我怎样才能得到字符串的第n个字符?我尝试了括号([])访问器,没有运气。

var string = "Hello, world!"

var firstChar = string[0] // Throws error

错误:'下标'是不可用的:不能下标String与Int,请参阅文档注释讨论


当前回答

到目前为止,下标(_:)不可用。就像我们不能这么做一样

str[0] 

与字符串。我们必须提供"String "。指数” 但是,我们如何给出我们自己的索引号呢,我们可以用,

string[str.index(str.startIndex, offsetBy: 0)]

其他回答

Swift 3:另一个解决方案(在操场测试)

extension String {
    func substr(_ start:Int, length:Int=0) -> String? {
        guard start > -1 else {
            return nil
        }

        let count = self.characters.count - 1

        guard start <= count else {
            return nil
        }

        let startOffset = max(0, start)
        let endOffset = length > 0 ? min(count, startOffset + length - 1) : count

        return self[self.index(self.startIndex, offsetBy: startOffset)...self.index(self.startIndex, offsetBy: endOffset)]
    }
}

用法:

let txt = "12345"

txt.substr(-1) //nil
txt.substr(0) //"12345"
txt.substr(0, length: 0) //"12345"
txt.substr(1) //"2345"
txt.substr(2) //"345"
txt.substr(3) //"45"
txt.substr(4) //"5"
txt.substr(6) //nil
txt.substr(0, length: 1) //"1"
txt.substr(1, length: 1) //"2"
txt.substr(2, length: 1) //"3"
txt.substr(3, length: 1) //"4"
txt.substr(3, length: 2) //"45"
txt.substr(3, length: 3) //"45"
txt.substr(4, length: 1) //"5"
txt.substr(4, length: 2) //"5"
txt.substr(5, length: 1) //nil
txt.substr(5, length: -1) //nil
txt.substr(-1, length: -1) //nil

我的解决方法很简单:

斯威夫特4.1:

let myString = "Test string"
let index = 0
let firstCharacter = myString[String.Index(encodedOffset: index)]

斯威夫特5.1:

let firstCharacter = myString[String.Index.init(utf16Offset: index, in: myString)]

一个类似蟒蛇的解决方案,允许你使用负下标,

var str = "Hello world!"
str[-1]        // "!"

可能是:

extension String {
    subscript (var index:Int)->Character{
        get {
            let n = distance(self.startIndex, self.endIndex)
            index %= n
            if index < 0 { index += n }
            return self[advance(startIndex, index)]
        }
    }
}

顺便说一下,调换整个python的切片符号可能是值得的

Swift 2.0的Xcode 7通用种子

var text = "Hello, world!"

let firstChar = text[text.startIndex.advancedBy(0)] // "H"

对于第n个字符,将0替换为n-1。

编辑:Swift 3.0

text[text.index(text.startIndex, offsetBy: 0)]

注意,有更简单的方法来获取字符串中的某些字符

例如:let firstChar = text.characters.first

斯威夫特5.1

这可能是所有答案中最简单的一个。

添加这个扩展:

extension String {
    func retrieveFirstCharacter() -> String? {
        guard self.count > 0 else { return nil }
        let numberOfCharacters = self.count
        return String(self.dropLast(numberOfCharacters - 1))
    }
}