我如何在c#中生成一个随机的8个字符的字母数字字符串?
当前回答
var chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
var stringChars = new char[8];
var random = new Random();
for (int i = 0; i < stringChars.Length; i++)
{
stringChars[i] = chars[random.Next(chars.Length)];
}
var finalString = new String(stringChars);
不如Linq解决方案优雅。
(注意:Random类的使用使得它不适用于任何与安全性相关的事情,比如创建密码或令牌。如果你需要强随机数生成器,请使用RNGCryptoServiceProvider类。)
其他回答
I was looking for a more specific answer, where I want to control the format of the random string and came across this post. For example: license plates (of cars) have a specific format (per country) and I wanted to created random license plates. I decided to write my own extension method of Random for this. (this is in order to reuse the same Random object, as you could have doubles in multi-threading scenarios). I created a gist (https://gist.github.com/SamVanhoutte/808845ca78b9c041e928), but will also copy the extension class here:
void Main()
{
Random rnd = new Random();
rnd.GetString("1-###-000").Dump();
}
public static class RandomExtensions
{
public static string GetString(this Random random, string format)
{
// Based on http://stackoverflow.com/questions/1344221/how-can-i-generate-random-alphanumeric-strings-in-c
// Added logic to specify the format of the random string (# will be random string, 0 will be random numeric, other characters remain)
StringBuilder result = new StringBuilder();
for(int formatIndex = 0; formatIndex < format.Length ; formatIndex++)
{
switch(format.ToUpper()[formatIndex])
{
case '0': result.Append(getRandomNumeric(random)); break;
case '#': result.Append(getRandomCharacter(random)); break;
default : result.Append(format[formatIndex]); break;
}
}
return result.ToString();
}
private static char getRandomCharacter(Random random)
{
string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
return chars[random.Next(chars.Length)];
}
private static char getRandomNumeric(Random random)
{
string nums = "0123456789";
return nums[random.Next(nums.Length)];
}
}
更新。net 6。RNGCryptoServiceProvider被标记为obsolete。相反,调用RandomNumberGenerator.Create()。答案中的代码已相应更新。
根据评论更新。原始实现生成a-h的时间为1.95%,其余字符的时间为1.56%。更新生成所有字符~1.61%的时间。 FRAMEWORK支持- . net Core 3(以及未来支持. net Standard 2.1或以上版本的平台)提供了一个加密的方法RandomNumberGenerator.GetInt32(),在期望的范围内生成一个随机整数。
与目前提出的一些替代方案不同,这个方案在密码学上是合理的。
using System;
using System.Security.Cryptography;
using System.Text;
namespace UniqueKey
{
public class KeyGenerator
{
internal static readonly char[] chars =
"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890".ToCharArray();
public static string GetUniqueKey(int size)
{
byte[] data = new byte[4*size];
using (var crypto = RandomNumberGenerator.Create())
{
crypto.GetBytes(data);
}
StringBuilder result = new StringBuilder(size);
for (int i = 0; i < size; i++)
{
var rnd = BitConverter.ToUInt32(data, i * 4);
var idx = rnd % chars.Length;
result.Append(chars[idx]);
}
return result.ToString();
}
public static string GetUniqueKeyOriginal_BIASED(int size)
{
char[] chars =
"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890".ToCharArray();
byte[] data = new byte[size];
using (RNGCryptoServiceProvider crypto = new RNGCryptoServiceProvider())
{
crypto.GetBytes(data);
}
StringBuilder result = new StringBuilder(size);
foreach (byte b in data)
{
result.Append(chars[b % (chars.Length)]);
}
return result.ToString();
}
}
}
基于这里对替代方案的讨论,并根据下面的评论进行了更新/修改。
下面是一个小型测试工具,演示了旧输出和更新输出中的字符分布。关于随机性分析的深入讨论,请访问random.org。
using System;
using System.Collections.Generic;
using System.Linq;
using UniqueKey;
namespace CryptoRNGDemo
{
class Program
{
const int REPETITIONS = 1000000;
const int KEY_SIZE = 32;
static void Main(string[] args)
{
Console.WriteLine("Original BIASED implementation");
PerformTest(REPETITIONS, KEY_SIZE, KeyGenerator.GetUniqueKeyOriginal_BIASED);
Console.WriteLine("Updated implementation");
PerformTest(REPETITIONS, KEY_SIZE, KeyGenerator.GetUniqueKey);
Console.ReadKey();
}
static void PerformTest(int repetitions, int keySize, Func<int, string> generator)
{
Dictionary<char, int> counts = new Dictionary<char, int>();
foreach (var ch in UniqueKey.KeyGenerator.chars) counts.Add(ch, 0);
for (int i = 0; i < REPETITIONS; i++)
{
var key = generator(KEY_SIZE);
foreach (var ch in key) counts[ch]++;
}
int totalChars = counts.Values.Sum();
foreach (var ch in UniqueKey.KeyGenerator.chars)
{
Console.WriteLine($"{ch}: {(100.0 * counts[ch] / totalChars).ToString("#.000")}%");
}
}
}
}
更新7/25/2022
根据评论中的一个问题,我很好奇这种分布是否真的是随机的。
我不是统计学家,但我可以在电视上扮演一个。如果一位真正的统计学家愿意插话,那将是最受欢迎的。
有62个可能的输出值(A-Za-Z0-9)和int。用于选择数组索引的最大值。int。MaxValue % 62是1,所以一个字符被选中的概率是其他字符的十亿分之一。我们可以通过在索引之前随机旋转输出值数组来进一步减少选择偏差。
t检验或其他统计度量将是确定输出结果中是否存在偏差的最佳方法,但这不是我在午休时间可以完成的工作,因此我留给您对上述代码的修改,以度量与预期的偏差。注意,它趋于零。
using System.Security.Cryptography;
using System.Text;
const int REPETITIONS = 1_000_000;
const int KEY_SIZE = 32;
int TASK_COUNT = Environment.ProcessorCount - 1;
var expectedPercentage = 100.0 / KeyGenerator.chars.Length;
var done = false;
var iterationNr = 1;
var totalRandomSymbols = 0L;
var grandTotalCounts = new Dictionary<char, long>();
foreach (var ch in KeyGenerator.chars) grandTotalCounts.Add(ch, 0);
while (!done)
{
var experiments = Enumerable.Range(0, TASK_COUNT).Select(i => Task.Run(Experiment)).ToArray();
Task.WaitAll(experiments);
var totalCountsThisRun = experiments.SelectMany(e => e.Result)
.GroupBy(e => e.Key)
.Select(e => new { e.Key, Count = e.Select(_ => _.Value).Sum() })
.ToDictionary(e => e.Key, e => e.Count);
foreach (var ch in KeyGenerator.chars)
grandTotalCounts[ch] += totalCountsThisRun[ch];
var totalChars = grandTotalCounts.Values.Sum();
totalRandomSymbols += totalChars;
var distributionScores = KeyGenerator.chars.Select(ch =>
new
{
Symbol = ch,
OverUnder = (100.0 * grandTotalCounts[ch] / totalChars) - expectedPercentage
});
Console.WriteLine($"Iteration {iterationNr++}. Total random symbols: {totalRandomSymbols:N0}");
foreach (var chWithValue in distributionScores.OrderByDescending(c => c.OverUnder))
{
Console.WriteLine($"{chWithValue.Symbol}: {chWithValue.OverUnder:#.00000}%");
}
done = Console.KeyAvailable;
}
Dictionary<char, long> Experiment()
{
var counts = new Dictionary<char, long>();
foreach (var ch in KeyGenerator.chars) counts.Add(ch, 0);
for (int i = 0; i < REPETITIONS; i++)
{
var key = KeyGenerator.GetUniqueKey(KEY_SIZE);
foreach (var ch in key) counts[ch]++;
}
return counts;
}
public class KeyGenerator
{
internal static readonly char[] chars =
"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890".ToCharArray();
public static string GetUniqueKey(int size)
{
byte[] data = new byte[4 * size];
using (var crypto = RandomNumberGenerator.Create())
{
crypto.GetBytes(data);
}
StringBuilder result = new StringBuilder(size);
for (int i = 0; i < size; i++)
{
var rnd = BitConverter.ToUInt32(data, i * 4);
var idx = rnd % chars.Length;
result.Append(chars[idx]);
}
return result.ToString();
}
}
一个包含所有字母字符和数字的解决方案,你可以随心所欲地更改:
public static string RandomString(int length)
{
Random rand = new Random();
string charbase = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
return new string(Enumerable.Range(0,length)
.Select(_ => charbase[rand.Next(charbase.Length)])
.ToArray());
}
如果你喜欢单行方法;)
public static Random rand = new Random();
public const string charbase = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
public static string RandomString(int length) =>
new string(Enumerable.Range(0,length).Select(_ => charbase[rand.Next(charbase.Length)]).ToArray());
一种简单且高度安全的方法可能是生成加密Aes密钥。
public static string GenerateRandomString()
{
using Aes crypto = Aes.Create();
crypto.GenerateKey();
return Convert.ToBase64String(crypto.Key);
}
var chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
var stringChars = new char[8];
var random = new Random();
for (int i = 0; i < stringChars.Length; i++)
{
stringChars[i] = chars[random.Next(chars.Length)];
}
var finalString = new String(stringChars);
不如Linq解决方案优雅。
(注意:Random类的使用使得它不适用于任何与安全性相关的事情,比如创建密码或令牌。如果你需要强随机数生成器,请使用RNGCryptoServiceProvider类。)
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