我如何在c#中生成一个随机的8个字符的字母数字字符串?
当前回答
对于加密和非加密,有效地:
public static string GenerateRandomString(int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") =>
new Random().GenerateRandomString(length, charset);
public static string GenerateRandomString(this Random random, int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") =>
RandomString(random.NextBytes, length, charset.ToCharArray());
public static string GenerateRandomCryptoString(int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890")
{
using (var crypto = new System.Security.Cryptography.RNGCryptoServiceProvider())
return crypto.GenerateRandomCryptoString(length, charset);
}
public static string GenerateRandomCryptoString(this RNGCryptoServiceProvider random, int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") =>
RandomString(random.GetBytes, length, charset.ToCharArray());
private static string RandomString(Action<byte[]> fillRandomBuffer, int length, char[] charset)
{
if (length < 0)
throw new ArgumentOutOfRangeException(nameof(length), $"{nameof(length)} must be greater or equal to 0");
if (charset is null)
throw new ArgumentNullException(nameof(charset));
if (charset.Length == 0)
throw new ArgumentException($"{nameof(charset)} must contain at least 1 character", nameof(charset));
var maxIdx = charset.Length;
var chars = new char[length];
var randomBuffer = new byte[length * 4];
fillRandomBuffer(randomBuffer);
for (var i = 0; i < length; i++)
chars[i] = charset[BitConverter.ToUInt32(randomBuffer, i * 4) % maxIdx];
return new string(chars);
}
使用生成器和LINQ。不是最快的选项(特别是因为它不会一次生成所有字节),但相当整洁和可扩展:
private static readonly Random _random = new Random();
public static string GenerateRandomString(int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") =>
new string(_random.GetGenerator().RandomChars(charset.ToCharArray()).Take(length).ToArray());
public static string GenerateRandomCryptoString(int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890")
{
using (var crypto = new System.Security.Cryptography.RNGCryptoServiceProvider())
return new string(crypto.GetGenerator().RandomChars(charset.ToCharArray()).Take(length).ToArray());
}
public static IEnumerable<char> RandomChars(this Func<uint, IEnumerable<uint>> randomGenerator, char[] charset)
{
if (charset is null)
throw new ArgumentNullException(nameof(charset));
if (charset.Length == 0)
throw new ArgumentException($"{nameof(charset)} must contain at least 1 character", nameof(charset));
return randomGenerator((uint)charset.Length).Select(r => charset[r]);
}
public static Func<uint, IEnumerable<uint>> GetGenerator(this Random random)
{
if (random is null)
throw new ArgumentNullException(nameof(random));
return GeneratorFunc_Inner;
IEnumerable<uint> GeneratorFunc_Inner(uint maxValue)
{
if (maxValue > int.MaxValue)
throw new ArgumentOutOfRangeException(nameof(maxValue));
return Generator_Inner();
IEnumerable<uint> Generator_Inner()
{
var randomBytes = new byte[4];
while (true)
{
random.NextBytes(randomBytes);
yield return BitConverter.ToUInt32(randomBytes, 0) % maxValue;
}
}
}
}
public static Func<uint, IEnumerable<uint>> GetGenerator(this System.Security.Cryptography.RNGCryptoServiceProvider random)
{
if (random is null)
throw new ArgumentNullException(nameof(random));
return Generator_Inner;
IEnumerable<uint> Generator_Inner(uint maxValue)
{
var randomBytes = new byte[4];
while (true)
{
random.GetBytes(randomBytes);
yield return BitConverter.ToUInt32(randomBytes, 0) % maxValue;
}
}
}
一个更简单的版本,使用LINQ只用于非加密字符串:
private static readonly Random _random = new Random();
public static string RandomString(int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") =>
new string(_random.GenerateChars(charset).Take(length).ToArray());
public static IEnumerable<char> GenerateChars(this Random random, string charset)
{
if (charset is null) throw new ArgumentNullException(nameof(charset));
if (charset.Length == 0) throw new ArgumentException($"{nameof(charset)} must contain at least 1 character", nameof(charset));
return random.Generator(charset.Length).Select(r => charset[r]);
}
public static IEnumerable<int> Generator(this Random random, int maxValue)
{
if (random is null) throw new ArgumentNullException(nameof(random));
return Generator_Inner();
IEnumerable<int> Generator_Inner() { while (true) yield return random.Next(maxValue); }
}
其他回答
很可怕,我知道,但我就是忍不住:
namespace ConsoleApplication2
{
using System;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
Random adomRng = new Random();
string rndString = string.Empty;
char c;
for (int i = 0; i < 8; i++)
{
while (!Regex.IsMatch((c=Convert.ToChar(adomRng.Next(48,128))).ToString(), "[A-Za-z0-9]"));
rndString += c;
}
Console.WriteLine(rndString + Environment.NewLine);
}
}
}
下面是Eric J的解决方案的一个变体,即加密声音,用于WinRT (Windows商店应用程序):
public static string GenerateRandomString(int length)
{
var chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
var result = new StringBuilder(length);
for (int i = 0; i < length; ++i)
{
result.Append(CryptographicBuffer.GenerateRandomNumber() % chars.Length);
}
return result.ToString();
}
如果性能很重要(特别是当长度很高时):
public static string GenerateRandomString(int length)
{
var chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
var result = new System.Text.StringBuilder(length);
var bytes = CryptographicBuffer.GenerateRandom((uint)length * 4).ToArray();
for (int i = 0; i < bytes.Length; i += 4)
{
result.Append(BitConverter.ToUInt32(bytes, i) % chars.Length);
}
return result.ToString();
}
最简单和最灵活的加密安全解决方案(。NET Core 3.0+):
如果你使用的是。net Core 3.0或更高版本,你可以在RandomNumberGenerator类上使用新的静态GetInt32方法(这是加密安全的)来为给定的字符集生成随机索引,并以这种方式很容易地填充结果。
这种方法比这个答案中提出的方法要简单得多;它还提供了完全的灵活性,因为你可以传入任何你想要的字符集。
public static string GenerateRandomString(int length, IEnumerable<char> charSet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789")
{
var charArray = charSet.Distinct().ToArray();
char[] result = new char[length];
for (int i = 0; i < length; i++)
result[i] = charArray[RandomNumberGenerator.GetInt32(charArray.Length)];
return new string(result);
}
用法:
string randomAlphanumericString = GenerateRandomString(length: 10);
现在是单行风格。
private string RandomName()
{
return new string(
Enumerable.Repeat("ABCDEFGHIJKLMNOPQRSTUVWXYZ", 13)
.Select(s =>
{
var cryptoResult = new byte[4];
using (var cryptoProvider = new RNGCryptoServiceProvider())
cryptoProvider.GetBytes(cryptoResult);
return s[new Random(BitConverter.ToInt32(cryptoResult, 0)).Next(s.Length)];
})
.ToArray());
}
问:为什么我要浪费时间使用Enumerable ?范围,而不是输入“ABCDEFGHJKLMNOPQRSTUVWXYZ0123456789”?
using System;
using System.Collections.Generic;
using System.Linq;
public class Test
{
public static void Main()
{
var randomCharacters = GetRandomCharacters(8, true);
Console.WriteLine(new string(randomCharacters.ToArray()));
}
private static List<char> getAvailableRandomCharacters(bool includeLowerCase)
{
var integers = Enumerable.Empty<int>();
integers = integers.Concat(Enumerable.Range('A', 26));
integers = integers.Concat(Enumerable.Range('0', 10));
if ( includeLowerCase )
integers = integers.Concat(Enumerable.Range('a', 26));
return integers.Select(i => (char)i).ToList();
}
public static IEnumerable<char> GetRandomCharacters(int count, bool includeLowerCase)
{
var characters = getAvailableRandomCharacters(includeLowerCase);
var random = new Random();
var result = Enumerable.Range(0, count)
.Select(_ => characters[random.Next(characters.Count)]);
return result;
}
}
答案:魔术弦不好。有没有人注意到在我的字符串顶部没有“I”?我妈妈教我不要用魔法弦就是因为这个原因……
注意事项1:正如许多像@dtb这样的人所说,不要使用系统。随机的,如果你需要密码安全…
注2:这个答案不是最有效或最短的,但我想用空间把答案和问题分开。我回答这个问题的目的,更多的是为了警告人们不要使用神奇的字符串,而不是提供一个花哨的创新答案。
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