mousedown').mapTo(0), Rx.Observable.fromEvent(element, 'mousemove').mapTo(1) ) .sample(Rx.Observable.fromEvent(element, 'mouseup')) .subscribe(flag => { console.clear(); console.log(flag ? "drag" : "click"); }); <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <script src="https://unpkg.com/@reactivex/rxjs@5.4.1/dist/global/Rx.js"></script>

这是@wong2在他的回答中所做的直接克隆,但转换为RxJs。

样本的使用也很有趣。示例操作符将从源(mousedown和mousemove的合并)中获取最新的值,并在内部观察对象(mouseup)发出时发出它。

使用jQuery和5像素x/y暂停来检测拖动:

var dragging = false;
$("body").on("mousedown", function(e) {
  var x = e.screenX;
  var y = e.screenY;
  dragging = false;
  $("body").on("mousemove", function(e) {
    if (Math.abs(x - e.screenX) > 5 || Math.abs(y - e.screenY) > 5) {
      dragging = true;
    }
  });
});
$("body").on("mouseup", function(e) {
  $("body").off("mousemove");
  console.log(dragging ? "drag" : "click");
});

有同样的问题,最近在一个树列表中,用户可以点击项目或拖动它,使这个小指针类,并把它放在我的utils.js

function Pointer(threshold = 10) {
  let x = 0;
  let y = 0;

  return {
    start(e) {
     x = e.clientX;
     y = e.clientY;
    },

    isClick(e) {
      const deltaX = Math.abs(e.clientX - x);
      const deltaY = Math.abs(e.clientY - y);
      return deltaX < threshold && deltaY < threshold;
    }
  }
}

下面你可以看到它的工作原理:

function Pointer(threshold = 10) { let x = 0; let y = 0; return { start(e) { x = e.clientX; y = e.clientY; }, isClick(e) { const deltaX = Math.abs(e.clientX - x); const deltaY = Math.abs(e.clientY - y); return deltaX < threshold && deltaY < threshold; } } } const pointer = new Pointer(); window.addEventListener('mousedown', (e) => pointer.start(e)) //window.addEventListener('mousemove', (e) => pointer.last(e)) window.addEventListener('mouseup', (e) => { const operation = pointer.isClick(e) ? "Click" : "Drag" console.log(operation) })

纯JS与DeltaX和delay

这个DeltaX和delay是由接受的答案中的评论所建议的,以避免由于鼠标移动一划而试图单击并获得拖动操作时的令人沮丧的体验。

    deltaX = deltaY = 2;//px
    var element = document.getElementById('divID');
    element.addEventListener("mousedown", function(e){
        if (typeof InitPageX == 'undefined' && typeof InitPageY == 'undefined') {
            InitPageX = e.pageX;
            InitPageY = e.pageY;
        }

    }, false);
    element.addEventListener("mousemove", function(e){
        if (typeof InitPageX !== 'undefined' && typeof InitPageY !== 'undefined') {
            diffX = e.pageX - InitPageX;
            diffY = e.pageY - InitPageY;
            if (    (diffX > deltaX) || (diffX < -deltaX)
                    || 
                    (diffY > deltaY) || (diffY < -deltaY)   
                    ) {
                console.log("dragging");//dragging event or function goes here.
            }
            else {
                console.log("click");//click event or moving back in delta goes here.
            }
        }
    }, false);
    element.addEventListener("mouseup", function(){
        delete InitPageX;
        delete InitPageY;
    }, false);

   element.addEventListener("click", function(){
        console.log("click");
    }, false);

正如mrjrdnthms在他对接受的答案的评论中指出的那样,这不再适用于Chrome(它总是触发鼠标移动),我已经改编了Gustavo的答案(因为我使用jQuery)来解决Chrome的行为。

var currentPos = [];

$(document).on('mousedown', function (evt) {

   currentPos = [evt.pageX, evt.pageY]

  $(document).on('mousemove', function handler(evt) {

    currentPos=[evt.pageX, evt.pageY];
    $(document).off('mousemove', handler);

  });

  $(document).on('mouseup', function handler(evt) {

    if([evt.pageX, evt.pageY].equals(currentPos))
      console.log("Click")
    else
      console.log("Drag")

    $(document).off('mouseup', handler);

  });

});

Array.prototype.equals函数来自这个答案