我怎样才能得到字符串的第n个字符?我尝试了括号([])访问器,没有运气。
var string = "Hello, world!"
var firstChar = string[0] // Throws error
错误:'下标'是不可用的:不能下标String与Int,请参阅文档注释讨论
我怎样才能得到字符串的第n个字符?我尝试了括号([])访问器,没有运气。
var string = "Hello, world!"
var firstChar = string[0] // Throws error
错误:'下标'是不可用的:不能下标String与Int,请参阅文档注释讨论
当前回答
这是一个你可以使用的扩展,与Swift 3.1一起工作。单个索引将返回一个字符,这在索引字符串时似乎很直观,而范围将返回一个字符串。
extension String {
subscript (i: Int) -> Character {
return Array(self.characters)[i]
}
subscript (r: CountableClosedRange<Int>) -> String {
return String(Array(self.characters)[r])
}
subscript (r: CountableRange<Int>) -> String {
return self[r.lowerBound...r.upperBound-1]
}
}
扩展的一些例子:
let string = "Hello"
let c1 = string[1] // Character "e"
let c2 = string[-1] // fatal error: Index out of range
let r1 = string[1..<4] // String "ell"
let r2 = string[1...4] // String "ello"
let r3 = string[1...5] // fatal error: Array index is out of range
如果需要的话,你可以在上面的扩展中添加一个额外的方法来返回一个包含单个字符的String:
subscript (i: Int) -> String {
return String(self[i])
}
注意,在索引字符串时,你必须显式地指定你想要的类型:
let c: Character = string[3] // Character "l"
let s: String = string[0] // String "H"
其他回答
Swift3
可以使用下标语法访问特定String索引处的Character。
let greeting = "Guten Tag!"
let index = greeting.index(greeting.startIndex, offsetBy: 7)
greeting[index] // a
访问https://developer.apple.com/library/content/documentation/Swift/Conceptual/Swift_Programming_Language/StringsAndCharacters.html
或者我们可以在Swift 4中做一个字符串扩展
extension String {
func getCharAtIndex(_ index: Int) -> Character {
return self[self.index(self.startIndex, offsetBy: index)]
}
}
用法:
let foo = "ABC123"
foo.getCharAtIndex(2) //C
Swift 2.0的Xcode 7通用种子
var text = "Hello, world!"
let firstChar = text[text.startIndex.advancedBy(0)] // "H"
对于第n个字符,将0替换为n-1。
编辑:Swift 3.0
text[text.index(text.startIndex, offsetBy: 0)]
注意,有更简单的方法来获取字符串中的某些字符
例如:let firstChar = text.characters.first
允许负指数
它总是有用的,不必总是写string[string]。长度- 1]用于在使用下标扩展名时获取最后一个字符。这(Swift 3)扩展允许负索引,范围和CountableClosedRange。
extension String {
var count: Int { return self.characters.count }
subscript (i: Int) -> Character {
// wraps out of bounds indices
let j = i % self.count
// wraps negative indices
let x = j < 0 ? j + self.count : j
// quick exit for first
guard x != 0 else {
return self.characters.first!
}
// quick exit for last
guard x != count - 1 else {
return self.characters.last!
}
return self[self.index(self.startIndex, offsetBy: x)]
}
subscript (r: Range<Int>) -> String {
let lb = r.lowerBound
let ub = r.upperBound
// quick exit for one character
guard lb != ub else { return String(self[lb]) }
return self[self.index(self.startIndex, offsetBy: lb)..<self.index(self.startIndex, offsetBy: ub)]
}
subscript (r: CountableClosedRange<Int>) -> String {
return self[r.lowerBound..<r.upperBound + 1]
}
}
如何使用:
var text = "Hello World"
text[-1] // d
text[2] // l
text[12] // e
text[0...4] // Hello
text[0..<4] // Hell
对于更彻底的程序员:在这个扩展中包括一个防止空字符串的保护
subscript (i: Int) -> Character {
guard self.count != 0 else { return '' }
...
}
subscript (r: Range<Int>) -> String {
guard self.count != 0 else { return "" }
...
}
斯威夫特3:
extension String {
func substring(fromPosition: UInt, toPosition: UInt) -> String? {
guard fromPosition <= toPosition else {
return nil
}
guard toPosition < UInt(characters.count) else {
return nil
}
let start = index(startIndex, offsetBy: String.IndexDistance(fromPosition))
let end = index(startIndex, offsetBy: String.IndexDistance(toPosition) + 1)
let range = start..<end
return substring(with: range)
}
}
"ffaabbcc".substring(fromPosition: 2, toPosition: 5) // return "aabb"
在Swift 3中,没有对String类的扩展,就像我能做的那样简单!
let myString = "abcedfg"
let characterLocationIndex = myString.index(myString.startIndex, offsetBy: 3)
let myCharacter = myString[characterLocationIndex]
本例中的myCharacter为“3”。