我如何在c#中生成一个随机的8个字符的字母数字字符串?


当前回答

对于加密和非加密,有效地:

public static string GenerateRandomString(int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") =>
    new Random().GenerateRandomString(length, charset);

public static string GenerateRandomString(this Random random, int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") =>
    RandomString(random.NextBytes, length, charset.ToCharArray());

public static string GenerateRandomCryptoString(int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890")
{
    using (var crypto = new System.Security.Cryptography.RNGCryptoServiceProvider())
        return crypto.GenerateRandomCryptoString(length, charset);
}

public static string GenerateRandomCryptoString(this RNGCryptoServiceProvider random, int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") => 
    RandomString(random.GetBytes, length, charset.ToCharArray());

private static string RandomString(Action<byte[]> fillRandomBuffer, int length, char[] charset)
{
    if (length < 0)
        throw new ArgumentOutOfRangeException(nameof(length), $"{nameof(length)} must be greater or equal to 0");
    if (charset is null)
        throw new ArgumentNullException(nameof(charset));
    if (charset.Length == 0)
        throw new ArgumentException($"{nameof(charset)} must contain at least 1 character", nameof(charset));

    var maxIdx = charset.Length;
    var chars = new char[length];
    var randomBuffer = new byte[length * 4];
    fillRandomBuffer(randomBuffer);

    for (var i = 0; i < length; i++)
        chars[i] = charset[BitConverter.ToUInt32(randomBuffer, i * 4) % maxIdx];

    return new string(chars);
}

使用生成器和LINQ。不是最快的选项(特别是因为它不会一次生成所有字节),但相当整洁和可扩展:

private static readonly Random _random = new Random();

public static string GenerateRandomString(int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") =>
    new string(_random.GetGenerator().RandomChars(charset.ToCharArray()).Take(length).ToArray());

public static string GenerateRandomCryptoString(int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890")
{
    using (var crypto = new System.Security.Cryptography.RNGCryptoServiceProvider())
        return new string(crypto.GetGenerator().RandomChars(charset.ToCharArray()).Take(length).ToArray());
}

public static IEnumerable<char> RandomChars(this Func<uint, IEnumerable<uint>> randomGenerator, char[] charset)
{
    if (charset is null)
        throw new ArgumentNullException(nameof(charset));
    if (charset.Length == 0)
        throw new ArgumentException($"{nameof(charset)} must contain at least 1 character", nameof(charset));

    return randomGenerator((uint)charset.Length).Select(r => charset[r]);
}

public static Func<uint, IEnumerable<uint>> GetGenerator(this Random random)
{
    if (random is null)
        throw new ArgumentNullException(nameof(random));

    return GeneratorFunc_Inner;

    IEnumerable<uint> GeneratorFunc_Inner(uint maxValue)
    {
        if (maxValue > int.MaxValue)
            throw new ArgumentOutOfRangeException(nameof(maxValue));

        return Generator_Inner();

        IEnumerable<uint> Generator_Inner()
        {
            var randomBytes = new byte[4];
            while (true)
            {
                random.NextBytes(randomBytes);
                yield return BitConverter.ToUInt32(randomBytes, 0) % maxValue;
            }
        }
    }
}

public static Func<uint, IEnumerable<uint>> GetGenerator(this System.Security.Cryptography.RNGCryptoServiceProvider random)
{
    if (random is null)
        throw new ArgumentNullException(nameof(random));

    return Generator_Inner;

    IEnumerable<uint> Generator_Inner(uint maxValue)
    {
        var randomBytes = new byte[4];
        while (true)
        {
            random.GetBytes(randomBytes);
            yield return BitConverter.ToUInt32(randomBytes, 0) % maxValue;
        }
    }
}

一个更简单的版本,使用LINQ只用于非加密字符串:

private static readonly Random _random = new Random();

public static string RandomString(int length, string charset = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890") =>
    new string(_random.GenerateChars(charset).Take(length).ToArray()); 

public static IEnumerable<char> GenerateChars(this Random random, string charset)
{
    if (charset is null) throw new ArgumentNullException(nameof(charset));
    if (charset.Length == 0) throw new ArgumentException($"{nameof(charset)} must contain at least 1 character", nameof(charset));

    return random.Generator(charset.Length).Select(r => charset[r]);
}

public static IEnumerable<int> Generator(this Random random, int maxValue)
{
    if (random is null) throw new ArgumentNullException(nameof(random));

    return Generator_Inner();

    IEnumerable<int> Generator_Inner() { while (true) yield return random.Next(maxValue); }
}

其他回答

很可怕,我知道,但我就是忍不住:


namespace ConsoleApplication2
{
    using System;
    using System.Text.RegularExpressions;

    class Program
    {
        static void Main(string[] args)
        {
            Random adomRng = new Random();
            string rndString = string.Empty;
            char c;

            for (int i = 0; i < 8; i++)
            {
                while (!Regex.IsMatch((c=Convert.ToChar(adomRng.Next(48,128))).ToString(), "[A-Za-z0-9]"));
                rndString += c;
            }

            Console.WriteLine(rndString + Environment.NewLine);
        }
    }
}

下面是Eric J的解决方案的一个变体,即加密声音,用于WinRT (Windows商店应用程序):

public static string GenerateRandomString(int length)
{
    var chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
    var result = new StringBuilder(length);
    for (int i = 0; i < length; ++i)
    {
        result.Append(CryptographicBuffer.GenerateRandomNumber() % chars.Length);
    }
    return result.ToString();
}

如果性能很重要(特别是当长度很高时):

public static string GenerateRandomString(int length)
{
    var chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
    var result = new System.Text.StringBuilder(length);
    var bytes = CryptographicBuffer.GenerateRandom((uint)length * 4).ToArray();
    for (int i = 0; i < bytes.Length; i += 4)
    {
        result.Append(BitConverter.ToUInt32(bytes, i) % chars.Length);
    }
    return result.ToString();
}

最简单和最灵活的加密安全解决方案(。NET Core 3.0+):

如果你使用的是。net Core 3.0或更高版本,你可以在RandomNumberGenerator类上使用新的静态GetInt32方法(这是加密安全的)来为给定的字符集生成随机索引,并以这种方式很容易地填充结果。

这种方法比这个答案中提出的方法要简单得多;它还提供了完全的灵活性,因为你可以传入任何你想要的字符集。

public static string GenerateRandomString(int length, IEnumerable<char> charSet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789")
{
    var charArray = charSet.Distinct().ToArray();
    char[] result = new char[length];
    for (int i = 0; i < length; i++)
        result[i] = charArray[RandomNumberGenerator.GetInt32(charArray.Length)];
    return new string(result);
}

用法:

string randomAlphanumericString = GenerateRandomString(length: 10);

现在是单行风格。

private string RandomName()
{
        return new string(
            Enumerable.Repeat("ABCDEFGHIJKLMNOPQRSTUVWXYZ", 13)
                .Select(s =>
                {
                    var cryptoResult = new byte[4];
                    using (var cryptoProvider = new RNGCryptoServiceProvider())
                        cryptoProvider.GetBytes(cryptoResult);

                    return s[new Random(BitConverter.ToInt32(cryptoResult, 0)).Next(s.Length)];
                })
                .ToArray());
}

问:为什么我要浪费时间使用Enumerable ?范围,而不是输入“ABCDEFGHJKLMNOPQRSTUVWXYZ0123456789”?

using System;
using System.Collections.Generic;
using System.Linq;

public class Test
{
    public static void Main()
    {
        var randomCharacters = GetRandomCharacters(8, true);
        Console.WriteLine(new string(randomCharacters.ToArray()));
    }

    private static List<char> getAvailableRandomCharacters(bool includeLowerCase)
    {
        var integers = Enumerable.Empty<int>();
        integers = integers.Concat(Enumerable.Range('A', 26));
        integers = integers.Concat(Enumerable.Range('0', 10));

        if ( includeLowerCase )
            integers = integers.Concat(Enumerable.Range('a', 26));

        return integers.Select(i => (char)i).ToList();
    }

    public static IEnumerable<char> GetRandomCharacters(int count, bool includeLowerCase)
    {
        var characters = getAvailableRandomCharacters(includeLowerCase);
        var random = new Random();
        var result = Enumerable.Range(0, count)
            .Select(_ => characters[random.Next(characters.Count)]);

        return result;
    }
}

答案:魔术弦不好。有没有人注意到在我的字符串顶部没有“I”?我妈妈教我不要用魔法弦就是因为这个原因……

注意事项1:正如许多像@dtb这样的人所说,不要使用系统。随机的,如果你需要密码安全…

注2:这个答案不是最有效或最短的,但我想用空间把答案和问题分开。我回答这个问题的目的,更多的是为了警告人们不要使用神奇的字符串,而不是提供一个花哨的创新答案。